MIP1502 Assessment FOUR 2025

MIP1502 ASSESSMENT 4 2025

Question 1

1.1.1

Situation 1

Independent variable – number of kilometres driven

Dependent variable – cost of renting a van

Situation 2

Independent variable - length of the radius

Dependent variable – area of the circle

1.1.2

Situation 1

𝑓 (𝑥 ) = 230 + 4,30𝑥

Situation 2

𝑔 (𝑥 ) = 𝜋𝑥 2

1.1.3

Situation 1

Input −𝑥 10 15 30 100
Output −𝑓 (𝑥 ) 273 294,50 359 660

Situation 2

Input −𝑥 1 5 7,5 12
Output −𝑔 (𝑥 ) 3,14 78,54 176,71 452,39

,1.1.4

Situation 1

𝑓 (𝑥 ) = 230 + 4,30𝑥

,Situation 2

𝑔 (𝑥 ) = 𝜋𝑥 2

, 1.2.1

The cost of the van can be recognized by the following equation:

Cost = fixed cost + variable cost

Thabo only recognized the variable cost and assumed that the cost is directly proportional
to the number of kilometers.

However, there is a fixed cost of R230 that must always be added. This R230 does not
depend on the number of kilometres. The correct relationship is a non-proportional linear
function.

1.2.2

There is a fixed cost of R230 that is paid no matter how many kilomtres are driven. It stays
the same and must always be added before the number of kilometres are considered.

1.2.3

The number of doughnuts produced is the cost of a van and the flour is the number of
kilometres driven.

We need some fixed oil for the machine which is the R230. Then each doughnut needs
R4,30 for it to be produced.

1.3
Suppose we create dots that form rectangles with the first pattern having one dot.

For the following patterns, we multiply the number of columns by two then we add one
more row below.

The number of columns have a common ratio of 2
The number of rows have a common difference of 1.

𝑛 1 2 3 4
Columns of 1 2 4 8
columns
Number of rows 1 2 3 4

Columns:
Starting from 1, multiply by 2 to get the next term