Finite Element Analysis
Assignment 3 Answers
Year 2026
0027 68 628 1800
,
, QUESTION 1
(a)
𝐿2−1 = 20𝑚 𝐿2−3 = 15𝑚 𝐿2−4 = 25𝑚
𝜃2−1 = 1800 𝜃2−3 = 900 𝜃2−4 = 143.130
sin 𝜃2−1 = 0 sin 𝜃2−3 = 1 sin 𝜃2−4 = 0.6
cos 𝜃2−1 = −1 cos 𝜃2−3 = 0 cos 𝜃2−4 = −0.8
𝐿1−4 = 15𝑚 𝐿1−3 = 25𝑚 𝐿3−4 = 20𝑚
𝜃1−4 = 900 𝜃1−3 = 36.870 𝜃3−4 = 1800
sin 𝜃1−4 = 1 sin 𝜃1−3 = 0.6 sin 𝜃3−4 = 0
cos 𝜃1−4 = 0 cos 𝜃1−3 = 0 cos 𝜃3−4 = −1
Boundary conditions 𝑢1 = 𝑣1 = 𝑢4 = 𝑣4 = 0
𝐶2 𝐶𝑆 −𝐶 2 −𝐶𝑆
𝐴𝐸 𝐶𝑆 𝑆2 −𝐶𝑆 −𝑆 2 ]
[𝐾] = [
𝐿 −𝐶 2 −𝐶𝑆 𝐶2 𝐶𝑆
−𝐶𝑆 −𝑆 2 𝐶𝑆 𝑆2
1 0 −1 0
𝐴𝐸 0 0 0 0]
𝑘2−1 = [
20 −1 0 1 0
0 0 0 0
Assignment 3 Answers
Year 2026
0027 68 628 1800
,
, QUESTION 1
(a)
𝐿2−1 = 20𝑚 𝐿2−3 = 15𝑚 𝐿2−4 = 25𝑚
𝜃2−1 = 1800 𝜃2−3 = 900 𝜃2−4 = 143.130
sin 𝜃2−1 = 0 sin 𝜃2−3 = 1 sin 𝜃2−4 = 0.6
cos 𝜃2−1 = −1 cos 𝜃2−3 = 0 cos 𝜃2−4 = −0.8
𝐿1−4 = 15𝑚 𝐿1−3 = 25𝑚 𝐿3−4 = 20𝑚
𝜃1−4 = 900 𝜃1−3 = 36.870 𝜃3−4 = 1800
sin 𝜃1−4 = 1 sin 𝜃1−3 = 0.6 sin 𝜃3−4 = 0
cos 𝜃1−4 = 0 cos 𝜃1−3 = 0 cos 𝜃3−4 = −1
Boundary conditions 𝑢1 = 𝑣1 = 𝑢4 = 𝑣4 = 0
𝐶2 𝐶𝑆 −𝐶 2 −𝐶𝑆
𝐴𝐸 𝐶𝑆 𝑆2 −𝐶𝑆 −𝑆 2 ]
[𝐾] = [
𝐿 −𝐶 2 −𝐶𝑆 𝐶2 𝐶𝑆
−𝐶𝑆 −𝑆 2 𝐶𝑆 𝑆2
1 0 −1 0
𝐴𝐸 0 0 0 0]
𝑘2−1 = [
20 −1 0 1 0
0 0 0 0
