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MSE2183 Assignment 4 Semester 2 2026 - Due 26 August 2026

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Course Geometry (MSE2183)
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MSE2183 Assignment 4 Semester 2 2026 - Due 26 August 2026 QUESTION 2 Lesson 7 – Trigonometry 2.1 Complete the following self-assessments, 2.1.1 Self-assessment 7.1 (questions 2, 3 and 4 – all questions) (33) 2.1.2 Self-assessment 7.2 (questions 1 (a), (b), (c) and 2 (a), (b) (17) [50] QUESTION 3 Lesson 8 – Circle Geometry 3.1 Complete self-assessment 8.1 3.1.1 Question 1 (all questions) (25) 3.1.2 Question 2 (all questions) (15) [40] Total Marks - 100

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MSE2183 Assessment 4 2026-
DUE 26 AUGUST 2026


QUESTION 1: FORUM 5




QUESTION 2: LESSON 7 – TRIGONOMETRY

2.1 Self-Assessment 7.1

Question 2a: cos 150° (3 marks)

cos 150° = cos(180° - 30°) = -cos 30° = -√3/2




(UNISA, 2026, Lesson 7, p. 186) – shows reduction formula for cos(180° - θ)
(Serra, 2008, p. 185) – quadrant values and reduction

, Question 2b: sin(-45°)

: sin(-45°) = -sin 45° = -√2/2



(UNISA, 2026, Lesson 7, p. 187) – negative angle reduction formula
(Serra, 2008, p. 184) – special angle table




Question 2c: tan 480°


tan 480° = tan(480° - 360°) = tan 120° = tan(180° - 60°) = -tan 60° = -√3



(UNISA, 2026, Lesson 7, p. 187) – quadrant III and IV reduction formulae




Question 2d: [sin(180° + x) × cos 330° × tan 150°] / sin x



sin(180° + x) = -sin x
cos 330° = cos(360° - 30°) = cos 30° = √3/2tan 150° =
tan(180° - 30°) = -tan 30° = -1/√3




[(-sin x) × (√3/2) × (-1/√3)]
/ sin x= [(-sin x) × (-1/2)]
/ sin x
= (sin x/2) / sin x = 1/2

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