PHY1505 ASSIGNMENT 2 Solutions 2026

PHY1505 ASSIGNMENT 2 Solutions 2026
UNISA
Module Code: PHY1505
Module Title: Elementary Mechanics
Assessment Format: Take-Home Assignment
Total Marks: 80
Duration: 8 -19 June 2026
First Examiner: Dr SJ Mofokeng
Second Examiner: Dr M Ramantswana

, Question 1

Given

• 𝑻𝟏 = 𝟒𝟔 N(horizontal to the left)

• 𝑻𝟐 = 𝟕𝟒 N(vertical upward)

• The loop is in equilibrium.

For equilibrium:

∑𝑭𝒙 = 𝟎, ∑𝑭𝒚 = 𝟎


Therefore, 𝑻𝟑 must balance both 𝑻𝟏 and 𝑻𝟐 .

Components of 𝑻𝟑

𝑻𝟑𝒙 = 𝟒𝟔 N
𝑻𝟑𝒚 = 𝟕𝟒 N

(The rope pulls downwards and to the right.)



Magnitude of 𝑻𝟑

Using Pythagoras:

𝑻𝟑 = √𝑻𝟐𝟑𝒙 + 𝑻𝟐𝟑𝒚

𝑻𝟑 = √𝟒𝟔𝟐 + 𝟕𝟒𝟐
𝑻𝟑 = √𝟐𝟏𝟏𝟔 + 𝟓𝟒𝟕𝟔
𝑻𝟑 = √𝟕𝟓𝟗𝟐
𝑻𝟑 = 𝟖𝟕. 𝟏𝟑 N

Direction of 𝑻𝟑
𝟕𝟒
𝐭𝐚𝐧⁡ 𝜽 =
𝟒𝟔
𝟕𝟒
𝜽 = 𝐭𝐚𝐧⁡−𝟏 ( )
𝟒𝟔
𝜽 = 𝟓𝟖. 𝟏𝟑∘

Answer

𝑻𝟑 = 𝟖𝟕. 𝟏 N
𝜽 = 𝟓𝟖. 𝟏∘

Direction: 58.1° below the horizontal toward the right.