Waste Water Certification Exam With Correct Questions And Answers 2024

Waste Water Certification Exam With Correct Questions And Answers 2024 Surface water runoff, storm water, sanitary and industrial. - correct answer.A collection system that is called "combined" may carry this kind of wastewater: 2 - correct answer.The flow in a collection system should be a minimum of ____ feet per second (FPS)? Solids will settle. - correct answer.What will happen if the flow is too slow in a collection system? Odors, Corrosion, Hydrogen Sulfide Gas (all of the above) - correct answer.A short detention time in the collection system will help prevent which of the following problems? Low areas must be sewered. - correct answer.When are lift (pumping) stations installed in a collection system? Parentheses, Exponents, Multiplication, Division, Addition, Subtraction - correct answer.The order of operations to solve math problems is: (from first to last) 27 - correct answer.3^3 24 - correct answer.(5+7)x4/2= 19 - correct answer.7+6X4/2= 4 - correct answer.2X+12=20. What is "X" equal to? 3,000,000gal/1,500,000MGD = 2 days = 48 hours - correct answer.The volume of a tank is 3,000,000 gallons (3MG) and the flow rate into the tank is 1,500,000 gallons per day (1.5 MGD). Calculate the detention time in hours. (750 GPM)(60 min/hr)(24 hr/day)/1,000,000 = 1.08 MGD - correct answer.A pump is rated at 750 gpm. Calculate the flow rate in million gallons per day (MGD). 1.5MG/1MLSS x 3.785L/1gal = 5.6775MG/1gal x 1lbs/453,592.37MG = 25.04 lbs/day - correct answer.A secondary clarifier discharges 2 MGD and the effluent contains 1.5 mg/l of mixed liquor suspended solids (MLSS). Calculate the pounds per day of MLSS discharged. (F012, F017, F022, F035) (200 mg/L - 15 mg/L)/(200 mg/L) x 100% = 92.5% - correct answer.The influent to a clarifier contains 200 mg/l of total suspended solids (TSS). What is the efficiency in % if there is 15 mg/l of TSS in the effluent? (F011 , F018) x= 0.785 x (100)^2 x (20) = 157,000 cf x 7.481/gal = 1,174,517 gal - correct answer.A clarifier is 100 ft. in diameter and 20 ft. deep. How many (ft^3) of water does the clarifier hold? How many gallons of water? Be subject to categorical standards, >25,000 gpd of process water or 5% or more of POTW capacity, have a reasonable potential to adversely affect POTW. (all of the above) - correct answer.To be define as a "significant industrial user" the industry must: Prevent introduction of pollutants that will interfere with and/or pass through with the POTW, and improve opportunities to recycle and reclaim water and sludges. (Both a and b) - correct answer.The major objectives of National Pretreatment Program include which of the following: Federal Water Pollution Control Act Amendments of 1972. - correct answer.The origin of the National Pretreatment Program goes back to this act: NPDES permit - correct answer.The POTW requirement to develop and implement a pretreatment program for industries is a condition of what? Once a year - correct answer.When are Control Authorities required to inspect significant industrial users? Identify responsible Control Authority officials, Identify the general time frame for actions, Potentially escalated actions based on the nature, frequency, magnitude and duration of the violation. (all of the above) - correct answer.What is the purpose of an Enforcement Response Guide (ERG)? Sludge deposits, floating debris, color, odor, and toxics (all of the above) - correct answer.Which