~ EM
t
E
t
15 D
I t
1~ +
-+
ASSIGNMEN~
+r r 3 SEMESliER
r 1 r 1
-------Alt I: QUEST Il!I NS f IL: 1:1-ANS WERED-
1
0UE: 12 1uNE 2 02-
01scu1MER: 11 11
THI$ DOCUMEN IS FDR REFERENCE AND GUIDf'NCE PURP SES
aNLv. 1Do NOT TAKE REsPaNs1e1u1rv~FDR A~v PLAGIARl~M.f M1sus . DR
ACADEMIC MIS DNDUCT RESULTING FROM THEIRI
USE. IT IS YOUR ----
RESPDNSIBILIT! TO ENSU¥ ORIGINALITY lN CDMPl.!IANtE WITH
RELEVA T GUIDELINES DR STAND~RDS. ~....:... ..,....~
, PLEASE USE THIS DOCUMENT AS A GUIDE ONLY
Question 1
1. Unde1rstanding the Given Data
o Mass of ttie bmr hn,)· 1 slug
o Weight of the bar (W): W =m •g = I slug x 3,2.2 ft /i = 3,2.2 lb
o Length of the bar CL.)~ 0 inches
o Angle O'f the incline (6'): 0¢ (Note: The bar ls perpendicufar to the indlne).
o Coefficient of statiic fritctrro n (µ}: 0. 4
1
o Iofili: Downward at the lower end. This meanstihe lower end wants to slide down
l.mpendling mot1
the incline, so the friction force Facts upward along the incline.
2. Setting up the Coordinate Syst,em
le.f's align our coordinate, axes. with the incline to make the math deaner:
o -axis: Parallel to the indi e (positive pointing upwards along the·incline).
o y-axis: Perpendicular to tile•incline (positive po 1nti ng outwards/upwards along the·bar's
lengrth).
Force Com1pone nts:
1 We;ight (W = 3·2. :2 [b): Acts ve rt:lra l:ly downward.
o Component parallel to fncline (x-dir-ection}: W ~ =- W sin ( • O'i)
o Component perpendicular to incline (y-direct1on): ~ T/ = - W co ( -OC-' )
o STnce the bar ·is urirform, this weight acts right at its center of gravf y (G), -whfch is fr =
20 in hes from t e contact point.
2. Normal Force OV): .Acts at the base of the oo r alo:ng1the y-directirn1.
3 Friction Force tF): Since motion is impending downwards, Facts along .. Because it's. on
the verge of ~dipping:.
t
E
t
15 D
I t
1~ +
-+
ASSIGNMEN~
+r r 3 SEMESliER
r 1 r 1
-------Alt I: QUEST Il!I NS f IL: 1:1-ANS WERED-
1
0UE: 12 1uNE 2 02-
01scu1MER: 11 11
THI$ DOCUMEN IS FDR REFERENCE AND GUIDf'NCE PURP SES
aNLv. 1Do NOT TAKE REsPaNs1e1u1rv~FDR A~v PLAGIARl~M.f M1sus . DR
ACADEMIC MIS DNDUCT RESULTING FROM THEIRI
USE. IT IS YOUR ----
RESPDNSIBILIT! TO ENSU¥ ORIGINALITY lN CDMPl.!IANtE WITH
RELEVA T GUIDELINES DR STAND~RDS. ~....:... ..,....~
, PLEASE USE THIS DOCUMENT AS A GUIDE ONLY
Question 1
1. Unde1rstanding the Given Data
o Mass of ttie bmr hn,)· 1 slug
o Weight of the bar (W): W =m •g = I slug x 3,2.2 ft /i = 3,2.2 lb
o Length of the bar CL.)~ 0 inches
o Angle O'f the incline (6'): 0¢ (Note: The bar ls perpendicufar to the indlne).
o Coefficient of statiic fritctrro n (µ}: 0. 4
1
o Iofili: Downward at the lower end. This meanstihe lower end wants to slide down
l.mpendling mot1
the incline, so the friction force Facts upward along the incline.
2. Setting up the Coordinate Syst,em
le.f's align our coordinate, axes. with the incline to make the math deaner:
o -axis: Parallel to the indi e (positive pointing upwards along the·incline).
o y-axis: Perpendicular to tile•incline (positive po 1nti ng outwards/upwards along the·bar's
lengrth).
Force Com1pone nts:
1 We;ight (W = 3·2. :2 [b): Acts ve rt:lra l:ly downward.
o Component parallel to fncline (x-dir-ection}: W ~ =- W sin ( • O'i)
o Component perpendicular to incline (y-direct1on): ~ T/ = - W co ( -OC-' )
o STnce the bar ·is urirform, this weight acts right at its center of gravf y (G), -whfch is fr =
20 in hes from t e contact point.
2. Normal Force OV): .Acts at the base of the oo r alo:ng1the y-directirn1.
3 Friction Force tF): Since motion is impending downwards, Facts along .. Because it's. on
the verge of ~dipping:.
