NR 507 Final Exam Advanced Pathophysiology
Practice Questions with Verified Answers
This professional study resource is a premium test bank tailored for graduate nursing
students preparing for the Chamberlain University NR 507 Advanced
Pathophysiology Final Examination. It features highly targeted practice questions,
100% verified answers, and comprehensive rationales mapping cellular adaptations,
renal conditions, gastrointestinal changes, and complex neurological syndromes.
Preparing with these premium test-prep materials will sharpen your diagnostic
reasoning, streamline your study sessions, and ensure you earn an A grade on your
proctored assessment.
SECTION 1: CELLULAR ADAPTATION, INJURY & DEATH
(Questions 1–25)
1. A 68-year-old male with chronic GERD undergoes endoscopy revealing
intestinal-type columnar epithelium replacing the normal squamous epithelium in
the distal esophagus. This cellular adaptation is BEST described as:
• A. Hyperplasia
• B. Metaplasia
• C. Dysplasia
• D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one adult cell type with another,
often an adaptive substitution of cells sensitive to stress with cells better able to withstand
,the adverse environment. In Barrett esophagus, chronic acid exposure causes squamous
epithelium to be replaced by intestinal-type columnar epithelium. Hyperplasia (A) is
increased cell number; dysplasia (C) is disordered growth; anaplasia (D) is lack of
differentiation (malignancy).
2. A 42-year-old female with a long history of poorly controlled hypertension is
admitted with severe headache and visual disturbances. Echocardiography reveals
significant left ventricular wall thickening, and myocardial biopsy shows enlarged
cardiac myocytes with increased amounts of cytoplasmic structural proteins. This
myocardial change is BEST described as:
• A. Hyperplasia resulting from increased number of cardiac myocytes under stress
• B. Hypertrophy resulting from increased cell size due to chronic pressure
overload
• C. Metaplasia resulting from replacement of one mature cell type by another
• D. Dysplasia resulting from disorganized cellular proliferation in the myocardium
Correct Answer: B
Rationale: Cardiac myocytes are terminally differentiated cells that cannot undergo
hyperplasia, so they respond to chronic pressure overload by increasing in size through the
addition of structural proteins, which defines hypertrophy. Cardiac myocytes are
permanent cells that have lost the ability to divide and therefore cannot increase in
number through hyperplasia (A).
3. A pathologist examining a tissue specimen notes cell swelling, vacuolation, and
nuclear changes including pyknosis (nuclear condensation). These findings are
MOST consistent with:
• A. Apoptosis
• B. Reversible cell injury (early ischemic change)
• C. Necrosis (late cell death with inflammation)
, • D. Metaplasia
Correct Answer: B
Rationale: Cellular swelling (hydropic change) and vacuolation are hallmarks of reversible
cell injury — early ischemic/hypoxic changes that can resolve if oxygenation is restored.
Pyknosis (chromatin condensation) may be present early. Necrosis (C) is characterized by
cell membrane rupture, inflammation, and progressive nuclear changes with surrounding
inflammation. Apoptosis (A) is programmed, controlled cell death without inflammation.
4. A 58-year-old male construction worker presents with chronic fatigue and
shortness of breath. He has a 30-year history of smoking two packs per day, and
his arterial blood gas reveals a carboxyhemoglobin level of 12%. His cardiac
myocytes show mitochondrial swelling and cristae disruption on electron
microscopy. The cellular injury pattern observed in this patient is BEST classified
as:
• A. Hypoxic injury due to decreased oxygen-carrying capacity of hemoglobin
• B. Ischemic injury due to reduced arterial blood flow to myocardial tissue
• C. Chemical injury due to direct toxin-mediated destruction of cell membranes
• D. Apoptotic injury due to programmed cell death triggered by carbon monoxide
Correct Answer: A
Rationale: Carbon monoxide binds hemoglobin with 200 times the affinity of oxygen,
drastically reducing the oxygen-carrying capacity and causing hypoxic injury to tissues,
including mitochondrial swelling and cristae disruption. Ischemic injury (B) refers
specifically to reduced blood flow rather than impaired oxygen transport; the blood flow to
this patient's myocardium is not compromised.
5. A client who has been immobilized in bed for several weeks develops muscle
wasting. This is an example of:
, • A. Atrophy
• B. Hypertrophy
• C. Hyperplasia
• D. Metaplasia
Correct Answer: A
Rationale: Atrophy is a decrease in cell size and number due to decreased workload,
denervation, or decreased blood supply. Immobilization leads to muscle atrophy from
decreased use. Hypertrophy (B) is an increase in cell size. Hyperplasia (C) is an increase in
cell number. Metaplasia (D) is a change from one cell type to another.
6. A client develops benign prostatic hyperplasia (BPH). This is an example of:
• A. Atrophy
• B. Hypertrophy
• C. Hyperplasia (increase in cell number)
• D. Metaplasia
Correct Answer: C
Rationale: Hyperplasia is an increase in the number of cells in an organ or tissue. BPH is
caused by hormonal stimulation leading to an increase in the number of prostate cells.
7. A client who smokes develops squamous metaplasia in the bronchial epithelium.
This is an example of:
• A. Atrophy
• B. Hypertrophy
• C. Hyperplasia
• D. Metaplasia (replacement of one cell type with another)
Practice Questions with Verified Answers
This professional study resource is a premium test bank tailored for graduate nursing
students preparing for the Chamberlain University NR 507 Advanced
Pathophysiology Final Examination. It features highly targeted practice questions,
100% verified answers, and comprehensive rationales mapping cellular adaptations,
renal conditions, gastrointestinal changes, and complex neurological syndromes.
Preparing with these premium test-prep materials will sharpen your diagnostic
reasoning, streamline your study sessions, and ensure you earn an A grade on your
proctored assessment.
SECTION 1: CELLULAR ADAPTATION, INJURY & DEATH
(Questions 1–25)
1. A 68-year-old male with chronic GERD undergoes endoscopy revealing
intestinal-type columnar epithelium replacing the normal squamous epithelium in
the distal esophagus. This cellular adaptation is BEST described as:
• A. Hyperplasia
• B. Metaplasia
• C. Dysplasia
• D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one adult cell type with another,
often an adaptive substitution of cells sensitive to stress with cells better able to withstand
,the adverse environment. In Barrett esophagus, chronic acid exposure causes squamous
epithelium to be replaced by intestinal-type columnar epithelium. Hyperplasia (A) is
increased cell number; dysplasia (C) is disordered growth; anaplasia (D) is lack of
differentiation (malignancy).
2. A 42-year-old female with a long history of poorly controlled hypertension is
admitted with severe headache and visual disturbances. Echocardiography reveals
significant left ventricular wall thickening, and myocardial biopsy shows enlarged
cardiac myocytes with increased amounts of cytoplasmic structural proteins. This
myocardial change is BEST described as:
• A. Hyperplasia resulting from increased number of cardiac myocytes under stress
• B. Hypertrophy resulting from increased cell size due to chronic pressure
overload
• C. Metaplasia resulting from replacement of one mature cell type by another
• D. Dysplasia resulting from disorganized cellular proliferation in the myocardium
Correct Answer: B
Rationale: Cardiac myocytes are terminally differentiated cells that cannot undergo
hyperplasia, so they respond to chronic pressure overload by increasing in size through the
addition of structural proteins, which defines hypertrophy. Cardiac myocytes are
permanent cells that have lost the ability to divide and therefore cannot increase in
number through hyperplasia (A).
3. A pathologist examining a tissue specimen notes cell swelling, vacuolation, and
nuclear changes including pyknosis (nuclear condensation). These findings are
MOST consistent with:
• A. Apoptosis
• B. Reversible cell injury (early ischemic change)
• C. Necrosis (late cell death with inflammation)
, • D. Metaplasia
Correct Answer: B
Rationale: Cellular swelling (hydropic change) and vacuolation are hallmarks of reversible
cell injury — early ischemic/hypoxic changes that can resolve if oxygenation is restored.
Pyknosis (chromatin condensation) may be present early. Necrosis (C) is characterized by
cell membrane rupture, inflammation, and progressive nuclear changes with surrounding
inflammation. Apoptosis (A) is programmed, controlled cell death without inflammation.
4. A 58-year-old male construction worker presents with chronic fatigue and
shortness of breath. He has a 30-year history of smoking two packs per day, and
his arterial blood gas reveals a carboxyhemoglobin level of 12%. His cardiac
myocytes show mitochondrial swelling and cristae disruption on electron
microscopy. The cellular injury pattern observed in this patient is BEST classified
as:
• A. Hypoxic injury due to decreased oxygen-carrying capacity of hemoglobin
• B. Ischemic injury due to reduced arterial blood flow to myocardial tissue
• C. Chemical injury due to direct toxin-mediated destruction of cell membranes
• D. Apoptotic injury due to programmed cell death triggered by carbon monoxide
Correct Answer: A
Rationale: Carbon monoxide binds hemoglobin with 200 times the affinity of oxygen,
drastically reducing the oxygen-carrying capacity and causing hypoxic injury to tissues,
including mitochondrial swelling and cristae disruption. Ischemic injury (B) refers
specifically to reduced blood flow rather than impaired oxygen transport; the blood flow to
this patient's myocardium is not compromised.
5. A client who has been immobilized in bed for several weeks develops muscle
wasting. This is an example of:
, • A. Atrophy
• B. Hypertrophy
• C. Hyperplasia
• D. Metaplasia
Correct Answer: A
Rationale: Atrophy is a decrease in cell size and number due to decreased workload,
denervation, or decreased blood supply. Immobilization leads to muscle atrophy from
decreased use. Hypertrophy (B) is an increase in cell size. Hyperplasia (C) is an increase in
cell number. Metaplasia (D) is a change from one cell type to another.
6. A client develops benign prostatic hyperplasia (BPH). This is an example of:
• A. Atrophy
• B. Hypertrophy
• C. Hyperplasia (increase in cell number)
• D. Metaplasia
Correct Answer: C
Rationale: Hyperplasia is an increase in the number of cells in an organ or tissue. BPH is
caused by hormonal stimulation leading to an increase in the number of prostate cells.
7. A client who smokes develops squamous metaplasia in the bronchial epithelium.
This is an example of:
• A. Atrophy
• B. Hypertrophy
• C. Hyperplasia
• D. Metaplasia (replacement of one cell type with another)
