BNU1501
EXAM PACK
Contact us on:
Email
Phone +27 65 505 3119
Whatsapp +27 65 505 3119
Facebook CTM Tutoring Solutions
Skype ctm.tutoring
,SOLUTIONS FOR BNU 1501 EXAMINATION QUESTION PAPER
OCT/NOV 2016
1. 3(𝑦 + 2) = 4(2 − 𝑦)
3𝑦 + 6 = 8 − 4𝑦
3𝑦 + 4𝑦 = 8 − 6
7𝑦 = 2
2
𝑦= Option [3]
7
2. 2(𝑥 − 1) − 3(𝑥 + 1) = 12𝑥 + 21
2𝑥 − 2 − 3𝑥 − 3 = 12𝑥 + 21
12𝑥 + 3𝑥 − 2𝑥 = −21 − 3 − 2
13𝑥 = −26
𝑥 = −2 Option [2]
3. √16𝑥16 = 4𝑥8 Option [4]
4. 2𝑥2 − (𝑥 − 3) − 2𝑥(1 + 𝑥)
= 2𝑥2 − 𝑥 + 3 − 2𝑥 − 2𝑥2
= −3𝑥 + 3 Option [1]
, 7 3 14
5. X ÷
24 16 32
7 3 32
= X X
24 16 14
1
= Option [4]
8
3 5
6. 6 + −
11 2 3
12 33 5
= + −
22 22 3
45 5
= −
22 3
135 110
= −
66 66
25
= Option [2]
66
9 3
7. 5 − ÷
9 8 4
5 9 4
− X
9 8 3
5 3
−
9 2
10 27
−
18 18
17
− Option [3]
18
, 8. 9𝑥𝑦 = 3 X 3 X 𝑥 X 𝑦
8𝑥2 = 2 X 2 X 2 X 𝑥 X 𝑥 X
6𝑥𝑦3 = 2 X 3 X 𝑥 X 𝑦 X 𝑦 X 𝑦
𝐿𝐶𝑀 = 2 X 2 X 2 X 3 X 3 X 𝑥 X 𝑥 X 𝑦 X 𝑦 X 𝑦
𝐿𝐶𝑀 = 72𝑥2𝑦3 Option [2]
9. 5𝑥 − 3 Option [3]
10. (𝑎𝑏2)(𝑎2𝑏)3 = (𝑎𝑏2)(𝑎6𝑏3)
= 𝑎7𝑏5 Option [3]
11. 𝐶i𝑟𝑐𝑢𝑚f𝑒𝑟𝑒𝑛𝑐𝑒 𝑜f 𝑡ℎ𝑒 j𝑎𝑐𝑢𝑧𝑧i = 𝜋𝑑
=𝜋X3
= 9,4 𝑚 Option [1]
1
12. 𝑃𝑎𝑣𝑒𝑑 𝑎𝑟𝑒𝑎 = [( 12 X 8)] − [( X 3 X 3 X 4) + (𝜋 X 1,52)]
2
96 − 18 − 2,25𝜋
= 78 − (2,25𝜋)
= 70,9 𝑚2 Option [4]
EXAM PACK
Contact us on:
Phone +27 65 505 3119
Whatsapp +27 65 505 3119
Facebook CTM Tutoring Solutions
Skype ctm.tutoring
,SOLUTIONS FOR BNU 1501 EXAMINATION QUESTION PAPER
OCT/NOV 2016
1. 3(𝑦 + 2) = 4(2 − 𝑦)
3𝑦 + 6 = 8 − 4𝑦
3𝑦 + 4𝑦 = 8 − 6
7𝑦 = 2
2
𝑦= Option [3]
7
2. 2(𝑥 − 1) − 3(𝑥 + 1) = 12𝑥 + 21
2𝑥 − 2 − 3𝑥 − 3 = 12𝑥 + 21
12𝑥 + 3𝑥 − 2𝑥 = −21 − 3 − 2
13𝑥 = −26
𝑥 = −2 Option [2]
3. √16𝑥16 = 4𝑥8 Option [4]
4. 2𝑥2 − (𝑥 − 3) − 2𝑥(1 + 𝑥)
= 2𝑥2 − 𝑥 + 3 − 2𝑥 − 2𝑥2
= −3𝑥 + 3 Option [1]
, 7 3 14
5. X ÷
24 16 32
7 3 32
= X X
24 16 14
1
= Option [4]
8
3 5
6. 6 + −
11 2 3
12 33 5
= + −
22 22 3
45 5
= −
22 3
135 110
= −
66 66
25
= Option [2]
66
9 3
7. 5 − ÷
9 8 4
5 9 4
− X
9 8 3
5 3
−
9 2
10 27
−
18 18
17
− Option [3]
18
, 8. 9𝑥𝑦 = 3 X 3 X 𝑥 X 𝑦
8𝑥2 = 2 X 2 X 2 X 𝑥 X 𝑥 X
6𝑥𝑦3 = 2 X 3 X 𝑥 X 𝑦 X 𝑦 X 𝑦
𝐿𝐶𝑀 = 2 X 2 X 2 X 3 X 3 X 𝑥 X 𝑥 X 𝑦 X 𝑦 X 𝑦
𝐿𝐶𝑀 = 72𝑥2𝑦3 Option [2]
9. 5𝑥 − 3 Option [3]
10. (𝑎𝑏2)(𝑎2𝑏)3 = (𝑎𝑏2)(𝑎6𝑏3)
= 𝑎7𝑏5 Option [3]
11. 𝐶i𝑟𝑐𝑢𝑚f𝑒𝑟𝑒𝑛𝑐𝑒 𝑜f 𝑡ℎ𝑒 j𝑎𝑐𝑢𝑧𝑧i = 𝜋𝑑
=𝜋X3
= 9,4 𝑚 Option [1]
1
12. 𝑃𝑎𝑣𝑒𝑑 𝑎𝑟𝑒𝑎 = [( 12 X 8)] − [( X 3 X 3 X 4) + (𝜋 X 1,52)]
2
96 − 18 − 2,25𝜋
= 78 − (2,25𝜋)
= 70,9 𝑚2 Option [4]