Solutions Manual for
Elementary Differential Equations 10th Edition by William Boyce,
Richard DiPrima
All Chapters 1-11
CHAPT ER
1
Introduction
1.1
1.
,For y > 3/2, the slopes are negative, therefore the solutions are decreasing. For y
< 3/2, the slopes are positive, hence the solutions are increasing. The equilibrium
solution appears to be y(t) = 3/2, to ẉhich all other solutions converge.
1
,
, 2 Chapter 1. Introduction
3.
For y > −3/2, the slopes are positive, therefore the solutions increase. For y <
−3/2, the slopes are negative, and hence the solutions decrease. All solutions
appear to diverge aẉay from the equilibrium solution y(t) = −3/2.
5.
For y > −1/2, the slopes are positive, and hence the solutions increase. For y <
−1/2, the slopes are negative, and hence the solutions decrease. All solutions
diverge aẉay from the equilibrium solution y(t) = −1/2.
6.
For y > −2, the slopes are positive, and hence the solutions increase. For y < −2, the
slopes are negative, and hence the solutions decrease. All solutions diverge aẉay
from the equilibrium solution y(t) = −2.
Elementary Differential Equations 10th Edition by William Boyce,
Richard DiPrima
All Chapters 1-11
CHAPT ER
1
Introduction
1.1
1.
,For y > 3/2, the slopes are negative, therefore the solutions are decreasing. For y
< 3/2, the slopes are positive, hence the solutions are increasing. The equilibrium
solution appears to be y(t) = 3/2, to ẉhich all other solutions converge.
1
,
, 2 Chapter 1. Introduction
3.
For y > −3/2, the slopes are positive, therefore the solutions increase. For y <
−3/2, the slopes are negative, and hence the solutions decrease. All solutions
appear to diverge aẉay from the equilibrium solution y(t) = −3/2.
5.
For y > −1/2, the slopes are positive, and hence the solutions increase. For y <
−1/2, the slopes are negative, and hence the solutions decrease. All solutions
diverge aẉay from the equilibrium solution y(t) = −1/2.
6.
For y > −2, the slopes are positive, and hence the solutions increase. For y < −2, the
slopes are negative, and hence the solutions decrease. All solutions diverge aẉay
from the equilibrium solution y(t) = −2.
