Phys 165 Module 9 Exam
A 15.Zero-cm diameter coil of cord is inner a zero.521-T magnetic discipline. What Emf is
prompted whilst it stays stationary for 15.0 s? - ANS-*No Emf is brought about* on this cord on
the grounds that there's no exchange to create the Emf since it stays desk bound.
A charged item movements at 475 m/s to the South via a magnetic subject of one.42 T, that's
directed to the East. If the fee of the item is +12.5 nC, what's the significance and direction of
the magnetic force appearing on the object? - ANS-Given: v= 475m/s , B= 1.Forty two, q= 1.42
wherein magnetic discipline directed east and object transferring south = 90deg
F= 90)
F= q(V x B)
= Q V x B Sin Ө
= (12.5x10^-9) x (475) x (1.Forty two) Sin(90)
F= 8.43125x10^-6
*F= eight.43 x10^-6 N [inwards]*
RHR states pressure is Up (?)
A long instantly cord contains a present day of 760 mA straight down. The area that is created
through this modern is being examined at point A, that is to the North of the wire. The energy of
the magnetic area is zero.357 µT at factor A. How a ways faraway from the wire is point A, and
in which path is the magnetic area? - ANS-r= (Mew)oI/2𝛑B
(Mew)o = 4𝛑x10^-7N/A^2 and B = three.57x10^-7 T
r= (4𝛑x10^-7) x (760x10^-3) / (2𝛑) x (zero.357x10^-6)
r= (2x10^-7) x (760x10^-three) / (zero.357x10^-6)
r= zero.4257703081
*r= 0.426 m*
A square loop of twine this is five.0 cm throughout actions into a vicinity of space in which the
magnetic area has a value of zero.20 T, as proven in Figure nine.T.1. The loop is pulled with the
aid of a few unseen force at a steady pace of 80.Zero m/s, as shown within the diagram.
Answer the following questions about this situation.
A. Calculate the Emf brought on inside the loop because it moves from a vicinity wherein there's
no magnetic discipline into the magnetic discipline proven.
B. In which route is the Emf induced inside the loop because it enters the magnetic discipline?
(clockwise or counter-clockwise)
c. In which path does conventional modern waft through the pinnacle horizontal segment of the
loop? (proper to left or left to proper)
A 15.Zero-cm diameter coil of cord is inner a zero.521-T magnetic discipline. What Emf is
prompted whilst it stays stationary for 15.0 s? - ANS-*No Emf is brought about* on this cord on
the grounds that there's no exchange to create the Emf since it stays desk bound.
A charged item movements at 475 m/s to the South via a magnetic subject of one.42 T, that's
directed to the East. If the fee of the item is +12.5 nC, what's the significance and direction of
the magnetic force appearing on the object? - ANS-Given: v= 475m/s , B= 1.Forty two, q= 1.42
wherein magnetic discipline directed east and object transferring south = 90deg
F= 90)
F= q(V x B)
= Q V x B Sin Ө
= (12.5x10^-9) x (475) x (1.Forty two) Sin(90)
F= 8.43125x10^-6
*F= eight.43 x10^-6 N [inwards]*
RHR states pressure is Up (?)
A long instantly cord contains a present day of 760 mA straight down. The area that is created
through this modern is being examined at point A, that is to the North of the wire. The energy of
the magnetic area is zero.357 µT at factor A. How a ways faraway from the wire is point A, and
in which path is the magnetic area? - ANS-r= (Mew)oI/2𝛑B
(Mew)o = 4𝛑x10^-7N/A^2 and B = three.57x10^-7 T
r= (4𝛑x10^-7) x (760x10^-3) / (2𝛑) x (zero.357x10^-6)
r= (2x10^-7) x (760x10^-three) / (zero.357x10^-6)
r= zero.4257703081
*r= 0.426 m*
A square loop of twine this is five.0 cm throughout actions into a vicinity of space in which the
magnetic area has a value of zero.20 T, as proven in Figure nine.T.1. The loop is pulled with the
aid of a few unseen force at a steady pace of 80.Zero m/s, as shown within the diagram.
Answer the following questions about this situation.
A. Calculate the Emf brought on inside the loop because it moves from a vicinity wherein there's
no magnetic discipline into the magnetic discipline proven.
B. In which route is the Emf induced inside the loop because it enters the magnetic discipline?
(clockwise or counter-clockwise)
c. In which path does conventional modern waft through the pinnacle horizontal segment of the
loop? (proper to left or left to proper)
