WGU BIOCHEMIST C785 Biochemistry Readiness Check 1B

12/12/2020 Biochemistry Readiness Check 1B




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Biochemistry Readiness Check 1B
The 2nd OA Readiness Check is designed to give you additional practice with new assessment-
style questions to help prepare for success on the OA. Thus, please try to mimic exam-like
conditions by taking the test in one <2 hr sitting without any study aids apart from your
whiteboard/scrap paper.

Note: Responses cannot be edited. You will be able to see the results and feedback after
submitting the test. A score of 70% is required for OA approval. If you score below 70%,
please speak with a Course Instructor via appointment to discuss next steps prior to retaking
this test.


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Points: 53/67



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1

What is the complementary sequence to 3’ CAG TAA CAA 5’? *
(0/1 Point)


5' TTG TTA CTG 3

The correct answer is 3' TTG TTA CTG 5'. Remember complementary means “Matching or Pairing”
You have to remember to pay attention to your numbers as well as your letters (A-T, G-C, 5'-3').
The correct answer is 3’ CAG TAA CAA 5’ (original sequence) 5’ GTC ATT GTT 3’ (complementary
sequence) But we asked for it in the 3’ direction, so mirror answer to give correct answer: 3’ TTG
TTA CTG 5’ If you chose 5' GTC ATT GTT 3', this sequence is just the mirror of the original
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,12/12/2020 Biochemistry Readiness Check 1B

sequence provided, and is not its complementary sequence. No "pairing" was done to get this
sequence.

3’ GTC ATT GTT 5’

3’ GTT ATT GTC 5’


3' TTG TTA CTG 5 





2

Which amino acid sequence would result from this Coding DNA strand? 3’ TAC
GTT AAC 5’? *
(0/1 Point)




Gln Leu His 
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,12/12/2020 Biochemistry Readiness Check 1B

Met Gln Leu

The correct answer is Gln Leu His. We are starting at the coding strand, and have to remember the
relationship between coding DNA and mRNA. These two strands are non-complementary and
parallel. So we copy the coding strand , change T ---> U, and then write the mRNA sequence: 3’
TAC GTT AAC 5’ coding 3’ UAC GUU AAC 5’ mRNA Mirror by changing orientation: 5’ CAA UUG CAU
3’ Read chart Gln Leu His (chart is in direction of 5' ---> 3') If you chose Met Gln Leu, this answer
is incorrect because this is the amino acid sequence that results from the mRNA 5' AUG CAA UUG
3' which would have been complementary to the given coding strand. Coding DNA is non-
complementary and parallel to mRNA.

Ile Asp Val


Gln Ile Met





3

Which amino acid sequence would be made from this template DNA strand? 5’
AGT TAT AAC 3’? *
(0/1 Point)




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, 12/12/2020 Biochemistry Readiness Check 1B




Met Leu Thr

Val Ile Thr 


Ser Tyr Asn

The correct answer is Val Ile Thr because 5’ AGT TAT AAC 3’ template is complementary and
antiparallel so 3’ UCA AUA UUG 5’ but it is in the wrong orientation, so mirror 5’ GUU AUA ACU 3’
and read the chart Val Ile Thr

Gln Tyr








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