QMI1500 EXAM
PACK ANSWERS
AND BRIEF NOTES
,2|Page
TABLE OF CONTENTS
PAPERS PAGE
Oct-Nov 2019 .......................................................................................................................................... 3
May-June 2019 ...................................................................................................................................... 15
,3|Page
QMI1500 OCT/NOV 2019
QUESTION 01
𝑎5 𝑏𝑐 3
𝑎2 𝑏3 𝑐 2
3 1 2
Since a = 2 , b = 2, c = 3
3 1 2
( )5 ( )( )3
= 3
2
1
2
2
3
=9
( ) 2 ( )3 ( )2
2 2 3
OPTION [1]
QUESTION 02
4−5𝑥 13 1−3𝑥
6
− 45
= 4
multiply everything by the highest denominator
4 − 5𝑥 13 1 − 3𝑥
45( ) − 45( ) = 45( )
6 45 4
1 1
72 (4 − 5𝑥) – 13 = 114(1 – 3x) get rid of the brackets
1 1 3
30 - 372 𝑥 – 13 = 114 - 334x collect like terms
1 3 1
30 – 13 - 114 = - 334x + 372 𝑥
3 3 3
54 = 34 𝑥 divide both sides by 34
8
115 = x
OPTION [4]
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QUESTION 3
Pule Lerato
Wind chimes(x) 4 2
Birdhouses(y) 3 4
More than 38 Less than 48
≤≥
4x + 3y ≥ 38
2x + 4y ≤ 48
OPTION [4]
QUESTION 4
COMBINATION
OPTION [1]
QUESTION 5
PERMUTATION
8 actors for 3 roles
Main role options x second role options x third role options
= 8 x 7 x 6 = 336
OR
n
Px = 8P3 = 336
OPTION [1]
PACK ANSWERS
AND BRIEF NOTES
,2|Page
TABLE OF CONTENTS
PAPERS PAGE
Oct-Nov 2019 .......................................................................................................................................... 3
May-June 2019 ...................................................................................................................................... 15
,3|Page
QMI1500 OCT/NOV 2019
QUESTION 01
𝑎5 𝑏𝑐 3
𝑎2 𝑏3 𝑐 2
3 1 2
Since a = 2 , b = 2, c = 3
3 1 2
( )5 ( )( )3
= 3
2
1
2
2
3
=9
( ) 2 ( )3 ( )2
2 2 3
OPTION [1]
QUESTION 02
4−5𝑥 13 1−3𝑥
6
− 45
= 4
multiply everything by the highest denominator
4 − 5𝑥 13 1 − 3𝑥
45( ) − 45( ) = 45( )
6 45 4
1 1
72 (4 − 5𝑥) – 13 = 114(1 – 3x) get rid of the brackets
1 1 3
30 - 372 𝑥 – 13 = 114 - 334x collect like terms
1 3 1
30 – 13 - 114 = - 334x + 372 𝑥
3 3 3
54 = 34 𝑥 divide both sides by 34
8
115 = x
OPTION [4]
, 4|Page
QUESTION 3
Pule Lerato
Wind chimes(x) 4 2
Birdhouses(y) 3 4
More than 38 Less than 48
≤≥
4x + 3y ≥ 38
2x + 4y ≤ 48
OPTION [4]
QUESTION 4
COMBINATION
OPTION [1]
QUESTION 5
PERMUTATION
8 actors for 3 roles
Main role options x second role options x third role options
= 8 x 7 x 6 = 336
OR
n
Px = 8P3 = 336
OPTION [1]