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MIP1501 ASSIGNMENT 03 DETAILED ANSWERS DUE: 22 JULY 2024 UNIQUE NO: (792287 )

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MIP1501 ASSIGNMENT 03 DETAILED ANSWERS DUE: 22 JULY 2024 UNIQUE NO: (792287 )











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Uploaded on
June 15, 2024
Number of pages
15
Written in
2023/2024
Type
Exam (elaborations)
Contains
Questions & answers

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,QUESTION 1

1.1. Solve and explain each step to grade 6 mathematics learners the
following multiplication and division calculations involving fractions.



ANSWER:
𝟖 𝟔
1.1.1 𝟔 ÷
𝟒 𝟏𝟐



𝟖
Step 1: Firstly, let’s solve or simplify 6
𝟒
 First we multiply denominator(4) by whole number(6) which is
24
 Then 24 will be added to numerator(8): 24 + 8 = 32
𝟑𝟐
 Then will be =8
𝟒
𝟔
Step 2: Simplify:
𝟏𝟐
𝟔
 Can be simplified by dividing the numerator and the
𝟏𝟐
denominator by their greatest common divisor (GCD), which is
6.
𝟔÷𝟔 𝟏
 =
𝟏𝟐÷𝟔 𝟐



Step 3: Rewrite the division as multiplication by the reciprocal.
𝟏
 Dividing by is the same as multiplying by its reciprocal, which
𝟐
is 2.
𝟏
 So, 8 ÷ = 8 * 2
𝟐

, Step 4: Multiply.

 8×2=16
𝟑𝟐 𝟔
 So, ÷ = 16
𝟒 𝟏𝟐



𝟕 𝟒
1.1.2 x
𝟏𝟒 𝟏𝟖



𝟕
Step 1: Let’s simplify
𝟏𝟒
 This can be simplified by dividing the numerator and the
denominator by their GCD, which is 7
𝟕 ÷ 𝟕 𝟏
 =
𝟏𝟒 ÷ 𝟕 𝟐

𝟒
Step 2: simplify
𝟏𝟖

𝟒
 can be simplified by dividing the numerator and the
𝟏𝟖
denominator by their GCD, which is 2
𝟒 ÷ 𝟐 𝟐
 =
𝟏𝟖 ÷ 𝟐 𝟗

Step 3: Multiply the simplified fractions.

𝟏 𝟐 𝟏 𝐱 𝟐 𝟐
 𝐱 = =
𝟐 𝟗 𝟐 𝐱 𝟗 𝟏𝟖

So then the final answer is:
𝟕 𝟒 𝟏
 x =
𝟏𝟒 𝟏𝟒 𝟗

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