NR 507 | MIDTERM |
NR 507 — Midterm Exam
Advanced Pathophysiology
Chamberlain University | MSN Program
GRADE A | VERIFIED
50
Questions
MCQ
Format
A
Grade
WHAT THIS COVERS
Cellular Adaptation & Injury Cardiovascular Pathophysiology
Inflammation & Tissue Repair Respiratory Pathophysiology
Hemodynamic Disorders & Shock Renal Pathophysiology
Genetic & Developmental Disorders Neurological Pathophysiology
Neoplasia Endocrine Pathophysiology
ABOUT THIS ASSESSMENT
This midterm assessment covers the foundational mechanisms of disease at the cellular, tissue, and organ-system
levels expected in graduate advanced pathophysiology coursework. Content spans cellular adaptation and injury,
inflammation and tissue repair, hemodynamic disorders and shock, genetic and developmental disorders,
neoplasia, and the pathophysiology of the cardiovascular, respiratory, renal, neurological, and endocrine
systems.
Items emphasize mechanism-based reasoning rather than recall: cellular and molecular pathways, oncogene and
tumor-suppressor biology, hemodynamic and perfusion derangements, neuroplasticity and neurodegeneration,
and endocrine feedback disruption. Test-takers are expected to integrate normal physiology with altered
mechanisms to explain clinical findings and predict disease progression.
This is an original study assessment. It is not affiliated with, endorsed by, or representative of any official
university or licensing examination, and is intended for educational review only.
STUVIA ACTUAL EXAM
,NR 507 | MIDTERM | Chamberlain University | MSN Program
CELLULAR ADAPTATION & INJURY | Questions 1–5
1. A 68-year-old male with longstanding essential hypertension undergoes echocardiography that
demonstrates increased left ventricular wall thickness with no increase in myocyte number. Myocardial
biopsy would show increased cell size due to additional contractile protein synthesis. Which cellular
adaptation best describes this process?
A. Hypertrophy, a reversible increase in cell size in response to increased workload
B. Hyperplasia, an increase in cell number from hormonal stimulation
C. Metaplasia, replacement of one differentiated cell type with another
D. Atrophy, a decrease in cell size due to reduced metabolic activity
CORRECT ANSWER: A — Hypertrophy, a reversible increase in cell size in response to increased
workload
Rationale: Option A is correct because chronic pressure overload from hypertension increases myocardial work, stimulating
terminally differentiated myocytes (which cannot divide) to synthesize more contractile proteins and enlarge, producing classic
compensatory hypertrophy. Option B is incorrect because hyperplasia requires cell division, which cardiac myocytes cannot
undergo. Option C is incorrect because metaplasia is a reversible substitution of one mature cell type for another (e.g., squamous
metaplasia of bronchi), not an increase in cell size. Option D is incorrect because atrophy describes cell shrinkage from disuse,
denervation, or reduced demand, the opposite of this presentation.
2. A 55-year-old chronic smoker undergoes bronchoscopy for a persistent cough. Biopsy of the bronchial
epithelium reveals replacement of normal ciliated pseudostratified columnar epithelium with stratified
squamous epithelium. Which adaptive mechanism and stimulus are most likely?
A. Dysplasia induced by viral integration of human papillomavirus
B. Anaplasia indicating autonomous malignant transformation
C. Metaplasia induced by chronic irritation from tobacco smoke, with reversible substitution of cell type
D. Hyperplasia induced by estrogen stimulation of bronchial glands
CORRECT ANSWER: C — Metaplasia induced by chronic irritation from tobacco smoke, with
reversible substitution of cell type
Rationale: Option C is correct because chronic tobacco exposure irritates the bronchial mucosa, prompting reversible
substitution of ciliated columnar epithelium with more resilient stratified squamous epithelium, a classic adaptive metaplasia.
Option A is incorrect because dysplasia denotes disordered maturation with cytologic atypia, not a uniform substitution of one
mature cell type for another. Option B is incorrect because anaplasia is a hallmark of malignancy with complete loss of
differentiation, not a metaplastic adaptation. Option D is incorrect because hyperplasia increases cell number within the same
cell type rather than replacing it with a different type.
STUVIA ACTUAL EXAM Page 2
, NR 507 | MIDTERM | Chamberlain University | MSN Program
3. A researcher exposes cultured renal tubular cells to ischemia. Within minutes, ATP depletion causes
failure of the Na+/K+-ATPase pump. Which sequence best describes the subsequent cellular events leading to
irreversible injury?
A. Potassium influx leading to cellular swelling, followed by caspase-mediated apoptosis
B. Sodium influx causing cellular swelling, followed by calcium influx, mitochondrial permeability transition pore
opening, and necrosis
C. Calcium efflux causing cellular shrinkage and caspase-3 activation
D. Chloride efflux causing karyorrhexis without inflammation
CORRECT ANSWER: B — Sodium influx causing cellular swelling, followed by calcium influx,
mitochondrial permeability transition pore opening, and necrosis
Rationale: Option B is correct because ischemia depletes ATP, disabling Na+/K+-ATPase; sodium and water enter the cell
causing swelling, then intracellular calcium accumulates, opening the mitochondrial permeability transition pore and activating
phospholipases and proteases that drive membrane injury and necrosis. Option A is incorrect because potassium does not influx
in early ischemic injury (sodium does), and apoptosis is not the dominant irreversible pathway in ischemia. Option C is incorrect
because calcium influx (not efflux) is the key injurious event, and ischemia produces necrosis rather than orderly apoptosis.
Option D is incorrect because chloride shifts are not the primary driver of irreversible injury and karyorrhexis is typically part of
apoptosis, not the dominant ischemic pattern.
4. A 45-year-old female with a history of gallstones presents with severe epigastric pain radiating to the back.
Laboratory studies show elevated serum lipase and amylase. Histologic examination of peripancreatic tissue
would most likely reveal:
A. Caseating granulomas with Langhans giant cells
B. Coagulative necrosis preserving tissue architecture
C. Liquefactive necrosis with neutrophil infiltration
D. Fat necrosis with chalky-white deposits of calcium soap formation
CORRECT ANSWER: D — Fat necrosis with chalky-white deposits of calcium soap formation
Rationale: Option D is correct because acute pancreatitis releases activated lipases that digest peripancreatic adipose tissue,
releasing free fatty acids that combine with calcium to form chalky-white calcium soaps, the characteristic saponification of fat
necrosis. Option A is incorrect because caseating granulomas typify tuberculosis or fungal infection, not pancreatic enzymatic
injury. Option B is incorrect because coagulative necrosis preserves tissue outlines and is typical of ischemic injury in solid
organs, not enzymatic fat destruction. Option C is incorrect because although liquefactive necrosis can occur in the pancreas
itself, the pathognomonic peripancreatic finding is fat necrosis with saponification, not neutrophil-predominant liquefaction.
STUVIA ACTUAL EXAM Page 3