ASSIGNMENT 12025
UNIQUE NO.
DUE DATE: 2025
, MAT1514
Assignment 1 2025
Unique No.
Due Date: 2025
Precalculus (Engineering)
Question 1
Given functions:
f(x)=3x2−4x+7f(x) = 3x^2 - 4x + 7f(x)=3x2−4x+7 g(x)=x2+1g(x) = x^2 + 1g(x)=x2+1
1. (g ∘ f)(x)
This represents the composition g(f(x))g(f(x))g(f(x)), meaning we substitute f(x)f(x)f(x)
into g(x)g(x)g(x):
g(f(x))=g(3x2−4x+7)g(f(x)) = g(3x^2 - 4x + 7)g(f(x))=g(3x2−4x+7)
Since g(x)=x2+1g(x) = x^2 + 1g(x)=x2+1, we replace xxx in g(x)g(x)g(x) with f(x)f(x)f(x):
g(f(x))=(3x2−4x+7)2+1g(f(x)) = (3x^2 - 4x + 7)^2 + 1g(f(x))=(3x2−4x+7)2+1
Expanding (3x2−4x+7)2(3x^2 - 4x + 7)^2(3x2−4x+7)2:
(3x2−4x+7)(3x2−4x+7)(3x^2 - 4x + 7)(3x^2 - 4x + 7)(3x2−4x+7)(3x2−4x+7)
Using the expansion (a+b+c)2=a2+b2+c2+2ab+2ac+2bc(a+b+c)^2 = a^2 + b^2 + c^2 +
2ab + 2ac + 2bc(a+b+c)2=a2+b2+c2+2ab+2ac+2bc:
(3x2)2+(−4x)2+(7)2+2(3x2)(−4x)+2(3x2)(7)+2(−4x)(7)(3x^2)^2 + (-4x)^2 + (7)^2 +
2(3x^2)(-4x) + 2(3x^2)(7) + 2(-