TEST BANK
Thomas' Calculus Early
Transcendentals, 15th Edition by
George B. Thomas
Complete Chapter Test Bank
are included (Ch 1 to 16)
** Immediate Download
** Swift Response
,Table of Contents are given below
1.Functions
2.Limits and Continuity
3.Derivatives
4.Applications of Derivatives
5.Integrals
6.Applications of Definite Integrals
7.Integrals and Transcendental Functions
8.Techniques of Integration
9.First-Order Differential Equations
10.Infinite Sequences and Series
11.Parametric Equations and Polar Coordinates
12.Vectors and the Geometry of Space
13.Vector-Valued Functions and Motion in Space
14.Partial Derivatives
15.Multiple Integrals
16.Integrals and Vector Fields
,The test bank is organized in reverse order, with the last chapter displayed first, to ensure that all chapters are included in this
document. (Complete Chapters included Ch16-1)
Exam
Name___________________________________
Chapter 16 15e
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Match the vector equation with the correct graph.
1) r(t) = 3i - 2j - tk; -1 ≤ t ≤ 1 1)
A) Figure 3 B) Figure 8 C) Figure 6 D) Figure 5
2) r(t) = 2 cos ti + sin tk; 0 ≤ t ≤ π 2)
A) Figure 6 B) Figure 7 C) Figure 4 D) Figure 2
3) r(t) = (3 - 2t)i + tj; 0 ≤ t ≤ 3 3)
2
A) Figure 1 B) Figure 3 C) Figure 8 D) Figure 5
4) r(t) = (1 - t2)j + 3tk; -1 ≤ t ≤ 1 4)
A) Figure 2 B) Figure 7 C) Figure 8 D) Figure 4
1
, 5) r(t) = tj; -2 ≤ t ≤ 2 Chapter 16 15e 5)
A) Figure 1 B) Figure 6 C) Figure 5 D) Figure 3
6) r(t) = sin tj - cos tk; 0 ≤ t ≤ π 6)
2
A) Figure 2 B) Figure 1 C) Figure 4 D) Figure 7
7) r(t) = 3 ti +(2 - t)k; 0 ≤ t ≤ 2 7)
2
A) Figure 1 B) Figure 8 C) Figure 5 D) Figure 3
8) r(t) = -3ti + 2tj + 2tk; 0 ≤ t ≤ 1 8)
A) Figure 5 B) Figure 1 C) Figure 8 D) Figure 3
Evaluate the line integral along the curve C.
9) ∫ y + z ds , C is the straight-line segment x = 0, y = 3 - t, z = t from (0, 3, 0) to (0, 0, 3) 9)
C
9
A) 9 2 B) C) 9 D) 0
2
x+y+z 4 4 5
10) ∫ 5
ds , C is the curve r(t) = 3ti + (5 cos t)j + (5 sin t)k , 0 ≤ t ≤ π
5 5 4
10)
C
75 2 25 75 2 75 25 75
A) π + B) π + 25 C) + D) π
32 2 32 32 2 32
11) ∫ (xz + y 2) ds, C is the curve r(t) = (-9 - t)i + 2tj - 2tk , 0 ≤ t ≤ 1 11)
C
A) - 21 B) 33 C) 11 D) - 7
4 3/5
12) ∫ z
ds , C is the curve r(t) = (4t5 cos t)i + (4t5 sin t)j + 4t5k , 0 ≤ t ≤ 5 2 12)
C
1000 500 1000
A) (4 + 2) B) (4 - 2) C) (4 - 2) D) 0
3 3 3
13) ∫ y + z ds , C is the path from (0, 0, 0) to (-4, 4, 1) given by: 13)
C
C1: r(t) = -4t2i + 4tj, 0 ≤ t ≤ 1
C2: r(t) = -4i + 4j + (t-1)k, 1 ≤ t ≤ 2
41 20 19 20 19 25
A) 2 B) 3 5+ C) 3 5- D) 12
6 6
2
Thomas' Calculus Early
Transcendentals, 15th Edition by
George B. Thomas
Complete Chapter Test Bank
are included (Ch 1 to 16)
** Immediate Download
** Swift Response
,Table of Contents are given below
1.Functions
2.Limits and Continuity
3.Derivatives
4.Applications of Derivatives
5.Integrals
6.Applications of Definite Integrals
7.Integrals and Transcendental Functions
8.Techniques of Integration
9.First-Order Differential Equations
10.Infinite Sequences and Series
11.Parametric Equations and Polar Coordinates
12.Vectors and the Geometry of Space
13.Vector-Valued Functions and Motion in Space
14.Partial Derivatives
15.Multiple Integrals
16.Integrals and Vector Fields
,The test bank is organized in reverse order, with the last chapter displayed first, to ensure that all chapters are included in this
document. (Complete Chapters included Ch16-1)
Exam
Name___________________________________
Chapter 16 15e
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Match the vector equation with the correct graph.
1) r(t) = 3i - 2j - tk; -1 ≤ t ≤ 1 1)
A) Figure 3 B) Figure 8 C) Figure 6 D) Figure 5
2) r(t) = 2 cos ti + sin tk; 0 ≤ t ≤ π 2)
A) Figure 6 B) Figure 7 C) Figure 4 D) Figure 2
3) r(t) = (3 - 2t)i + tj; 0 ≤ t ≤ 3 3)
2
A) Figure 1 B) Figure 3 C) Figure 8 D) Figure 5
4) r(t) = (1 - t2)j + 3tk; -1 ≤ t ≤ 1 4)
A) Figure 2 B) Figure 7 C) Figure 8 D) Figure 4
1
, 5) r(t) = tj; -2 ≤ t ≤ 2 Chapter 16 15e 5)
A) Figure 1 B) Figure 6 C) Figure 5 D) Figure 3
6) r(t) = sin tj - cos tk; 0 ≤ t ≤ π 6)
2
A) Figure 2 B) Figure 1 C) Figure 4 D) Figure 7
7) r(t) = 3 ti +(2 - t)k; 0 ≤ t ≤ 2 7)
2
A) Figure 1 B) Figure 8 C) Figure 5 D) Figure 3
8) r(t) = -3ti + 2tj + 2tk; 0 ≤ t ≤ 1 8)
A) Figure 5 B) Figure 1 C) Figure 8 D) Figure 3
Evaluate the line integral along the curve C.
9) ∫ y + z ds , C is the straight-line segment x = 0, y = 3 - t, z = t from (0, 3, 0) to (0, 0, 3) 9)
C
9
A) 9 2 B) C) 9 D) 0
2
x+y+z 4 4 5
10) ∫ 5
ds , C is the curve r(t) = 3ti + (5 cos t)j + (5 sin t)k , 0 ≤ t ≤ π
5 5 4
10)
C
75 2 25 75 2 75 25 75
A) π + B) π + 25 C) + D) π
32 2 32 32 2 32
11) ∫ (xz + y 2) ds, C is the curve r(t) = (-9 - t)i + 2tj - 2tk , 0 ≤ t ≤ 1 11)
C
A) - 21 B) 33 C) 11 D) - 7
4 3/5
12) ∫ z
ds , C is the curve r(t) = (4t5 cos t)i + (4t5 sin t)j + 4t5k , 0 ≤ t ≤ 5 2 12)
C
1000 500 1000
A) (4 + 2) B) (4 - 2) C) (4 - 2) D) 0
3 3 3
13) ∫ y + z ds , C is the path from (0, 0, 0) to (-4, 4, 1) given by: 13)
C
C1: r(t) = -4t2i + 4tj, 0 ≤ t ≤ 1
C2: r(t) = -4i + 4j + (t-1)k, 1 ≤ t ≤ 2
41 20 19 20 19 25
A) 2 B) 3 5+ C) 3 5- D) 12
6 6
2
