QMI1500 – ELEMENTARY
QUANTITATIVE METHODS
ASSIGNMENT 1 – SEMESTER
2, 2024
DELL
[COMPANY NAME] [Company address]
, ROYAL ACADEMY TUTORS
Empowering you to conquer your world
QMI1500 – Elementary Quantitative Methods
Assignment 1 – Semester 2, 2024
Question 1
Solving
(−49 ÷ 7 × 3(−8)) ÷ 4 + (6 × 3) − 21 ÷ 3 = 𝟓𝟑
gives
Question 2
The correct mathematical equation for
The monthly consumption, W, of a household is 237 liters with an additional monthly free water
usage of 1 200 liters. The water – household consumed for l months is given by
𝑀𝑜𝑛𝑡ℎ𝑙𝑦 𝑤𝑎𝑡𝑒𝑟 𝑢𝑠𝑎𝑔𝑒 = 237 + 1200
Question
Page 1 of 16
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Question 3
Below are the five statements and five fractions:
Information table
Statements Fractions
A. A reciprocal of 5 written as a mixed fraction. 1. 3
63 2
𝑏
Reciprocal of 𝑎 𝑖𝑠
𝑏 𝑎
63 3
Reciprocal of 5 = = 12 𝑎𝑠 𝑎 𝑚𝑖𝑥𝑒𝑑 𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 = 𝟒
63 5 5
3 2
B. A fraction with a denominator of 176 that is equivalent to 2.
11 3
48 3
= =𝟓
176 11
4 3
C. √16
3 written as a proper fraction. 3.
27 0
√ 4
√16 2
3 = =𝟐
√27 3
2 18 3
D. 5 ÷ written as an improper fraction 4. 12
5 5 5
2 18 3
5 ÷ = =𝟏
5 5 2
E. A cube root of 3.375 expressed as a common fraction in 5. 48
176
simplest form
3
3√3,375 = = 𝟏
2
𝐀∶𝟒 𝐁∶𝟓 𝐂∶𝟐 𝐃∶𝟏 𝐄∶𝟏
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QUANTITATIVE METHODS
ASSIGNMENT 1 – SEMESTER
2, 2024
DELL
[COMPANY NAME] [Company address]
, ROYAL ACADEMY TUTORS
Empowering you to conquer your world
QMI1500 – Elementary Quantitative Methods
Assignment 1 – Semester 2, 2024
Question 1
Solving
(−49 ÷ 7 × 3(−8)) ÷ 4 + (6 × 3) − 21 ÷ 3 = 𝟓𝟑
gives
Question 2
The correct mathematical equation for
The monthly consumption, W, of a household is 237 liters with an additional monthly free water
usage of 1 200 liters. The water – household consumed for l months is given by
𝑀𝑜𝑛𝑡ℎ𝑙𝑦 𝑤𝑎𝑡𝑒𝑟 𝑢𝑠𝑎𝑔𝑒 = 237 + 1200
Question
Page 1 of 16
, ROYAL ACADEMY TUTORS
Empowering you to conquer your world
Question 3
Below are the five statements and five fractions:
Information table
Statements Fractions
A. A reciprocal of 5 written as a mixed fraction. 1. 3
63 2
𝑏
Reciprocal of 𝑎 𝑖𝑠
𝑏 𝑎
63 3
Reciprocal of 5 = = 12 𝑎𝑠 𝑎 𝑚𝑖𝑥𝑒𝑑 𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 = 𝟒
63 5 5
3 2
B. A fraction with a denominator of 176 that is equivalent to 2.
11 3
48 3
= =𝟓
176 11
4 3
C. √16
3 written as a proper fraction. 3.
27 0
√ 4
√16 2
3 = =𝟐
√27 3
2 18 3
D. 5 ÷ written as an improper fraction 4. 12
5 5 5
2 18 3
5 ÷ = =𝟏
5 5 2
E. A cube root of 3.375 expressed as a common fraction in 5. 48
176
simplest form
3
3√3,375 = = 𝟏
2
𝐀∶𝟒 𝐁∶𝟓 𝐂∶𝟐 𝐃∶𝟏 𝐄∶𝟏
Page 2 of 16