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Summary Year 12 Standard 2 Maths Guide – All Topics Explained

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This is a comprehensive, high-quality set of notes for Mathematics Standard 2 (Year 12 HSC) based on the Cambridge textbook. It covers all syllabus topics in detail, including clear explanations, worked examples, formulas, and key definitions. Perfect for students preparing for assessments, trials, and the final HSC exam. Whether you're revising or catching up on missed lessons, this resource is designed to make Standard 2 Maths easier to understand and more approachable.

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Subido en
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Chapter 1 Rates and Ratios
1A Rates and Concentrations

Converting a rate

1.​ Write the rate as a fraction. First quantity is the numerator and 1 is the denominator.
2.​ Convert the first amount to the required unit.
3.​ Convert the second amount to the required unit.
4.​ Simplify the fraction

E.g. ​ 55200 m/h to m/min
​ 55200/60​​
920m/min

Unitary Method

1.​ Find one unit quantity by dividing the amount
2.​ Multiply the result to solve the problem

E.g. ​ A car travels 240 km on 30L of petrol. How far does it travel on 7L
30L = 240km
​ = 240 ÷ 30 x 7
​ = 56km

Speed




Distance = speed X time
Speed= Distance / Time
Time= Distance / speed


1B Heart Rate

Maximum Heart Rate MHR= 220 - Age


1C Energy Rate

,1kW = 1000W

E.g find the cost of a 200W television for 20 hours at $0.21/kWh
0.2kW × 20hrs = 4 kWh
Cost = 4 × 0.21 = $0.84

1D Fuel Consumption Rate
Fuel consumption = ​Amount of fuel (L) × 100
Distance travelled

E.g. A car travelled 850 km using 78.2 L of petrol, what was the fuel consumption
78.2 x 100 = 9.2L/100km
​ 850


1E Calculations with Ratios

Equivalent ratios are found by multiplying or dividing by the same number




1F Dividing a Quantity into a Given Ratio

Divides each amount in the Ratio by the total number of parts.

E.g. Mikhail and Ilya were given $450 to share in the ratio 4:5. How much did each get?

1.​ Calculate the total number of parts by adding each amount in the ratio (4 + 5) = 9
2.​ Divide the quantity ($450) by the total number of parts (9 parts) to determine the value of
one part. (450 ÷ 9 = $50)
3.​ Multiply each amount of the ratio by $50 (50X4 -- mikhail, 50X5 -- illya)
4.​ Mikhail got $200, Ilya got $250

,1G Scale Drawings

Scale of a drawing = Drawing length : Actual length

A scale drawing has a scale of 1:50.
Find the actual length if the drawing length is 30mm. Answer to the nearest centimetre
Find the drawing length if the actual length is 4.5m. Answer to the nearest millimetre.

1.​ Multiply the drawing length by 50 to determine the actual length.
2.​ Divide by 10 to change millimetres to centimetres.
3.​ Divide the actual length by 50 to determine the drawing length.
4.​ Multiply by 1000 to change metres to millimetres.

Actual length = 30 × 50 mm = 1500 mm
= 150 cm
Drawing length = 4.5 ÷ 50 m = 0.09 m
​ ​ = 90 mm


1H Plans & Elevations

A plan is a view of an object from the top.
An elevation is a view of an object from one side, such as a front elevation or side elevation.


1I Perimeter, Area & Volume

Perimeter:​to calculate the perimeter of land, multiply the length on the aerial photograph by the
scale.
Area:​to estimate the area of land, divide it into square grids and count the number of squares.
Volume:​If water covers an area (such as the bottom of a pool), to a constant depth, its
volume can be calculated using V = Ah
Trapezoidal rule:

, 2D Shapes – Area Formulas
Shape Formula Variables

Square A = s² s = side length

Rectangle A=l×w l = length, w = width

Triangle A=½×b×h b = base, h = height

Circle A = π × r² r = radius

Semicircle A = ½ × π × r² r = radius

Trapezoid A = ½ × (a + b) × h a, b = bases, h =
height

Parallelogram A=b×h b = base, h = height




3D Shapes – Volume and Surface Area Formulas
Shape Volume Surface Area Variables
Formula Formula

Cube V = s³ SA = 6 × s² s = side length

Rectangular V=l×w×h SA = 2(lw + lh + l = length, w = width, h = height
Prism wh)

Cylinder V = π × r² × h SA = 2πr²+2πrh r = radius, h = height

Sphere V = ⁴⁄₃ × π × r³ SA = 4π × r² r = radius

Hemisphere V = ²⁄₃ × π × r³ SA = 3π × r² r = radius
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