PASSPOINTPRO
PHYS 112
GENERAL PHYSICS II
300-Question Comprehensive Practice Exam
Calculations + Conceptual Reasoning + Detailed Worked Explanations
300 A-D WORKED
MIXED PRACTICE QUESTIONS MULTIPLE-CHOICE FORMAT DETAILED RATIONALES
A comprehensive review of electricity, circuits, magnetism, induction, electromagnetic waves, and optics.
PASSPOINTPRO
,PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
How to Use This Practice Exam
This resource contains 300 mixed General Physics II practice questions. Calculation problems are intentionally mixed with
conceptual questions so you practice choosing the correct physical principle before substituting numbers. Each item includes the
correct answer immediately after the choices and a concise worked rationale. Use the first pass as a timed diagnostic, then
revisit missed questions and rework the calculations without looking at the explanation.
Area Core relationships used throughout the exam
Electrostatics F = k|q1q2|/r^2; E = F/q = k|Q|/r^2; V = kQ/r; Delta U = q Delta V
Capacitance C = Q/V; Cparallel = sum C; 1/Cseries = sum(1/C); U = (1/2)CV^2; tau = RC
DC circuits V = IR; P = IV = I^2R = V^2/R; R = rho L/A; junction: sum Iin = sum Iout; loop: sum Delta V = 0
Magnetism Fq = qvB sin(theta); Fwire = ILB sin(theta); r = mv/(|q|B); Bwire = mu0 I/(2 pi r); Bsolenoid = mu0
nI
Induction / AC |emf| = N|Delta Phi|/Delta t; Phi = BA cos(theta); emf = BLv; Vs/Vp = Ns/Np; Vrms = V0/sqrt(2); XL
= 2 pi fL; XC = 1/(2 pi fC)
Waves / optics c = f lambda; n = c/v; n1 sin(theta1) = n2 sin(theta2); 1/f = 1/do + 1/di; m = -di/do; Delta y =
lambda L/d; I = I0 cos^2(theta)
Constants used when needed: k = 8.99 x 10^9 N m^2/C^2; e = 1.602 x 10^-19 C; epsilon0 = 8.854 x 10^-12 F/m; mu0 = 4 pi x 10^-7 T m/A; c = 2.998 x
10^8 m/s.
PassPointPro | 300-Question Comprehensive Practice Exam Page 2
,PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
CAPACITANCE AND RC CIRCUITS
1. How much energy is stored in a 6.8 uF capacitor charged to 18 V?
A. 5.51e-04 J
B. 1.66e-03 J
C. 2.20e-03 J
D. 1.10e-03 J
Answer: D. 1.10e-03 J
Explanation: Stored energy is U = (1/2)CV^2. Therefore U = 0.5(6.80e-06)(18)^2 = 0.0011 J.
ELECTROMAGNETIC WAVES
2. Light in vacuum has wavelength 700 nm. What is its frequency?
A. 2.14 x 10^14 Hz
B. 6.47 x 10^14 Hz
C. 8.57 x 10^14 Hz
D. 4.28 x 10^14 Hz
Answer: D. 4.28 x 10^14 Hz
Explanation: Use f = c/lambda. With lambda = 7.000e-07 m, f = (2.998 x 10^8)/(7.000e-07) = 4.283e+14 Hz.
CAPACITANCE AND RC CIRCUITS
3. A 2.2 uF capacitor is connected across 24 V. How much charge is stored on either plate?
A. 106 uC
B. 26.4 uC
C. 79.7 uC
D. 52.8 uC
Answer: D. 52.8 uC
Explanation: Use Q = CV. Q = (2.20e-06 F)(24 V) = 5.280e-05 C = 52.8 uC.
PassPointPro | 300-Question Comprehensive Practice Exam Page 3
, PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
INDUCTION AND AC
4. Eddy currents are commonly reduced in transformer cores by
A. laminating the core
B. making the core one thick conducting block
C. eliminating all magnetic flux
D. using only DC in both coils
Answer: A. laminating the core
Explanation: Thin insulated laminations interrupt large circulating current paths and reduce eddy-current heating losses.
OPTICS
5. A concave mirror has focal length 0.20 m and an object is placed 0.50 m in front of it. What is the image
distance?
A. 0.333 m
B. 0.7 m
C. 0.143 m
D. 0.3 m
Answer: A. 0.333 m
Explanation: For a concave mirror with the standard real-positive convention, 1/f = 1/do + 1/di. Solving gives di = 0.333 m, so
the image is real and forms in front of the mirror.
ELECTRIC FIELDS AND POTENTIAL
6. A +2.5 uC charge is placed in a uniform electric field of 1.20e+04 N/C. What force magnitude acts on it?
A. 0.015 N
B. 0.03 N
C. 3.00e-03 N
D. 0.3 N
Answer: B. 0.03 N
Explanation: Electric force in a known field is F = qE. Using q = 2.50e-06 C gives F = (2.50e-06)(1.20e+04) = 0.03 N.
PassPointPro | 300-Question Comprehensive Practice Exam Page 4
PHYS 112
GENERAL PHYSICS II
300-Question Comprehensive Practice Exam
Calculations + Conceptual Reasoning + Detailed Worked Explanations
300 A-D WORKED
MIXED PRACTICE QUESTIONS MULTIPLE-CHOICE FORMAT DETAILED RATIONALES
A comprehensive review of electricity, circuits, magnetism, induction, electromagnetic waves, and optics.
PASSPOINTPRO
,PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
How to Use This Practice Exam
This resource contains 300 mixed General Physics II practice questions. Calculation problems are intentionally mixed with
conceptual questions so you practice choosing the correct physical principle before substituting numbers. Each item includes the
correct answer immediately after the choices and a concise worked rationale. Use the first pass as a timed diagnostic, then
revisit missed questions and rework the calculations without looking at the explanation.
Area Core relationships used throughout the exam
Electrostatics F = k|q1q2|/r^2; E = F/q = k|Q|/r^2; V = kQ/r; Delta U = q Delta V
Capacitance C = Q/V; Cparallel = sum C; 1/Cseries = sum(1/C); U = (1/2)CV^2; tau = RC
DC circuits V = IR; P = IV = I^2R = V^2/R; R = rho L/A; junction: sum Iin = sum Iout; loop: sum Delta V = 0
Magnetism Fq = qvB sin(theta); Fwire = ILB sin(theta); r = mv/(|q|B); Bwire = mu0 I/(2 pi r); Bsolenoid = mu0
nI
Induction / AC |emf| = N|Delta Phi|/Delta t; Phi = BA cos(theta); emf = BLv; Vs/Vp = Ns/Np; Vrms = V0/sqrt(2); XL
= 2 pi fL; XC = 1/(2 pi fC)
Waves / optics c = f lambda; n = c/v; n1 sin(theta1) = n2 sin(theta2); 1/f = 1/do + 1/di; m = -di/do; Delta y =
lambda L/d; I = I0 cos^2(theta)
Constants used when needed: k = 8.99 x 10^9 N m^2/C^2; e = 1.602 x 10^-19 C; epsilon0 = 8.854 x 10^-12 F/m; mu0 = 4 pi x 10^-7 T m/A; c = 2.998 x
10^8 m/s.
PassPointPro | 300-Question Comprehensive Practice Exam Page 2
,PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
CAPACITANCE AND RC CIRCUITS
1. How much energy is stored in a 6.8 uF capacitor charged to 18 V?
A. 5.51e-04 J
B. 1.66e-03 J
C. 2.20e-03 J
D. 1.10e-03 J
Answer: D. 1.10e-03 J
Explanation: Stored energy is U = (1/2)CV^2. Therefore U = 0.5(6.80e-06)(18)^2 = 0.0011 J.
ELECTROMAGNETIC WAVES
2. Light in vacuum has wavelength 700 nm. What is its frequency?
A. 2.14 x 10^14 Hz
B. 6.47 x 10^14 Hz
C. 8.57 x 10^14 Hz
D. 4.28 x 10^14 Hz
Answer: D. 4.28 x 10^14 Hz
Explanation: Use f = c/lambda. With lambda = 7.000e-07 m, f = (2.998 x 10^8)/(7.000e-07) = 4.283e+14 Hz.
CAPACITANCE AND RC CIRCUITS
3. A 2.2 uF capacitor is connected across 24 V. How much charge is stored on either plate?
A. 106 uC
B. 26.4 uC
C. 79.7 uC
D. 52.8 uC
Answer: D. 52.8 uC
Explanation: Use Q = CV. Q = (2.20e-06 F)(24 V) = 5.280e-05 C = 52.8 uC.
PassPointPro | 300-Question Comprehensive Practice Exam Page 3
, PHYS 112 | GENERAL PHYSICS II PASSPOINTPRO PRACTICE EXAM
INDUCTION AND AC
4. Eddy currents are commonly reduced in transformer cores by
A. laminating the core
B. making the core one thick conducting block
C. eliminating all magnetic flux
D. using only DC in both coils
Answer: A. laminating the core
Explanation: Thin insulated laminations interrupt large circulating current paths and reduce eddy-current heating losses.
OPTICS
5. A concave mirror has focal length 0.20 m and an object is placed 0.50 m in front of it. What is the image
distance?
A. 0.333 m
B. 0.7 m
C. 0.143 m
D. 0.3 m
Answer: A. 0.333 m
Explanation: For a concave mirror with the standard real-positive convention, 1/f = 1/do + 1/di. Solving gives di = 0.333 m, so
the image is real and forms in front of the mirror.
ELECTRIC FIELDS AND POTENTIAL
6. A +2.5 uC charge is placed in a uniform electric field of 1.20e+04 N/C. What force magnitude acts on it?
A. 0.015 N
B. 0.03 N
C. 3.00e-03 N
D. 0.3 N
Answer: B. 0.03 N
Explanation: Electric force in a known field is F = qE. Using q = 2.50e-06 C gives F = (2.50e-06)(1.20e+04) = 0.03 N.
PassPointPro | 300-Question Comprehensive Practice Exam Page 4
