TEST BANK For Fundamentals of Physics 10th
w w w w w w
w Edition By Resnick, Walker and Halliday
w w w w w
w Chapters 1 - 44
w w w
,Chapter 1 w
1. Various geometric formulas are given in Appendix E.
w w w w w w w
(a) Expressing the radius of the Earth as w w w w w w
R = w w (6.37 w 106 m)(10−3 km m) = 6.37 103 km,
w w w w w w w w w
its circumference is s = 2 R = 2 (6.37 103 km) = 4.00 104 km.
w w w w w w w w w w w w w w w w
(b) The surface area of Earth is A = 4
w w w w w w w w = 4 ( 6.37 103
w w w w w = 5.10
w w km2.
R2 108
km )
w 2 w
w
4 4
( 6.37 103 km )
3 w ww
(c) The volume of Earth is V = R3 = = 1.08 1012 km 3 .
ww w
w w w w w w w w ww ww w w ww w w w ww
3 3
2. The conversion factors are: 1 gry = 1/10 line , 1 line = 1/12 inch and 1 point =
w w w w w w w w w w w w w w w w w w
w1/72inch. The factors imply that
w w w w w
1 gry = (1/10)(1/12)(72 points) = 0.60 point.
w w w w w w w
Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .
w w w w w w w w w w w w w w w w w
3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the
w w w w w w w w w w w w w
winsidefront cover of the textbook (see also Table 1–2).
w w w w w w w w w
(a) Since 1 km = 1 103 m and 1 m = 1 106 m,
w w w w w w w w w w w w w w w w
1km = 103 m = w w w w w (103 m m) =
w w w m.
109
m)(106
w
w
The given measurement is 1.0 km (two significant figures), which implies
w w w w w w w w w w
wour resultshould be written as 1.0 109 m.
w w w w w w w w w
(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10−2 m,
w w w w w w w w w w w w w w w
1cm = 10−2 m = w w w w w (10−2m)(106 m m) = w w w w m.
w104
We conclude that the fraction of one centimeter equal to 1.0 m is 1.0
w w w w w w w w w w w w w w
w 10−4.(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
w w w w w w w w w w w
,1
, 2 CHAPTER 1
1.0 yd = (0.91m)(106 m m) = 9.1
w w w w w w w w w m.
105
w
4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1
w w w w w w w w w w w w w w w
winch, weobtain w w
6 picas
= (0.80
0.80 cm 1.9 picas.
w w w w
1 inch
cm)
w w w w w
w
2.54 cm 1 inch w w w
w
w w w w
(b) With 12 points = 1 pica, we
w w w w w w w
whave
0.80
cm = (0.80 cm) 1 inch 6 picas 12 points
23 points.
w w w w w w w w w w w
w
w w
2.54 cm 1 inch 1 pica
w w w w
w
w w w w w
5. Given that 1 = 201.168 m , 1 rod = 5.0292 and 1 chain = 20.117 m , we find
w w w w w w w w w w w w w w w w w
furlong
w m w
the relevant conversion factors to be
w w w w w
1 rod
1.0 furlong = 201.168 m = (201.168 m = 40 rods,
w
w w w w w w w w w
) w
5.0292 m
and
1 chain
1.0 furlong = 201.168 m = (201.168 =10 chains .
w
w w w w w w w w
m) w
20.117 m w
w
Note the cancellation of m (meters), the unwanted unit. Using the given
w w w w w w w w w w w
wconversionfactors, we find w w w
(a) the distance d in rods to be
w w w w w w
40
d = 4.0 furlongs =(4.0 furlongs)
w w w w w w
= 160 rods, w w
wrods
1 furlong
w
(b) and that distance in chains to be
w w w w w w
10 chains
d = 4.0 furlongs =(4.0 furlongs) = 40 chains.
w w
w w w w w w w
1 furlong
w
6. We make use of Table 1-6.
w w w w w
(a) We look at the first (“cahiz”) column: 1 fanega is equivalent to what amount of
w w w w w w w w w w w w w w
wcahiz? We note from the already completed part of the table that 1 cahiz equals a
w w w w w w w w w w w w w w w
wdozen fanega. Thus,
w
12 1 fanega =
1
cahiz, or 8.33 10−2 cahiz. Similarly, “1 cahiz =
w w w w w w w w w w w w w w w
w48 cuartilla” (in the
w w w
already completed part) implies that 1 cuartilla =
w w w w w w w w
1
wcahiz,
48 w or 2.08
w w w 10−2 w cahiz.
w Continuing in this way, the remaining entries in the first column are 6.94
w w w w w w w w w w w w w
w w w w w w
w Edition By Resnick, Walker and Halliday
w w w w w
w Chapters 1 - 44
w w w
,Chapter 1 w
1. Various geometric formulas are given in Appendix E.
w w w w w w w
(a) Expressing the radius of the Earth as w w w w w w
R = w w (6.37 w 106 m)(10−3 km m) = 6.37 103 km,
w w w w w w w w w
its circumference is s = 2 R = 2 (6.37 103 km) = 4.00 104 km.
w w w w w w w w w w w w w w w w
(b) The surface area of Earth is A = 4
w w w w w w w w = 4 ( 6.37 103
w w w w w = 5.10
w w km2.
R2 108
km )
w 2 w
w
4 4
( 6.37 103 km )
3 w ww
(c) The volume of Earth is V = R3 = = 1.08 1012 km 3 .
ww w
w w w w w w w w ww ww w w ww w w w ww
3 3
2. The conversion factors are: 1 gry = 1/10 line , 1 line = 1/12 inch and 1 point =
w w w w w w w w w w w w w w w w w w
w1/72inch. The factors imply that
w w w w w
1 gry = (1/10)(1/12)(72 points) = 0.60 point.
w w w w w w w
Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry 2 = 0.18 point 2 .
w w w w w w w w w w w w w w w w w
3. The metric prefixes (micro, pico, nano, …) are given for ready reference on the
w w w w w w w w w w w w w
winsidefront cover of the textbook (see also Table 1–2).
w w w w w w w w w
(a) Since 1 km = 1 103 m and 1 m = 1 106 m,
w w w w w w w w w w w w w w w w
1km = 103 m = w w w w w (103 m m) =
w w w m.
109
m)(106
w
w
The given measurement is 1.0 km (two significant figures), which implies
w w w w w w w w w w
wour resultshould be written as 1.0 109 m.
w w w w w w w w w
(b) We calculate the number of microns in 1 centimeter. Since 1 cm = 10−2 m,
w w w w w w w w w w w w w w w
1cm = 10−2 m = w w w w w (10−2m)(106 m m) = w w w w m.
w104
We conclude that the fraction of one centimeter equal to 1.0 m is 1.0
w w w w w w w w w w w w w w
w 10−4.(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
w w w w w w w w w w w
,1
, 2 CHAPTER 1
1.0 yd = (0.91m)(106 m m) = 9.1
w w w w w w w w w m.
105
w
4. (a) Using the conversion factors 1 inch = 2.54 cm exactly and 6 picas = 1
w w w w w w w w w w w w w w w
winch, weobtain w w
6 picas
= (0.80
0.80 cm 1.9 picas.
w w w w
1 inch
cm)
w w w w w
w
2.54 cm 1 inch w w w
w
w w w w
(b) With 12 points = 1 pica, we
w w w w w w w
whave
0.80
cm = (0.80 cm) 1 inch 6 picas 12 points
23 points.
w w w w w w w w w w w
w
w w
2.54 cm 1 inch 1 pica
w w w w
w
w w w w w
5. Given that 1 = 201.168 m , 1 rod = 5.0292 and 1 chain = 20.117 m , we find
w w w w w w w w w w w w w w w w w
furlong
w m w
the relevant conversion factors to be
w w w w w
1 rod
1.0 furlong = 201.168 m = (201.168 m = 40 rods,
w
w w w w w w w w w
) w
5.0292 m
and
1 chain
1.0 furlong = 201.168 m = (201.168 =10 chains .
w
w w w w w w w w
m) w
20.117 m w
w
Note the cancellation of m (meters), the unwanted unit. Using the given
w w w w w w w w w w w
wconversionfactors, we find w w w
(a) the distance d in rods to be
w w w w w w
40
d = 4.0 furlongs =(4.0 furlongs)
w w w w w w
= 160 rods, w w
wrods
1 furlong
w
(b) and that distance in chains to be
w w w w w w
10 chains
d = 4.0 furlongs =(4.0 furlongs) = 40 chains.
w w
w w w w w w w
1 furlong
w
6. We make use of Table 1-6.
w w w w w
(a) We look at the first (“cahiz”) column: 1 fanega is equivalent to what amount of
w w w w w w w w w w w w w w
wcahiz? We note from the already completed part of the table that 1 cahiz equals a
w w w w w w w w w w w w w w w
wdozen fanega. Thus,
w
12 1 fanega =
1
cahiz, or 8.33 10−2 cahiz. Similarly, “1 cahiz =
w w w w w w w w w w w w w w w
w48 cuartilla” (in the
w w w
already completed part) implies that 1 cuartilla =
w w w w w w w w
1
wcahiz,
48 w or 2.08
w w w 10−2 w cahiz.
w Continuing in this way, the remaining entries in the first column are 6.94
w w w w w w w w w w w w w
