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Examen

Solutions for Elementary Algebra: Graphs and Authentic Applications, 3rd edition by Lehmann

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Vista previa 4 fuera de 440 páginas

Solutions for Elementary Algebra: Graphs and Authentic Applications, 3rd edition by Lehmann

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SOLUTIONS for
TU

Elementary Algebra: Graphs and
Authentic Applications, 3rd edition
Author (s): Jay Lehmann
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A
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, Chapter 1
Introduction to Modeling
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Homework 1.1 b. In the described situation, the symbols W
and L are variables. Their values can
2. In 2015, Chris Davis hit 47 home runs. change.
4. In 2017, about 60 percent of children aged 5– c. In the described situation, the symbol A is
18 participated in organized physical activity. a constant. Its value is fixed at 36 square
inches.
6. In 2015, 11.1 percent of American workers
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were in unions. 24. a. Answers may vary. Example:

8. The temperature is −10°F . That is the
temperature is 10 degrees below 0 (in 4 inches
Fahrenheit).
4 inches
A
10. The statement t = 13 represents the year 2018
(13 years after 2005). 3 inches

12. The statement t = −2 represents the year 2008 5 inches
(2 years before 2010). 2 inches
A
14. Answers may vary. Example: 6 inches
Let t be the amount of time (in hours) that a
b. In the described situation, the symbols W
student prepares for an exam. Then t can
and L are variables. Their values can
represent the numbers 0 and 4, but t cannot
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change.
represent the numbers −1 and −3 .
c. In the described situation, the symbol P is
16. Answers may vary. Example:
a constant. Its value is fixed at 16 feet.
Let n be the number of students enrolled in an
algebra class. Then n can represent the 26. a. Answers may vary. Example:
numbers 15 and 28, but n cannot represent the
numbers −20 and 0.5. 1 inch 2 inches
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2 inches
4 inches
18. Answers may vary. Example:
Let T be the temperature (in degrees
3 inches
Fahrenheit) in an oven. Then T can represent
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the numbers 300 and 450, but T cannot 6 inches
represent the numbers −300 and −450 .
b. In the described situation, the symbols W,
20. Answers may vary. Example: L, and A are all variables. All of their
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Let v be the value (in thousands of dollars) of values can change.
a new home. Then v can represent the numbers
100 and 250, but v cannot represent the c. In the described situation, none of the
numbers −100 and −250 . symbols are constants. All of their values
can change.
22. a. Answers may vary. Example:
28. a. Answers may vary. Example:
4 inches
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5 cm 5 cm
9 inches
5 cm 7 cm
3 inches
12 inches 5 cm
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2 inches 10 cm
18 inches


Copyright © 2019 Pearson Education, Inc.

, 2 ISM: Elementary Algebra

b. In the described situation, the symbols L 3
and A are variables. Their values can 50. The real numbers in the list are −9.7, −4, 0, ,
5
change.
7, 3, and π .
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c. In the described situation, the symbol W is
a constant. Its value is fixed at 5 cm. 52. Answers may vary. Example: 1, 5, and 12

30. 54. Answers may vary. Example: −1, −2, and −3
−8−7−6−5−4−3−2−1 0 1 2 3 4 5 6 7 8
1 3 7
56. Answers may vary. Example: , , and
32. −5 1 9 2 4 9
4 4 4
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58. Answers may vary. Example: 2, 5, and π

−3 −2 −1 0 1 2 3 60. Answers may vary. Example: 2, 5, and π
34. 0.9 1.5 2.3 2.7 3.4
2 + 0 + 1 + 5 + 4 12
62. = = 2.4
A
5 5
0 1 2 3 4 The average number of songs downloaded per
visit is 2.4 songs.
36. −2.4 −0.7 0.2 0.9
Average:
2.4 songs
A
−3 −2 −1 0 1 2
n
38. The counting numbers between 1 and 5 are 2, 0 1 2 3 4 5
3, and 4. Number of songs
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79 + 82 + 75 + 77 + 76 389
1 2 3 4 5 64. = = 77.8
5 5
40. The integers between −4 and 4, inclusive, are The average percentage of flights in a year that
−4, − 3, − 2, − 1, 0, 1, 2, 3, and 4. are on time is 77.8% per year.
Average:
77.8%
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−5 −4 −3 −2 −1 0 1 2 3 4 5

42. The integers between −6 and 3, inclusive, are p
−6, − 5, − 4, − 3, − 2, − 1, 0, 1, 2, and 3. 73 74 75 76 77 78 79 80 81 82 83
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Percent
−7 −6 −5 −4 −3 −2 −1 0 1 2 3 4 66. c
1.6 1.7 1.8 1.9 2.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7
44. The positive integers between −4 and 4 are 1,
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2, and 3. Per person consumption

68. −5 3
0 1 2 3 4

46. The integers in the list are −4, 0, and 3. p
−10 −8 −6 −4 −2 0 2 4 6
48. The rational numbers in the list are Annual profit (in millions)
3
D
−9.7, −4, 0, , and 3.
5
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Copyright © 2019 Pearson Education, Inc.

, Chapter 1: Introduction to Modeling 3

6.1 + 7.2 + 7.6 + 7.7 28.6 74. No. Answers may vary. Example:
70. a. = = 7.15 The numbers 2 and 5 are not “between 2 and
4 4
The average sales are about $7.15 million 5.” The numbers between 2 and 5 are simply 3
and 4.
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per year.
76. Two consecutive integers are 1 unit apart on
the number line.
Two consecutive even integers are 2 units
apart on the number line.
Two consecutive odd integers are 2 units apart
on the number line.
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78. Answers may vary. Example:
b. Car sales increased from 2011 to 2014. 90 points; the fifth score did not change the
Sales went up each year. average, so it must be the same as the average.

c. The increases in car sales decreased from 80. Answers may vary. Example:
2011 to 2014. The decreases were: Negative quantities are graphed to the left of 0
on the number line.
A
Years Decrease
2011 to 2012 7.2 − 6.1 = 1.1 Homework 1.2
2012 to 2013 7.6 − 7.2 = 0.4 2–16 even. y

2013 to 2014 7.7 − 7.6 = 0.1 5
(−1, 3) (2, 3)
A
(−3.5, 1.5) (1, 0)
1 + 7 + 19 + 67 + 276 370 x
72. a. = = 74
5 5 −5 5
(−5,−2)
The average number of cities where Uber
(3,−4)
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operates is about 74. (−2.4,−4.1)
−5
(0,−4)

18. The y-coordinate is −4 .
20. Presumably, the longer a person works for a
company, the higher his or her salary will be.
So, the salary s depends on the number of
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years t. Thus, t is the explanatory variable and
s is the response variable.
22. As a student’s GPA increases, the percentage
of college that would accept him or her would
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increase. So, the percentage p depends on the
b. The number of cities where Uber operates GPA g. Thus, g is the explanatory variable and
increased from 2010 to 2014. The number p is the response variable.
of cities where Uber operates went up each
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year. 24. As the age of men increases, the percentage
with gray hair also increases. So, the
c. The increases in the number of cities where percentage p depends on the age a. Thus, a is
Uber operates increased from 2010 to the explanatory variable and p is the response
2014. The increases were variable.
Years Increase 26. The longer the potato has been out of the oven,
2010 to 2011 7 −1 = 6 the cooler it will be (until it is cooled
D
2011 to 2012 19 − 7 = 8 completely). So, the temperature of the potato
F depends on the number of minutes t since it
2012 to 2013 67 − 19 = 48 was removed from the oven. Thus, t is the
2013 to 2014 276 − 67 = 209 explanatory variable and F is the response
variable.
?

Copyright © 2019 Pearson Education, Inc.

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Subido en
24 de marzo de 2025
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Escrito en
2024/2025
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