Bio 340 Exam 2
Questions and
Complete Solutions
Graded A+
Denning [Date] [Course title]
, If black and white true-breeding mice are mated and the result is all gray offspring, what inheritance
pattern would this be indicative of? - Correct Ans: incomplete dominance
ABO blood groups are examples of: - Correct Ans: Multiple alleles and codominance
Could an individual with blood type O (genotype ii) be a legitimate child of parents in which one parent
had blood type A and the other parent had blood type B? - Correct Ans: Yes, if each parent carries one i
allele.
A white splashed (Bl/Bl) Andalausian chicken and a black (bl/bl) Andalusian chicken are crossed. The
heterozygotes produced show an intermediate phenotype (blue). What inheritance pattern would this
be indicative of? - Correct Ans: incomplete dominance
A person with only one sickle cell anemia allele and one unaffected allele will have some normal blood
cells and some abnormal. What inheritance pattern would this be indicated of? - Correct Ans:
Codominance
In a mating between two individuals that are heterozygous for a recessive lethal allele that is expressed
in utero, what genotypic ratio (homozygous dominant:heterozygous:homozygous recessive) would you
expect to observe in the offspring? - Correct Ans: 1:2:0
The wild-type coat color, agouti (AA) is dominant to solid-colored fur (aa). However, a separate gene C,
when present as the recessive homozygote (cc), negates any expression of pigment from the A gene and
results in an albino mouse. Therefore, the genotypes AAcc, Aacc, and aacc all produce the same albino
phenotype. A cross between heterozygotes for both genes (AaCc x AaCc) would generate offspring with
a phenotypic ratio of 9 agouti:3 black:4 albino. Which type of gene interaction is this? - Correct Ans:
recessive epistasis
Wild type blue-eyed mary has blue flowers. Two genes
control the pathway that makes the blue pigment: The
product of gene Wturns a white precursor into magenta
pigment. The product of gene M turns the magenta
pigment into blue pigment. Each gene has a recessive
loss-of-function allele: w and m, respectively. A double
Questions and
Complete Solutions
Graded A+
Denning [Date] [Course title]
, If black and white true-breeding mice are mated and the result is all gray offspring, what inheritance
pattern would this be indicative of? - Correct Ans: incomplete dominance
ABO blood groups are examples of: - Correct Ans: Multiple alleles and codominance
Could an individual with blood type O (genotype ii) be a legitimate child of parents in which one parent
had blood type A and the other parent had blood type B? - Correct Ans: Yes, if each parent carries one i
allele.
A white splashed (Bl/Bl) Andalausian chicken and a black (bl/bl) Andalusian chicken are crossed. The
heterozygotes produced show an intermediate phenotype (blue). What inheritance pattern would this
be indicative of? - Correct Ans: incomplete dominance
A person with only one sickle cell anemia allele and one unaffected allele will have some normal blood
cells and some abnormal. What inheritance pattern would this be indicated of? - Correct Ans:
Codominance
In a mating between two individuals that are heterozygous for a recessive lethal allele that is expressed
in utero, what genotypic ratio (homozygous dominant:heterozygous:homozygous recessive) would you
expect to observe in the offspring? - Correct Ans: 1:2:0
The wild-type coat color, agouti (AA) is dominant to solid-colored fur (aa). However, a separate gene C,
when present as the recessive homozygote (cc), negates any expression of pigment from the A gene and
results in an albino mouse. Therefore, the genotypes AAcc, Aacc, and aacc all produce the same albino
phenotype. A cross between heterozygotes for both genes (AaCc x AaCc) would generate offspring with
a phenotypic ratio of 9 agouti:3 black:4 albino. Which type of gene interaction is this? - Correct Ans:
recessive epistasis
Wild type blue-eyed mary has blue flowers. Two genes
control the pathway that makes the blue pigment: The
product of gene Wturns a white precursor into magenta
pigment. The product of gene M turns the magenta
pigment into blue pigment. Each gene has a recessive
loss-of-function allele: w and m, respectively. A double
