HESI A2 Physics Exam
2025/2026 – Verified
Questions & Correct Answers
| Real Test Practice
Section 1: Motion (Questions 1-40)
Question 1
A nurse pushes a wheelchair with a constant acceleration of 0.5 m/s² over 10 seconds from rest.
What is the final velocity? A. 2.5 m/s B. 5 m/s C. 10 m/s D. 0 m/s
Correct Answer: B
Rationale: Using the kinematic equation v = u + at (where u = 0 initial velocity, a = 0.5 m/s², t =
10 s), v = 0 + (0.5)(10) = 5 m/s. This illustrates linear motion principles, relevant for calculating
safe acceleration in patient transport to avoid discomfort or injury.
Question 2
An object falls freely under gravity (g = 9.8 m/s²). How far does it fall in 2 seconds? A. 9.8 m B.
19.6 m C. 4.9 m D. 39.2 m
Correct Answer: B
Rationale: From s = (1/2)gt² (initial velocity 0), s = (1/2)(9.8)(4) = 19.6 m. Free fall
demonstrates constant acceleration due to gravity, applicable to understanding fall risks in
healthcare settings for impact velocity estimation.
Question 3
A car travels 100 m at 20 m/s. What is its time of travel? A. 2 s B. 5 s C. 10 s D. 20 s
Correct Answer: B
Rationale: Time t = distance / speed = = 5 s. This basic kinematic relation (uniform
motion) helps in timing medical transports or infusion rates.
,Question 4
If velocity doubles and time halves, what happens to distance? A. Halves B. Stays the same C.
Doubles D. Quadruples
Correct Answer: B
Rationale: Distance s = v t; (2v)(t/2) = v t, unchanged. Principle of displacement invariance
under proportional changes, useful for adjusting patient movement schedules.
Question 5
An object decelerates from 30 m/s to 10 m/s in 4 s. What is the acceleration? A. -5 m/s² B. 5 m/s²
C. -2.5 m/s² D. 2.5 m/s²
Correct Answer: A
Rationale: a = (v - u)/t = (10 - 30)/4 = -20/4 = -5 m/s². Negative acceleration (deceleration)
follows Newton's first law; relevant for braking in ambulances to prevent whiplash.
Question 6
A projectile is launched at 45° with 20 m/s initial speed. What is the maximum height? (g = 9.8
m/s²) A. 10.2 m B. 20.4 m C. 5.1 m D. 40.8 m
Correct Answer: A
Rationale: h = (v sinθ)² / (2g) = (20 sin45°)² / (2*9.8) ≈ (14.14)² / 19.6 ≈ 10.2 m. Parabolic
motion principle; applies to trajectory of thrown objects in emergency scenarios.
Question 7
Average speed is 60 km/h for 2 hours. Total distance? A. 60 km B. 120 km C. 30 km D. 180 km
Correct Answer: B
Rationale: Distance = speed × time = 60 × 2 = 120 km. Uniform motion equation; used in
calculating travel time for medical supplies.
Question 8
Acceleration is constant at 2 m/s² for 3 s from 4 m/s. Final velocity? A. 6 m/s B. 8 m/s C. 10 m/s
D. 12 m/s
Correct Answer: C
, Rationale: v = u + at = 4 + 2*3 = 10 m/s. First kinematic equation; illustrates velocity change in
accelerating stretchers.
Question 9
Distance covered with initial velocity 0, a = 1.5 m/s², t = 6 s? A. 9 m B. 18 m C. 27 m D. 36 m
Correct Answer: C
Rationale: s = (1/2)at² = 0.51.536 = 27 m. Second kinematic equation; key for distance in
constant acceleration, like falling objects.
Question 10
If force causes 4 m/s² acceleration on 2 kg mass, what is the force? (F = ma) A. 4 N B. 8 N C. 2
N D. 6 N
Correct Answer: B
Rationale: F = m a = 2*4 = 8 N. Newton's second law; applies to force needed for moving
equipment.
Question 11
A ball rolls 20 m in 4 s, then 30 m in 6 s. Average speed? A. 2.5 m/s B. 3 m/s C. 5 m/s D. 7 m/s
Correct Answer: B
Rationale: Total distance 50 m, total time 10 s, speed = 50/10 = 5 m/s? Wait, recalculate: First 5
m/s, second 5 m/s, average 5 m/s. Wait, options have 5. Correct C 5 m/s.
Correct Answer: C
Rationale: Average speed = total distance / total time = 50/10 = 5 m/s. Principle of average vs
instantaneous speed; useful for non-uniform motion in diagnostics.
Question 12
Velocity is 10 m/s north, acceleration 2 m/s² south. Time to stop? A. 2 s B. 5 s C. 10 s D. 20 s
Correct Answer: A
Rationale: a = -2 m/s², v = 0 = 10 + (-2)t, t = 5 s? Wait, 10/2 = 5 s. Correct B.
Correct Answer: B
2025/2026 – Verified
Questions & Correct Answers
| Real Test Practice
Section 1: Motion (Questions 1-40)
Question 1
A nurse pushes a wheelchair with a constant acceleration of 0.5 m/s² over 10 seconds from rest.
What is the final velocity? A. 2.5 m/s B. 5 m/s C. 10 m/s D. 0 m/s
Correct Answer: B
Rationale: Using the kinematic equation v = u + at (where u = 0 initial velocity, a = 0.5 m/s², t =
10 s), v = 0 + (0.5)(10) = 5 m/s. This illustrates linear motion principles, relevant for calculating
safe acceleration in patient transport to avoid discomfort or injury.
Question 2
An object falls freely under gravity (g = 9.8 m/s²). How far does it fall in 2 seconds? A. 9.8 m B.
19.6 m C. 4.9 m D. 39.2 m
Correct Answer: B
Rationale: From s = (1/2)gt² (initial velocity 0), s = (1/2)(9.8)(4) = 19.6 m. Free fall
demonstrates constant acceleration due to gravity, applicable to understanding fall risks in
healthcare settings for impact velocity estimation.
Question 3
A car travels 100 m at 20 m/s. What is its time of travel? A. 2 s B. 5 s C. 10 s D. 20 s
Correct Answer: B
Rationale: Time t = distance / speed = = 5 s. This basic kinematic relation (uniform
motion) helps in timing medical transports or infusion rates.
,Question 4
If velocity doubles and time halves, what happens to distance? A. Halves B. Stays the same C.
Doubles D. Quadruples
Correct Answer: B
Rationale: Distance s = v t; (2v)(t/2) = v t, unchanged. Principle of displacement invariance
under proportional changes, useful for adjusting patient movement schedules.
Question 5
An object decelerates from 30 m/s to 10 m/s in 4 s. What is the acceleration? A. -5 m/s² B. 5 m/s²
C. -2.5 m/s² D. 2.5 m/s²
Correct Answer: A
Rationale: a = (v - u)/t = (10 - 30)/4 = -20/4 = -5 m/s². Negative acceleration (deceleration)
follows Newton's first law; relevant for braking in ambulances to prevent whiplash.
Question 6
A projectile is launched at 45° with 20 m/s initial speed. What is the maximum height? (g = 9.8
m/s²) A. 10.2 m B. 20.4 m C. 5.1 m D. 40.8 m
Correct Answer: A
Rationale: h = (v sinθ)² / (2g) = (20 sin45°)² / (2*9.8) ≈ (14.14)² / 19.6 ≈ 10.2 m. Parabolic
motion principle; applies to trajectory of thrown objects in emergency scenarios.
Question 7
Average speed is 60 km/h for 2 hours. Total distance? A. 60 km B. 120 km C. 30 km D. 180 km
Correct Answer: B
Rationale: Distance = speed × time = 60 × 2 = 120 km. Uniform motion equation; used in
calculating travel time for medical supplies.
Question 8
Acceleration is constant at 2 m/s² for 3 s from 4 m/s. Final velocity? A. 6 m/s B. 8 m/s C. 10 m/s
D. 12 m/s
Correct Answer: C
, Rationale: v = u + at = 4 + 2*3 = 10 m/s. First kinematic equation; illustrates velocity change in
accelerating stretchers.
Question 9
Distance covered with initial velocity 0, a = 1.5 m/s², t = 6 s? A. 9 m B. 18 m C. 27 m D. 36 m
Correct Answer: C
Rationale: s = (1/2)at² = 0.51.536 = 27 m. Second kinematic equation; key for distance in
constant acceleration, like falling objects.
Question 10
If force causes 4 m/s² acceleration on 2 kg mass, what is the force? (F = ma) A. 4 N B. 8 N C. 2
N D. 6 N
Correct Answer: B
Rationale: F = m a = 2*4 = 8 N. Newton's second law; applies to force needed for moving
equipment.
Question 11
A ball rolls 20 m in 4 s, then 30 m in 6 s. Average speed? A. 2.5 m/s B. 3 m/s C. 5 m/s D. 7 m/s
Correct Answer: B
Rationale: Total distance 50 m, total time 10 s, speed = 50/10 = 5 m/s? Wait, recalculate: First 5
m/s, second 5 m/s, average 5 m/s. Wait, options have 5. Correct C 5 m/s.
Correct Answer: C
Rationale: Average speed = total distance / total time = 50/10 = 5 m/s. Principle of average vs
instantaneous speed; useful for non-uniform motion in diagnostics.
Question 12
Velocity is 10 m/s north, acceleration 2 m/s² south. Time to stop? A. 2 s B. 5 s C. 10 s D. 20 s
Correct Answer: A
Rationale: a = -2 m/s², v = 0 = 10 + (-2)t, t = 5 s? Wait, 10/2 = 5 s. Correct B.
Correct Answer: B
