Solution Manual for Developmental Mathematics: College Mathematics and Introductory Algebra 10th Edition by Marvin Bittinger, Chapter 1 to 15

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INSTRUCTOR’S SOLUTIONS
MANUAL


DEVELOPMENTAL MATHEMATICS:
AP
COLLEGE MATHEMATICS AND
INTRODUCTORY ALGEBRA
TENTH EDITION
LU
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Marvin L. Bittinger
Indiana University Purdue University Indianapolis
01
Judith A. Beecher

, Contents
Chapter 1 . . . . . . . . . . . . . . . . . . . . . . . . . . . 1

Chapter 2 . . . . . . . . . . . . . . . . . . . . . . . . . . 29

Chapter 3 . . . . . . . . . . . . . . . . . . . . . . . . . . 53

Chapter 4 . . . . . . . . . . . . . . . . . . . . . . . . . . 73

Chapter 5 . . . . . . . . . . . . . . . . . . . . . . . . . . 101
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Chapter 6 . . . . . . . . . . . . . . . . . . . . . . . . . . 115

Chapter 7 . . . . . . . . . . . . . . . . . . . . . . . . . . 133

Chapter 8 . . . . . . . . . . . . . . . . . . . . . . . . . . 149

Chapter 9 . . . . . . . . . . . . . . . . . . . . . . . . . . 175
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Chapter 10 . . . . . . . . . . . . . . . . . . . . . . . . . . 209

Chapter 11 . . . . . . . . . . . . . . . . . . . . . . . . . . 231

Chapter 12 . . . . . . . . . . . . . . . . . . . . . . . . . . 257

Chapter 13 . . . . . . . . . . . . . . . . . . . . . . . . . . 291
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Chapter 14 . . . . . . . . . . . . . . . . . . . . . . . . . . 319

Chapter 15 . . . . . . . . . . . . . . . . . . . . . . . . . . 335
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Chapter 1
Whole Numbers
44. 200,017
Exercise Set 1.1 46. 2,793,000,000

RC2. In 615,702, the number 615 is in the thousands period. 48. 32 > 0

RC4. The number 721 is written in standard notation. 50. 28 > 18

CC2. A word name for 42,000,000 is forty-two million. 52. 77 < 117

CC4. A word name for 18,000,000,000 is eighteen billion. 54. 999 > 997
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CC6. A word name for 40,000,000,000,000 is forty trillion. 56. 345 < 456

2. 5 ten thousands 58. 12 < 32

4. 5 hundred thousands 60. 1, 014, 023 > 758, 708, or 758, 708 < 1, 014, 023

6. 9 62. 843, 393 > 842, 583, or 842, 583 < 843, 393
8. 3 64. All digits are 9’s. Answers may vary. For an 8-digit read-
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out, for example, it would be 99,999,999. This number has
10. 6 thousands + 6 hundreds + 8 tens + 8 ones three periods.
12. 1 thousand + 7 hundreds + 8 tens + 6 ones
14. 3 ten thousands + 8 thousands + 4 hundreds + 5 tens + Exercise Set 1.2
3 ones
RC2. In the subtraction 18 − 5 = 13, the number 5 is the
16. 1 hundred thousand + 3 ten thousands + 5 thousands + subtrahend.
0 hundreds + 8 tens + 0 ones, or 1 hundred thousand +
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3 ten thousands + 5 thousands + 8 tens RC4. The distance around an object is its perimeter.
18. 1 billion + 2 hundred millions + 6 ten millions + 6 9 10
millions + 8 hundred thousands + 8 ten thousands + 3 CC2. ✥1✥
0 /0
thousands + 5 hundreds + 9 tens + 8 ones — 7
20. 3 hundred millions + 2 ten millions + 3 millions + 9 hun- 93
dred thousands + 9 ten thousands + 5 thousands + 5
10
hundreds + 2 tens + 8 ones
01
CC4. 1/ /0 0 0
22. Forty-eight − 4 00
6 00
24. Forty-five thousand, nine hundred eighty-seven

1✥0✥0✥/0
9 9 10
26. One hundred eleven thousand, thirteen CC6.
− 9 9 9
28. Forty-three billion, five hundred fifty million, six hundred 1
fifty-one thousand, eight hundred eight
2. 1521
30. Ninety-nine thousand, eight hundred fifty-three
+ 348
32. Two hundred twenty-six million, one thousand, two hun- 1869
dred eighty-eight 1
4. 73
34. 354,702 +69
36. 17,112 1 42
1
38. 19,610,439 6. 7 503
+ 2 683
40. 700,000,000
1 0, 1 8 6
42. 26,000,000,000
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, 2 Chapter 1: Whole Numbers

1
8. 3654 28. 526
+2700 —323
6354 203
1
10. 271 18
6 /8 15
+3338 30. 7/ /9 /5
3609 —3 9 8
1 3 9 7
12. 280
+ 3 4, 9 0 2 10
2 /0 16
3 5, 1 8 2 32. 3/ /1 /6
1 1 1 —2 4 7
14. 4 5, 8 7 9 6 9
+ 2 1, 7 8 6
6 7, 6 6 5 17
7 /7 17
34. 8/ /8 /7
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1 1 1 1
16. 9 9, 9 9 9 —6 9 8
+ 112 1 8 9
1 0 0, 1 1 1
3 12
1 1 1 1
18. 4 2, 4 8 7 36. 3 /4 /2
8 3, 1 4 1 —21 7
+ 3 6, 7 1 2 12 5
1 6 2, 3 4 0
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13 12
5 /3 /2 11
2 2 38. 6/ /4 /3 /1
20. 989 —2 8 9 6
566 3 5 3 5
834
920 12 15
+703 40. 7 /2 /5 14
8/ /3 /6 /4
4 012 —5 3 7 5
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22. Perimeter = 14 mi + 13 mi + 8 mi + 10 mi + 47 mi + 2 9 8 9
22 mi 11 13
We carry out the addition. 42. 8 /1 /3 11
9/ /2 /4 /1
2 —5 6 4 3
14
3 5 9 8
13
6 15
8
7/ /5 8 3
10 44.
01
−3 6 41
47
3 9 42
+22
1 14 11 11
The perimeter of the figure is 114 mi. 46. 5 /1 /1 12
1 /6, /2 /2 /2
24. 90 ft + 90 ft + 90 ft + 90 ft = Perimeter — 5, 8 8 8
1 0, 3 3 4
We carry out the addition.
90 11
90 48. 2 /1 11 8 14
3/ /2, 1/ /9 /4
90 — 2 9, 2 3 6
+90 2 9 5 8
3 60
The batter travels 360 ft when a home run is hit. 8 10
87 50. 9/ /0
26.
—34 —7 8
53 1 2



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