MAT 101 TEST 1
(2*3)4=2(three*four)
(ab)c= a(bc) - ANS-associative property for multiplication
(10-five)-3
IS NOT EQUAL TO
10-(five-three) - ANS-why is not there the associative assets for subtraction?
(a)(b) = (b)(a) - ANS-comunitive belongings for multiplication
(a+b)+c = a+(b+c) - ANS-associative assets for addition
*(20/4)/2* NOT EQUAL to *20/(4/2)* - ANS-why isn't there the associative belongings for
division?
2: number ends in an even variety
5: wide variety results in zero or 5
10: number ends in zero
4: 4 divides into closing 2 digits
8: eight divides into closing three digits
3: the sum of the numbers is divisible through three
9: the sum of the numbers is divisible by using nine
6: 2 and three divide flippantly
12: 3 and 4 divide frivolously - ANS-divisibility rules
(2, five,10, 4, 8, 3, 9, 6, 12)
three*1 = 1*3
a*1 = 1*a - ANS-identity belongings for multiplication
6-3
IS NOT EQUAL TO
three-6 - ANS-why isn't always there the commutative assets for subtraction?
A(b-c) = ab-ac - ANS-distributive assets over subtraction
a(b+c) = ab+ac - ANS-distributive property over addition
a/four
IS NOT EQUAL TO
four/a - ANS-why is not there a commutative belongings for division?
A+(n+1)d
a= first range in sequence
(2*3)4=2(three*four)
(ab)c= a(bc) - ANS-associative property for multiplication
(10-five)-3
IS NOT EQUAL TO
10-(five-three) - ANS-why is not there the associative assets for subtraction?
(a)(b) = (b)(a) - ANS-comunitive belongings for multiplication
(a+b)+c = a+(b+c) - ANS-associative assets for addition
*(20/4)/2* NOT EQUAL to *20/(4/2)* - ANS-why isn't there the associative belongings for
division?
2: number ends in an even variety
5: wide variety results in zero or 5
10: number ends in zero
4: 4 divides into closing 2 digits
8: eight divides into closing three digits
3: the sum of the numbers is divisible through three
9: the sum of the numbers is divisible by using nine
6: 2 and three divide flippantly
12: 3 and 4 divide frivolously - ANS-divisibility rules
(2, five,10, 4, 8, 3, 9, 6, 12)
three*1 = 1*3
a*1 = 1*a - ANS-identity belongings for multiplication
6-3
IS NOT EQUAL TO
three-6 - ANS-why isn't always there the commutative assets for subtraction?
A(b-c) = ab-ac - ANS-distributive assets over subtraction
a(b+c) = ab+ac - ANS-distributive property over addition
a/four
IS NOT EQUAL TO
four/a - ANS-why is not there a commutative belongings for division?
A+(n+1)d
a= first range in sequence