What is a proposition? - correct answer a statement that is either true or false
A compound proposition with 5 propositional variables. The number of rows in its truth table is
(a) 2 × 5 = 10
(b) 2^5 = 32
(c) 5^2 = 25
(d) None of the above - correct answer b
The logic expression p → q means that p cannot be True when q is False.
(a) True
(b) False - correct answer a
Select the converse of p → q
(a) p → q
(b) q → p
(c) ¬p → ¬q
(d) ¬q → ¬p - correct answer b
Which statement is the contrapositive of: "If x = 4, then 3x = 12."
(a) If x = 4 then 3x = 12.
(b) If 3x = 12 then x = 4.
(c) If x /= 4 then 3x /= 12.
(d) If 3x /= 12 then x /= 4 - correct answer d
Which of the followings does NOT have the same meaning of p → q?
, (a) q if p
(b) p is sufficient for q
(c) p is necessary for q
(d) ¬q → ¬p - correct answer a
Identify which line has a mistake in the proof of the theorem: The difference between two odd numbers
is even.
1. Let x and y be two odd integers. We shall show that x − y is even.
2. Since x is odd, then x = 2k + 1 for some integer k. Since y is odd, then y = 2j + 1 for some integer j.
3. Let x − y = (2k + 1) − (2j + 1).
4. Since x−y is two times an integer, then x−y is even.
(a) Line 1
(b) Line 2
(c) Line 3
(d) Line 4 - correct answer c
m = 8 is an even integer since 8 = 2 · 4. m^2 = 8^2 = 64 is an even integer since 64 = 2 · 32. Therefore if n
is an even integer, then n2 is also an even integer. - correct answer "Generalizing from examples"
If n is an odd integer, then n = 2k+1 for some integer k. Therefore n^2 = (2k+1)^2 and n^2 is odd. -
correct answer "Skipping steps"
If n is an odd integer, then n = 2k+1 for some integer k. Let n^2 = 2j + 1 for some integer j. Since n^2 is
equal to two times an integer plus 1, then n^2 is odd. - correct answer "Circular reasoning"
Suppose r is a rational number. The product of any two rational numbers is rational. Therefore r^2 = r · r
is also rational. - correct answer "Assuming facts that have not yet been proven"