RIO SALADO physics 112 midterm Questions With
Complete Solutions
A 1.5V battery connects to a 10 ohm resistor. The power
dissipated by the resistor is Correct Answers P=V^2/R
P=1.5^2/10
P=0.23 W
a 9.0 Vbattery connects to a wire resistor. The wire resistor is
tungsten (resistor 5.6x10^-8) 0.5m long has a radius of 1.2x10^-
5m. What is the current through the resistor Correct Answers
0.15 A
A battery connects to a resistor with resistance R and the
resulting current is measured. The resistor is removed and a new
resistor with a resistance of 2R is added. As a result Correct
Answers the voltage will double
the current will double
the charge speed will double
none of the above will options are correct!!
a battery connects to a resistor. The rate of energy dissipated by
the resistor is 1.44 W The rate of energy supplied by the battery
is Correct Answers equal to 1.44 W
A battery with a potential difference of V connects to a resistor,
and the resulting current is measured. You remove the battery,
and a new battery with a potential difference of 2Vis put in its
place. As a result Correct Answers the current will double
,A battery with an emf of 12V connects in parallel to a 50 ohm
and 25 ohm resistor. The current through the battery is 0.70 A.
What is the internal resistance of the battery Correct Answers
50 x+25 +16.6
E=I(Req +r)
12=0.7(16.6 +r)
12=11.66 +0.7r
0.333=0.7r
0.54 ohm
A charged particle moving to the right enters a uniform
magnetic field directed into the page. The charged particle
experiences a magnetic force. Which of the following is a true
statement (disregard any gravitational effects) Correct Answers
The speed of the of the particle will remain the same
A device plugged into a wall outlet experiences an alternating
current. The RMS current value is 2A. The peak current is
Correct Answers 2x sqrt2
=2.8
A light bulb connects to a battery. A second, identical light bulb
connects in parallel to the first light bulb. The connecting wires
have negligible resistance. When the switch is closed, the
original light bulb will Correct Answers experience no change
in brightness
A negatively charged particle moves through various electric
fields. Which of the following correctly indicates whether the
negatively charged particle gained or lost energy in each of the
following examples Correct Answers gained energy
, lost energy
gained energy
A particle with a charge of +2uC is at the position marked by x.
Which statement concerning the particle's energy is most
accurate? Correct Answers The particle will have a positive
energy term
A particle with a mass of 0.01 kg and a net charge of -0.05 C
accelerates from rest through a uniform electric field. If the
strength of the field is 2000 V/C, what is the speed of the
particle after traveling for 0.5 m? Correct Answers
Fd=1/2mv^2
qEd=1/2mv^2
sqrt(2qEd/m)=v
sqrt(2 (0.05) (2000) (.5)/0.01
100m/s
A particle with a net charge of -2uC is halfway between two
particles with a net charge of +4 uC and +6uC respectively. The
two positively charged particles are 10 cm apart. What is the
magnitude of the net force on the negative particle Correct
Answers F=kqq/r^2
9x10^9 (4x10^-6)(4x10^-6)/.1^2
14.4
A particular alternating voltage supply completes one full
voltage cycle at a frequency Correct Answers equal to 10Hz
Complete Solutions
A 1.5V battery connects to a 10 ohm resistor. The power
dissipated by the resistor is Correct Answers P=V^2/R
P=1.5^2/10
P=0.23 W
a 9.0 Vbattery connects to a wire resistor. The wire resistor is
tungsten (resistor 5.6x10^-8) 0.5m long has a radius of 1.2x10^-
5m. What is the current through the resistor Correct Answers
0.15 A
A battery connects to a resistor with resistance R and the
resulting current is measured. The resistor is removed and a new
resistor with a resistance of 2R is added. As a result Correct
Answers the voltage will double
the current will double
the charge speed will double
none of the above will options are correct!!
a battery connects to a resistor. The rate of energy dissipated by
the resistor is 1.44 W The rate of energy supplied by the battery
is Correct Answers equal to 1.44 W
A battery with a potential difference of V connects to a resistor,
and the resulting current is measured. You remove the battery,
and a new battery with a potential difference of 2Vis put in its
place. As a result Correct Answers the current will double
,A battery with an emf of 12V connects in parallel to a 50 ohm
and 25 ohm resistor. The current through the battery is 0.70 A.
What is the internal resistance of the battery Correct Answers
50 x+25 +16.6
E=I(Req +r)
12=0.7(16.6 +r)
12=11.66 +0.7r
0.333=0.7r
0.54 ohm
A charged particle moving to the right enters a uniform
magnetic field directed into the page. The charged particle
experiences a magnetic force. Which of the following is a true
statement (disregard any gravitational effects) Correct Answers
The speed of the of the particle will remain the same
A device plugged into a wall outlet experiences an alternating
current. The RMS current value is 2A. The peak current is
Correct Answers 2x sqrt2
=2.8
A light bulb connects to a battery. A second, identical light bulb
connects in parallel to the first light bulb. The connecting wires
have negligible resistance. When the switch is closed, the
original light bulb will Correct Answers experience no change
in brightness
A negatively charged particle moves through various electric
fields. Which of the following correctly indicates whether the
negatively charged particle gained or lost energy in each of the
following examples Correct Answers gained energy
, lost energy
gained energy
A particle with a charge of +2uC is at the position marked by x.
Which statement concerning the particle's energy is most
accurate? Correct Answers The particle will have a positive
energy term
A particle with a mass of 0.01 kg and a net charge of -0.05 C
accelerates from rest through a uniform electric field. If the
strength of the field is 2000 V/C, what is the speed of the
particle after traveling for 0.5 m? Correct Answers
Fd=1/2mv^2
qEd=1/2mv^2
sqrt(2qEd/m)=v
sqrt(2 (0.05) (2000) (.5)/0.01
100m/s
A particle with a net charge of -2uC is halfway between two
particles with a net charge of +4 uC and +6uC respectively. The
two positively charged particles are 10 cm apart. What is the
magnitude of the net force on the negative particle Correct
Answers F=kqq/r^2
9x10^9 (4x10^-6)(4x10^-6)/.1^2
14.4
A particular alternating voltage supply completes one full
voltage cycle at a frequency Correct Answers equal to 10Hz
