Solutions Manual for Engineering Mechanics: Statics, 11th Edition (Hibbeler, 2006) | All Chapters 1–11 Covered

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A?
VI
TU
_S
ED
OV
PR
AP

,AP
TABLE OF CONTENTS
PR Engineering Mechanics: Statics (11th Edition) - Solutions Manual
R.C. Hibbeler


Chapter 1
OV
General Principles

Chapter 2 Force Vectors




R
Chapter 3 Equilibrium of a Particle
ED

U
Chapter 4 Force System Resultants




SE
Chapter 5 Equilibrium of a Rigid Body

Chapter 6 Structural Analysis _S
IS
Chapter 7 Internal Forces

Chapter 8 Friction

Chapter 9 Center of Gravity and Centroid
O TU
N
Chapter 10 Moments of Inertia
N

Chapter 11 Virtual Work
VI
O
C



A?
ED




?
M

,Engineering Mechanics - Statics
AP Chapter 1



Problem 1-1

Represent each of the following combinations of units in the correct SI form using an
appropriate prefix:
PR
(a) m/ms (b) km (c) ks/mg (d) kmN

Units Used:
6
N  10 N

6
OV
km  10 km

9
Gs  10 s ED
3
ks  10 s

3
mN  10 N _S
3
ms  10 s

Solution: TU
(a) m  1  103 m
ms s

m km
1
ms s

(b) km  1  10
3
m
VI
km  1 mm
A?
(c) ks  1  109 s
mg kg ?
ks Gs
1
mg kg

3
(d) kmN  1  10 mN

kmN  1 mmN

, Engineering Mechanics - Statics
AP Chapter 1



Problem 1-2

Wood has a density d. What is its density expressed in SI units?
PR
Units Used:

Mg  1000 kg

Given:

d  4.70
OV
slug
3
ft

Solution:

1slug  14.594 kg
Mg
ED
d  2.42
3
m _S
Problem 1-3

Represent each of the following combinations of units in the correct SI form using an
appropriate prefix:
TU
(a) Mg/mm (b) mN/s (c) mMg

Solution: VI
3 6
Mg 10 kg 10 kg Gg
(a) mm   
3 m m
10 m A?
Mg Gg

mm m

3 3
mN 10 N  10 N kN
(b)  
s
10
6
s
s s
?
mN kN

s s

(c) mMg   10 6 m103 kg  10 3 m kg
mMg  mmkg