Physics 102A
, MNEMATICS
S
I ve
x -
t
InstantaneousVelocityat any
t 1
i
m
point
= 1
=
= 0
xo
Do
=
10m
t =
10s t -
to &
-
to =
IS = 5 . 6 m/S
Aspeed object is
=
at
t
nitude a speed of
traveling
5 6 .
m/s at
of velocity - a direction +
t ↳ bom
168-5
=
o
=
, .
am
& traveling
a
x =
10m 5. 6m/s
5 in the []
7) direction !
acceleration :
rate of
change of
velocity
S
V T
IDEQUATIONS OF MOTION FOR
-
V
V n CONSTANT ACCELLERATION
-
- - - - - -
voz + a +2
+ anti
d =
- Vo
V a= slope (V-T graph) ↓. x =
30 +
Vot
coordinate
⑮
= on >2 airis x
rector ( + >d
Vo =
10m's
( +Tc)-
Vo ex :
--iz -
71 -c =
Os
he Vi
V
t
=
=
50m/s
10S
↓ .
2 < =
xo Fict
+ =
x0
+
+g +
t
=
a
= 4
=
·
ex .
dragster -y find acceleration and final velocity .
3 V =
Foss +
ascate
d= mile
t =
55 Sec
DeVos earn
Dan
formula manipulation : D .
Ena
= ax+
2
* x
velocity
:
Vast Fox + ast
(32 2 mis ) (55s)
·
.
2 =
1609m/s
cars
racing
mili
d
V2TVI
car 2 Freely Falling Bodies :
-9 8 m/s.
y direction mag 9 am/s2 in Ey) direction
,
has a higher - the acceleration in the ~ .
final velo siyut
3
still loses .
g
=
9 8m/s +
Voyt - gt
y yo
.
=
-
t
ay
= -
g Call ID formulas shift)
,assignment 1: V
= 4 m/s a =
9 % .
II . -. com d= = 0
"m=metres
3
=5
=
A
↓
2
top =
O
=
xg
=
& ISDI . = m
v =
vo + 2ad
2 . a)
&
1 a =
do +
vot zatz
+
=
0
=
42 + 2) -
9 8)
I a
.
3
82cm
=
0
= 1 .
g + 4(t) -
4 90572
.
traves . 9-3 =
6 +2 =
am
quad it up ! 4= 15.316 =
1 -
145
-
7 .
t =
18t = 0 .
3
.8
9
3 .
Votzad
= 2(9 8)(18) + .
vag === 34 . 3250south of east
=
6 27 m/s.
34 3 km/n .
1@minx
3h
=
= 0 .
total trip 1 min there/back :
18(2) =
39 mins
=
0 Ghours
.
relative+ o
distance :
& total = 24 km
shours
+=
Vixd
total time (h
=
2 5
.
14 .
8
. velocity calculated wi +
is
displacement a
=
-
9 .
there/back
=
Odisp =
0
# :
vo + 2ad
-V =
Vad
.
9
v =
2m/s ?
1Pmi 1 .
43
=
=9.
2 5)
Tm/S
.
b) Vf = 0
S=
E & total = 5M
ai
=
1 .
4
Ead
=5 :
0.5
t =
0 .
800s =
vi = at =
1 .
12m/S S :
Ea(5) =
9 amis
.
vf
=
Vit abt
40m
:=
ab 1 .
, Sept 11
physics
2 . What is the
velocity of rock at bottom of cliff .
rock is thrown upwards at 18m/s ·
& what
? Vy = 0
is
velocity at bottom
a = 9 8m/s
.
2
+
? 18m/s
(y-yo)
=
Vy2 =
Voy -
2g
Voy
origin (yo Om)
=
: =
102 = 45 z
·
-
2(9 8)(-100) . . 4 mis
& how high above cliff does it go
?
100 m
Voy 2g (y -yo)
?
Vy
-
=
Vy = 45 4 m/s
Voy-2g(y-o)
Noy =O
=
-
o
.
: = = 100m
y
-
-
③ how
long does it take?
se&
le
·
a) y
=
y
+
Voyt-0 5gt .
Vy Voy-gt=
(0 5)(9 8772
Lay ==
-
100 =
0 + 10 -
. .
-10 :
5
20 5) (9) (t))
.
-
18 + 100 - :
know
b2 4ac = t =
5 7
b
-
=
.
-
=
t = -
3 65s past
2a
.
⑪ what is different if , now down at comis interesting .
Vy Voy"-2g(y-yo
2
* =
Vy2 -102 269 8) (-100)
-
= - :
.
45 4 10 65m/
=
-
45 4 m/S
.
.
-
=
3 .
same as + 102 -
9 8 .
time will be different
ex .
a parachutist descends at a speed of 10m/s and drops a camera from an altitude of
50m What . time does camera take to reach ground?
&
decend
Voy =
10m/s
-
30
Xy2 Voy2 2g(y-yo) Yy Voy gt
=
50
= = -
Y
-
Voy
=
-10
Vy
= -
102 -
2(9 .
8)(50) =
t
= 32 9m/S
50m .
3290) 23sn
:
=
-
- V= G
0
y
=
, MNEMATICS
S
I ve
x -
t
InstantaneousVelocityat any
t 1
i
m
point
= 1
=
= 0
xo
Do
=
10m
t =
10s t -
to &
-
to =
IS = 5 . 6 m/S
Aspeed object is
=
at
t
nitude a speed of
traveling
5 6 .
m/s at
of velocity - a direction +
t ↳ bom
168-5
=
o
=
, .
am
& traveling
a
x =
10m 5. 6m/s
5 in the []
7) direction !
acceleration :
rate of
change of
velocity
S
V T
IDEQUATIONS OF MOTION FOR
-
V
V n CONSTANT ACCELLERATION
-
- - - - - -
voz + a +2
+ anti
d =
- Vo
V a= slope (V-T graph) ↓. x =
30 +
Vot
coordinate
⑮
= on >2 airis x
rector ( + >d
Vo =
10m's
( +Tc)-
Vo ex :
--iz -
71 -c =
Os
he Vi
V
t
=
=
50m/s
10S
↓ .
2 < =
xo Fict
+ =
x0
+
+g +
t
=
a
= 4
=
·
ex .
dragster -y find acceleration and final velocity .
3 V =
Foss +
ascate
d= mile
t =
55 Sec
DeVos earn
Dan
formula manipulation : D .
Ena
= ax+
2
* x
velocity
:
Vast Fox + ast
(32 2 mis ) (55s)
·
.
2 =
1609m/s
cars
racing
mili
d
V2TVI
car 2 Freely Falling Bodies :
-9 8 m/s.
y direction mag 9 am/s2 in Ey) direction
,
has a higher - the acceleration in the ~ .
final velo siyut
3
still loses .
g
=
9 8m/s +
Voyt - gt
y yo
.
=
-
t
ay
= -
g Call ID formulas shift)
,assignment 1: V
= 4 m/s a =
9 % .
II . -. com d= = 0
"m=metres
3
=5
=
A
↓
2
top =
O
=
xg
=
& ISDI . = m
v =
vo + 2ad
2 . a)
&
1 a =
do +
vot zatz
+
=
0
=
42 + 2) -
9 8)
I a
.
3
82cm
=
0
= 1 .
g + 4(t) -
4 90572
.
traves . 9-3 =
6 +2 =
am
quad it up ! 4= 15.316 =
1 -
145
-
7 .
t =
18t = 0 .
3
.8
9
3 .
Votzad
= 2(9 8)(18) + .
vag === 34 . 3250south of east
=
6 27 m/s.
34 3 km/n .
1@minx
3h
=
= 0 .
total trip 1 min there/back :
18(2) =
39 mins
=
0 Ghours
.
relative+ o
distance :
& total = 24 km
shours
+=
Vixd
total time (h
=
2 5
.
14 .
8
. velocity calculated wi +
is
displacement a
=
-
9 .
there/back
=
Odisp =
0
# :
vo + 2ad
-V =
Vad
.
9
v =
2m/s ?
1Pmi 1 .
43
=
=9.
2 5)
Tm/S
.
b) Vf = 0
S=
E & total = 5M
ai
=
1 .
4
Ead
=5 :
0.5
t =
0 .
800s =
vi = at =
1 .
12m/S S :
Ea(5) =
9 amis
.
vf
=
Vit abt
40m
:=
ab 1 .
, Sept 11
physics
2 . What is the
velocity of rock at bottom of cliff .
rock is thrown upwards at 18m/s ·
& what
? Vy = 0
is
velocity at bottom
a = 9 8m/s
.
2
+
? 18m/s
(y-yo)
=
Vy2 =
Voy -
2g
Voy
origin (yo Om)
=
: =
102 = 45 z
·
-
2(9 8)(-100) . . 4 mis
& how high above cliff does it go
?
100 m
Voy 2g (y -yo)
?
Vy
-
=
Vy = 45 4 m/s
Voy-2g(y-o)
Noy =O
=
-
o
.
: = = 100m
y
-
-
③ how
long does it take?
se&
le
·
a) y
=
y
+
Voyt-0 5gt .
Vy Voy-gt=
(0 5)(9 8772
Lay ==
-
100 =
0 + 10 -
. .
-10 :
5
20 5) (9) (t))
.
-
18 + 100 - :
know
b2 4ac = t =
5 7
b
-
=
.
-
=
t = -
3 65s past
2a
.
⑪ what is different if , now down at comis interesting .
Vy Voy"-2g(y-yo
2
* =
Vy2 -102 269 8) (-100)
-
= - :
.
45 4 10 65m/
=
-
45 4 m/S
.
.
-
=
3 .
same as + 102 -
9 8 .
time will be different
ex .
a parachutist descends at a speed of 10m/s and drops a camera from an altitude of
50m What . time does camera take to reach ground?
&
decend
Voy =
10m/s
-
30
Xy2 Voy2 2g(y-yo) Yy Voy gt
=
50
= = -
Y
-
Voy
=
-10
Vy
= -
102 -
2(9 .
8)(50) =
t
= 32 9m/S
50m .
3290) 23sn
:
=
-
- V= G
0
y
=
