Qmi 1500 exam pack

ELEMENTARY QUANTITATIVE METHODS


QMI 1500



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MAY/JUNE 2016
Question 1.

• Simply put the question as is into your calculator
8 29
• It is often safer to change all mixed fractions into improper fractions: so 3 7 will be 7

20
() + [(1/3) + (29/7)] – (6/7) = 421

Answer: Option 2



Question 2.
𝟑

∑(𝟓 + √𝒙𝟐 )
𝒊=𝟎

If x = 4

Then ∑𝟑𝒊=𝟎(𝟓 + √𝟒𝟐 ) = ∑𝟑𝒊=𝟎(𝟓 + 𝟒) = ∑𝟑𝒊=𝟎(𝟗)

Therefore = 9(4) = 36

Answer: Option 5



Question 3.

8𝑥 × 83𝑥
23𝑥 × 4𝑥+2
8𝑥+3𝑥
= 23𝑥 × 22(𝑥+2)

84𝑥
=
23𝑥 × 22𝑥+4

84𝑥
= 23𝑥+2𝑥+4

23(4𝑥)
=
25𝑥+4

212𝑥
= 25𝑥+4

= 212𝑥−(5𝑥+4)

= 212𝑥− 5𝑥 − 4

= 27𝑥−4

Answer: Option 3




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Question 4.
3𝑥−2 1 1−5𝑥
- =
4 4 2

3𝑥−2 1 1−5𝑥
4( ) – 4( ) = 4( )
4 4 2

3x – 2 – 1 = 2(1 – 5x)

3x – 3 = 2 – 10x

3x + 10x = 2 + 3

13x = 5
5
x = 13

Answer: Option 3



Question 5.

168 mangoes for R354
168
12
= 14 dozen

Total Revenue = R35 x 14



Profit = Revenue – Cost

= R490 – R354

= R136
𝑃𝑟𝑜𝑓𝑖𝑡
Percentage Profit = 𝐶𝑜𝑠𝑡

136
= 354 x 100

= 38.42%

Answer: Option 3



Question 6.

Total = 10

Any 4
10 10!
C4 = (10−4)! 4!

= 210

Answer: Option 1




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