We use INSTRUMENTAL !
Chapter 1: Units ,
Trig 3 , vectors !
↓ 5128/24
>
Significant Figures : assuming it comes from an
2x103 I sig fig :
.
instrument (instrumental approach)
figs
3
2 QQQ :
4
Sig .
Think that there is an instrument that could
measure that accurately ! (powers of 10
02004 :
. 4
sig .
figs * More for X do not count )
!
LAB !
2x104 : I sig fig .
* Theoretical approach : 2000 >
-
1
sig fig
For should have least amount
sig figs
multiplication of !
·
:
solution .
M = 3 1415
.
< T ·
2 -
103 =
6x103 ONE SIG FIG
Multiplying by constant does not change the number of
sig figs in
·
a
the result !
> Vectors :
3
>
"3
-
Y
O
A : : units in X direction"
3- ·
B :
2Y :
"a units in
y
direction"
2x * / unit vectors :
1
· 2x3 "2 units in
-
:
direction + Sunits
i2X
:
x
in y direction"
~
You can NEVER mix the * w/ Y !
:
Ex
1
* Book notation :
m + B = 3X +
y Y = T Y =
J
·
Analytical Addition/Subtraction of Vectors :
Ex : = -
SY -
6Y
a
- x 2)
=
-
7X -
2Y
i a - =
2 -
4y :
( -
Sy -
Gπ) -
Ex ::
2x +
34 a -
5 + E - : -
64 + 154
-
1
X 2y
-
2x +
14
: 5x
1
3y
-
a + 5 + 2+ :
6Y +
SY
, ·
Graphical Method of Addition / Subtraction of Vectors :
*
* T
A v (STEP1))
A
7
·
SOLUTION !
1) More one vector to the tip of the other vector !
* Can NOT
change the size or inclination of the vector!
-
> Count squares to ensure ACCURACY !!
2) Join Origin (0 0) , with tip of translated vector !
* You can use analytical method to check:
>
Analytically !
-
: 3Y
3
Creck
SAME RESULT ! a 3x Y
= -
a +5 :
5y 5 =
2x +
34
1
* FOR SUBTRACTION :
5 1 5 - =
Y -
4y
>
-
a
1
S
a - 5 =
? Solution !
~
·
X 1) You just join the tip of
one vector w/ tip of other
Vector .
2) Tip of arrow faces from
-
b to a
, Subtraction
~
w/3 Vectors :
M 1 a -
5 -
5 =
?
↓ Solution
·
6x 74
↓
-
1) Subtract first 2 vectors like
normal .
# 2) More that solution to the
origin properly.
3) Repeat subtraction steps by
(Completes HW 1 Material) 2 tips.
joining
~
Vectors :
-
a = 3x + 24
2 -Magnitude : 1)
la)
=
=
3 + 22 Pythagorean
13
Theoryis
i' 27 11 =
3 6
.
-
Magn .
Formula:
|| =
a2x + a
?
11
15) = 22 + 22 -
=
8 = 2 8 .
] * Can't
get a
neg .
magnitude bic of
squaring !!
-
Orientation Direction : The
angle with respect to the horizontal !
!
tan) Sinopposite *Cos
SOHCAHTOA
hypotenuse
*
T
magnitude Oy : Adjacent tan : Opposita
O Copposite)
an (5)
↓ =+
ax
Hyp Adjacent
ladjacent)
0 =
33 . 70
, ~
In Physics most of the time you have the O and the Hypotenuse !
hypotenuse ay
SinO =
Opposite
hypotenuse
=
Ay
hyp
O F Ay =
Hyp xSin8
aX
Ay = 3 . 605xSin (33 . 6)
Ay =
1 995
.
!!
* Normally you will be asked to solve for Ax or My !
COSO
as
Solve for ax ? =A
= hyp
Cos (33 . 6) ·
3 605 .
= Ax
Ax =
3 00 .
Chapter 2 : Motion in One Dimension : Only happens in or Y or
-
Object is
moving only in Y or only in Y !
~
Displacement : total distance advanced * =
* -
2 x
a =
C =. 5x :
Displacement ZERO ! =
+ 3 S -
=
0 0 =
Displacement
=
a =
y 5 3x5
= =
2x
a + 5 + E x 3 = + +
2x = GX =
Displacement
* Displacement is a VECTOR !!
Distance of displacement
~
Magnitude
:
Distance 1212 *Typical unit meters (m)
62
=
is
X +
y
= =
6
[meters] =
[m] SI (MKS(
~
Velocity : - :
Vector velocity >
"Average Speed" VECTOR
15) :
speed >
"Average speed" Not Vector
Also, Instantaneous Velocity Instantaneous Speed At
specific
·
+
-
point !
distance
1%1 : Speed :
&X =
time
= 6m = 3 M/S : "meters per second"
Or "V" 2S
Chapter 1: Units ,
Trig 3 , vectors !
↓ 5128/24
>
Significant Figures : assuming it comes from an
2x103 I sig fig :
.
instrument (instrumental approach)
figs
3
2 QQQ :
4
Sig .
Think that there is an instrument that could
measure that accurately ! (powers of 10
02004 :
. 4
sig .
figs * More for X do not count )
!
LAB !
2x104 : I sig fig .
* Theoretical approach : 2000 >
-
1
sig fig
For should have least amount
sig figs
multiplication of !
·
:
solution .
M = 3 1415
.
< T ·
2 -
103 =
6x103 ONE SIG FIG
Multiplying by constant does not change the number of
sig figs in
·
a
the result !
> Vectors :
3
>
"3
-
Y
O
A : : units in X direction"
3- ·
B :
2Y :
"a units in
y
direction"
2x * / unit vectors :
1
· 2x3 "2 units in
-
:
direction + Sunits
i2X
:
x
in y direction"
~
You can NEVER mix the * w/ Y !
:
Ex
1
* Book notation :
m + B = 3X +
y Y = T Y =
J
·
Analytical Addition/Subtraction of Vectors :
Ex : = -
SY -
6Y
a
- x 2)
=
-
7X -
2Y
i a - =
2 -
4y :
( -
Sy -
Gπ) -
Ex ::
2x +
34 a -
5 + E - : -
64 + 154
-
1
X 2y
-
2x +
14
: 5x
1
3y
-
a + 5 + 2+ :
6Y +
SY
, ·
Graphical Method of Addition / Subtraction of Vectors :
*
* T
A v (STEP1))
A
7
·
SOLUTION !
1) More one vector to the tip of the other vector !
* Can NOT
change the size or inclination of the vector!
-
> Count squares to ensure ACCURACY !!
2) Join Origin (0 0) , with tip of translated vector !
* You can use analytical method to check:
>
Analytically !
-
: 3Y
3
Creck
SAME RESULT ! a 3x Y
= -
a +5 :
5y 5 =
2x +
34
1
* FOR SUBTRACTION :
5 1 5 - =
Y -
4y
>
-
a
1
S
a - 5 =
? Solution !
~
·
X 1) You just join the tip of
one vector w/ tip of other
Vector .
2) Tip of arrow faces from
-
b to a
, Subtraction
~
w/3 Vectors :
M 1 a -
5 -
5 =
?
↓ Solution
·
6x 74
↓
-
1) Subtract first 2 vectors like
normal .
# 2) More that solution to the
origin properly.
3) Repeat subtraction steps by
(Completes HW 1 Material) 2 tips.
joining
~
Vectors :
-
a = 3x + 24
2 -Magnitude : 1)
la)
=
=
3 + 22 Pythagorean
13
Theoryis
i' 27 11 =
3 6
.
-
Magn .
Formula:
|| =
a2x + a
?
11
15) = 22 + 22 -
=
8 = 2 8 .
] * Can't
get a
neg .
magnitude bic of
squaring !!
-
Orientation Direction : The
angle with respect to the horizontal !
!
tan) Sinopposite *Cos
SOHCAHTOA
hypotenuse
*
T
magnitude Oy : Adjacent tan : Opposita
O Copposite)
an (5)
↓ =+
ax
Hyp Adjacent
ladjacent)
0 =
33 . 70
, ~
In Physics most of the time you have the O and the Hypotenuse !
hypotenuse ay
SinO =
Opposite
hypotenuse
=
Ay
hyp
O F Ay =
Hyp xSin8
aX
Ay = 3 . 605xSin (33 . 6)
Ay =
1 995
.
!!
* Normally you will be asked to solve for Ax or My !
COSO
as
Solve for ax ? =A
= hyp
Cos (33 . 6) ·
3 605 .
= Ax
Ax =
3 00 .
Chapter 2 : Motion in One Dimension : Only happens in or Y or
-
Object is
moving only in Y or only in Y !
~
Displacement : total distance advanced * =
* -
2 x
a =
C =. 5x :
Displacement ZERO ! =
+ 3 S -
=
0 0 =
Displacement
=
a =
y 5 3x5
= =
2x
a + 5 + E x 3 = + +
2x = GX =
Displacement
* Displacement is a VECTOR !!
Distance of displacement
~
Magnitude
:
Distance 1212 *Typical unit meters (m)
62
=
is
X +
y
= =
6
[meters] =
[m] SI (MKS(
~
Velocity : - :
Vector velocity >
"Average Speed" VECTOR
15) :
speed >
"Average speed" Not Vector
Also, Instantaneous Velocity Instantaneous Speed At
specific
·
+
-
point !
distance
1%1 : Speed :
&X =
time
= 6m = 3 M/S : "meters per second"
Or "V" 2S