Math 301 Exam 1 (Module 1)
Questions and Answers 2026
(ABandBBBareBsets)
WhatBisBAB∪BB?B-
BAnswerBTheBunionBofBABandBB.BSetBofBelementsBthatBareBinBABORBBB(orBboth)
(ABandBBBareBsets)
WhatBisBAB∩BB?B-
BAnswerBTheBintersectionBofBABandBB.BABsetBofBelementsBthatBareBinBbothBABANDB
B.
HowBcanByouBwriteBAB∪BBBinBsymbols?B-BAnswerB{x:BxB∈BABorBxB∈BB}
HowBcanByouBwriteBAB∩BBBinBsymbols?B-BAnswerB{x:BxB∈BABandBxB∈BB}
SupposeBAB=B{1,B2,B3}BandBBB=B{3,B4,B5},BwhatBis:
AB∪BB
and
AB∩BBB-BAnswerB{1,B2,B3,B4,B5}
and
{3}
A∪BB=BB∪AB
A∩B=B∩AB-BAnswerBcommutativeBproperty
, (AB∪BB)B∪BCB=AB∪B(BB∪BC)
and
(AB∩BB)B∩BCB=AB∩B(BB∩BC)B-BAnswerBassociativeBproperty
ABUBØB=B?B
AB∩BØB=B?B-BAnswerBABUBØB=BA
AB∩BØB=BØ
WhatBdoesB|A|Bmean?B-BAnswerBcardinalityBofBA
combinatorialBproofB-BAnswerBABproofBthatBmakesBuseBofBcountingBprinciples
ToBproveBanBequationBofBtheBformBLHSB=BRHS:
PoseBaBquestionBofBtheBform,B"InBhowBmanyBwaysB.B.B.B?"
OnBtheBoneBhand,BargueBwhyBLHSBisBaBcorrectBAnswerBtoBtheBquestion.B
OnBtheBotherBhand,BargueBwhyBRHSBisBaBcorrectBAnswer.
ThereforeBLHSB=BRHS.
WhenBareBABandBBBdisjoint?B-BAnswerBwhenBAB∩BBB=BØ
LetBABandBBBbeBfiniteBsets.BThenB
|A|B+B|B|B=B?B-BAnswerB|BABUBBB|B+B|BAB∩BBB|
Questions and Answers 2026
(ABandBBBareBsets)
WhatBisBAB∪BB?B-
BAnswerBTheBunionBofBABandBB.BSetBofBelementsBthatBareBinBABORBBB(orBboth)
(ABandBBBareBsets)
WhatBisBAB∩BB?B-
BAnswerBTheBintersectionBofBABandBB.BABsetBofBelementsBthatBareBinBbothBABANDB
B.
HowBcanByouBwriteBAB∪BBBinBsymbols?B-BAnswerB{x:BxB∈BABorBxB∈BB}
HowBcanByouBwriteBAB∩BBBinBsymbols?B-BAnswerB{x:BxB∈BABandBxB∈BB}
SupposeBAB=B{1,B2,B3}BandBBB=B{3,B4,B5},BwhatBis:
AB∪BB
and
AB∩BBB-BAnswerB{1,B2,B3,B4,B5}
and
{3}
A∪BB=BB∪AB
A∩B=B∩AB-BAnswerBcommutativeBproperty
, (AB∪BB)B∪BCB=AB∪B(BB∪BC)
and
(AB∩BB)B∩BCB=AB∩B(BB∩BC)B-BAnswerBassociativeBproperty
ABUBØB=B?B
AB∩BØB=B?B-BAnswerBABUBØB=BA
AB∩BØB=BØ
WhatBdoesB|A|Bmean?B-BAnswerBcardinalityBofBA
combinatorialBproofB-BAnswerBABproofBthatBmakesBuseBofBcountingBprinciples
ToBproveBanBequationBofBtheBformBLHSB=BRHS:
PoseBaBquestionBofBtheBform,B"InBhowBmanyBwaysB.B.B.B?"
OnBtheBoneBhand,BargueBwhyBLHSBisBaBcorrectBAnswerBtoBtheBquestion.B
OnBtheBotherBhand,BargueBwhyBRHSBisBaBcorrectBAnswer.
ThereforeBLHSB=BRHS.
WhenBareBABandBBBdisjoint?B-BAnswerBwhenBAB∩BBB=BØ
LetBABandBBBbeBfiniteBsets.BThenB
|A|B+B|B|B=B?B-BAnswerB|BABUBBB|B+B|BAB∩BBB|