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Examen

Linear Algebra and Its Applications 4th Edition Solution Manual – Complete Instructor’s Guide by David C. Lay

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This Solution Manual for Linear Algebra and Its Applications, 4th Edition by David C. Lay provides step-by-step solutions to all exercises in the textbook, making it an essential resource for instructors and students alike. Covering key topics such as linear equations, matrix algebra, vector spaces, eigenvalues, orthogonality, and more, this manual simplifies complex concepts with clear explanations and detailed worked-out problems. Perfect for exam preparation, homework help, and self-study, this guide ensures a deep understanding of linear algebra. It includes reduced echelon forms, parametric vector solutions, and applications of linear algebra in real-world scenarios. Whether you're teaching or learning, this manual is your go-to companion for mastering linear algebra

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LINEAR ALGEBRA AND ITS APPLICATIONS
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LINEAR ALGEBRA AND ITS APPLICATIONS

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Subido en
13 de julio de 2025
Número de páginas
706
Escrito en
2024/2025
Tipo
Examen
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INSTRUCTOR’S
SOLUTIONS
MANUAL
THOMAS POLASKI
Winthrop University

JUDITH MCDONALD
Washington State University


L INEAR A LGEBRA AND
I TS APPLICATIONS F OURTH
E DITION

David C. Lay
University of Maryland

,The author and publisher of this book have used their best efforts in preparing this book. These efforts include the
development, research, and testing of the theories and programs to determine their effectiveness. The author and
publisher make no warranty of any kind, expressed or implied, with regard to these programs or the documentation
contained in this book. The author and publisher shall not be liable in any event for incidental or consequential
damages in connection with, or arising out of, the furnishing, performance, or use of these programs.

Reproduced by Pearson Addison-Wesley from electronic files supplied by the author.

Copyright © 2012, 2006, 1997 Pearson Education, Inc.
Publishing as Pearson Addison-Wesley, 75 Arlington Street, Boston, MA 02116.

All rights reserved. No part of this publication may be reproduced, stored in a retrieval system, or transmitted, in any
form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written
permission of the publisher. Printed in the United States of America.

ISBN-13: 978-0-321-38888-9
ISBN-10: 0-321-38888-7

1 2 3 4 5 6 BB 15 14 13 12 11

,Contents
CHAPTER 1 Linear Equations in Linear Algebra 1

CHAPTER 2 Matrix Algebra 87

CHAPTER 3 Determinants 167

CHAPTER 4 Vector Spaces 197

CHAPTER 5 Eigenvalues and Eigenvectors 273

CHAPTER 6 Orthogonality and Least Squares 357

CHAPTER 7 Symmetric Matrices and Quadratic Forms 405

CHAPTER 8 The Geometry of Vector Spaces 453




iii

, 1.1 SOLUTIONS
Notes: The key exercises are 7 (or 11 or 12), 19–22, and 25. For brevity, the symbols R1, R2,…, stand
for row 1 (or equation 1), row 2 (or equation 2), and so on. Additional notes are at the end of the section.

x  5x  7  1 7
1. 2x 1  7 x 2  5 5
5
2 7
1 2  
x1  5x2  7 1 5 7
Replace R2 by R2 + (2)R1 and obtain:  9
3x2  9 0 3 

Scale R2 by 1/3: x1  5x2  7 1 5 7

0 3
x2  3 1
 
x1  8 1 0 8

Replace R1 by R1 + (–5)R2: 0 3
x2  3  1 
The solution is (x1, x2) = (–8, 3), or simply (–8, 3).


3x1  6x2  3 3 6 3
2. 5x  7x  10 5 7 10 
1 2  
 x1  2x2  1 1 2 1
Scale R1 by 1/3 and obtain: 5 7 10
5x  7 x  10

xReplace R1 by R1 +1 (–2)R2:
1  2x 2  1  2 1
 15
3x  15 0 3
Replace R2 by R2 + (–5)R1: 
x1  2x2  1 1 2 1
x  5 0 1 5
Scale R2 by –1/3: 
x1  9 1 0 9
Copyright © 2012 Pearson Education, Inc. Publishing as Addison-Wesley.
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