WGU BIOCHEMISTRY EXAM SCRIPT TESTED
QUESTIONS VERIFIED SOLUTIONS
◍ pKa of Lysine R-group.
Answer: 10.5
◍ Rate-limiting Step of the Citric Acid Cycle.
Answer: Step 1 Acetyl-Coa + Oxaloacetate --> Citrate
◍ Total Energy Produced by Glycolysis.
Answer: 2NADH + 4 ATP
◍ Complex I in the ETC.
Answer: Accepts two electrons from NADH via an FMN cofactor. Transfers
4H+ to Pside and 2H+ to Q
◍ DNA Base-paring.
Answer: G-C base pairs have 3 H-bondsA-T base pairs have 2 H-bonds
◍ (Short response) What the definition of inorganic chemistry? How does it
differ from organic chemistry?.
Answer: Inorganic chemistry is the study of all other elements, but carbon.
Organic chemistry is the study of carbon-based compounds both in living
and non-living organisms. There is no need to have separate sub-disciples
for organic and inorganic chemistry, but for historical and organizational
reasons, the difference exists.
◍ ACC (acetyl-CoA carboxylase) Regulation.
Answer: Inhibited by PKA in glucagon chain and activated by pjhosphatase
in INSR chain.
◍ Helix Dipole.
, Answer: Formed from added dipole moments of all hydrogen bonds in an
α-helix. N-terminus is δ+ and C-terminus is δ-.
◍ Complex III in the ETC.
Answer: Transfers two electrons from QH2 to cytochrome c via the Q-cycle.
Transfers 4H+ to Pside.
◍ RuBisCo (Ribulose 1,5-bisphosphate carboxylase/oxygenase).
Answer: Incorporates CO2 into ribulose 1,5-bisphosphate and cleaves the
6C intermediate into 2 3-phosphoglycerate.
◍ Ka for Binding.
Answer: Ka = [PL] / [P][L]
◍ TPP Cofactor Structure.
Answer:
◍ Step 3 of Epinephrine Signal Transduction.
Answer: Activated α-subunit separates from ßɣ-complex and moves to
adenylyl cyclase, activating it.
◍ Hill Plot.
Answer: Turns sigmoid into straight lines. Slope = n (# of binding sites).
Allows measurement of binding sites that are cooperative.
◍ α+ß Protein Folding.
Answer: Two distinct areas of α and ß folding.
◍ Rubisco Activase.
Answer: Triggers removal of ribulose 1,5-bisphosphate or
2-carboxyaarabinitol 1-phosphate so Lys can be carbamoylated.
◍ A ___________ is a chemical formula that shows how the atoms of a
molecule are bonded to one another..
Answer: Kekule' structure
◍ (Short response) Biochemists study the communication within and among
organisms. According to the module, what are two other aspects of living
organisms that biochemists study?.
, Answer: In the module, biochemists also study the structure and function of
biomolecules and the chemical reactions of organisms.
◍ Iodoacetate.
Answer: Adds carboxymethyl group on free -SH groups. Blocks disulfide
bonding.
◍ Net Energy Gain of the Citric Acid Cycle.
Answer: 3 NADH, FADH2, and GTP
◍ PCR (Protein Chain Reaction).
Answer: Process by which DNA is replicated. Has melting step, annealing
step, replication step.
◍ High-Spin Fe.
Answer: Electrons are "spread out" and result in larger atom.
◍ Homologs.
Answer: Shares 25% identity with another gene
◍ Myoglobin 4° Structure.
Answer: Symmetric homodimer,
◍ pKa of Cysteine R-group.
Answer: 8
◍ Step 6 of Glycolysis.
Answer: Glyceraldehyde 3-Phosphate + Pi <-->
1,3-biphosphoglycerate.Uses G3P dehydrogenase enzyme.NAD+ <-->
NADH
◍ Gluconeogenic Bypass of Step 1.
Answer: Glucose 6-phosphate + H2O --> Glucose + PiUses glucose
6-phosphatase.
◍ Stage 3 of the Calvin Cycle.
Answer: Glyceraldehyde 3-phosphate --> Ribulose
1,5-bisphosphateRequires 3 ATP and uses transketolase (TPP).Only uses 8
of the 9 G3P's produced. One G3P is used to make starch/sucrose.
QUESTIONS VERIFIED SOLUTIONS
◍ pKa of Lysine R-group.
Answer: 10.5
◍ Rate-limiting Step of the Citric Acid Cycle.
Answer: Step 1 Acetyl-Coa + Oxaloacetate --> Citrate
◍ Total Energy Produced by Glycolysis.
Answer: 2NADH + 4 ATP
◍ Complex I in the ETC.
Answer: Accepts two electrons from NADH via an FMN cofactor. Transfers
4H+ to Pside and 2H+ to Q
◍ DNA Base-paring.
Answer: G-C base pairs have 3 H-bondsA-T base pairs have 2 H-bonds
◍ (Short response) What the definition of inorganic chemistry? How does it
differ from organic chemistry?.
Answer: Inorganic chemistry is the study of all other elements, but carbon.
Organic chemistry is the study of carbon-based compounds both in living
and non-living organisms. There is no need to have separate sub-disciples
for organic and inorganic chemistry, but for historical and organizational
reasons, the difference exists.
◍ ACC (acetyl-CoA carboxylase) Regulation.
Answer: Inhibited by PKA in glucagon chain and activated by pjhosphatase
in INSR chain.
◍ Helix Dipole.
, Answer: Formed from added dipole moments of all hydrogen bonds in an
α-helix. N-terminus is δ+ and C-terminus is δ-.
◍ Complex III in the ETC.
Answer: Transfers two electrons from QH2 to cytochrome c via the Q-cycle.
Transfers 4H+ to Pside.
◍ RuBisCo (Ribulose 1,5-bisphosphate carboxylase/oxygenase).
Answer: Incorporates CO2 into ribulose 1,5-bisphosphate and cleaves the
6C intermediate into 2 3-phosphoglycerate.
◍ Ka for Binding.
Answer: Ka = [PL] / [P][L]
◍ TPP Cofactor Structure.
Answer:
◍ Step 3 of Epinephrine Signal Transduction.
Answer: Activated α-subunit separates from ßɣ-complex and moves to
adenylyl cyclase, activating it.
◍ Hill Plot.
Answer: Turns sigmoid into straight lines. Slope = n (# of binding sites).
Allows measurement of binding sites that are cooperative.
◍ α+ß Protein Folding.
Answer: Two distinct areas of α and ß folding.
◍ Rubisco Activase.
Answer: Triggers removal of ribulose 1,5-bisphosphate or
2-carboxyaarabinitol 1-phosphate so Lys can be carbamoylated.
◍ A ___________ is a chemical formula that shows how the atoms of a
molecule are bonded to one another..
Answer: Kekule' structure
◍ (Short response) Biochemists study the communication within and among
organisms. According to the module, what are two other aspects of living
organisms that biochemists study?.
, Answer: In the module, biochemists also study the structure and function of
biomolecules and the chemical reactions of organisms.
◍ Iodoacetate.
Answer: Adds carboxymethyl group on free -SH groups. Blocks disulfide
bonding.
◍ Net Energy Gain of the Citric Acid Cycle.
Answer: 3 NADH, FADH2, and GTP
◍ PCR (Protein Chain Reaction).
Answer: Process by which DNA is replicated. Has melting step, annealing
step, replication step.
◍ High-Spin Fe.
Answer: Electrons are "spread out" and result in larger atom.
◍ Homologs.
Answer: Shares 25% identity with another gene
◍ Myoglobin 4° Structure.
Answer: Symmetric homodimer,
◍ pKa of Cysteine R-group.
Answer: 8
◍ Step 6 of Glycolysis.
Answer: Glyceraldehyde 3-Phosphate + Pi <-->
1,3-biphosphoglycerate.Uses G3P dehydrogenase enzyme.NAD+ <-->
NADH
◍ Gluconeogenic Bypass of Step 1.
Answer: Glucose 6-phosphate + H2O --> Glucose + PiUses glucose
6-phosphatase.
◍ Stage 3 of the Calvin Cycle.
Answer: Glyceraldehyde 3-phosphate --> Ribulose
1,5-bisphosphateRequires 3 ATP and uses transketolase (TPP).Only uses 8
of the 9 G3P's produced. One G3P is used to make starch/sucrose.
