Extended, International Adaptation, 12th
Edition Halliday (All Chapters included)
Chapter f1: MEASUREMENT 1
, Chapter f 1: MEASUREMENT
1. The fSI fstandard fof ftime fis fbased fon:
A. the fdaily frotation fof fthe fearth
B. the ffrequency fof flight femitted fby fKr86
C. the fyearly frevolution fof fthe fearth fabout fthe fsun
D. a fprecision fpendulum fclock
E. none fof fthese
fAns: f E
2. A fnanosecond fis:
A. 109 fs
B. 10−9 fs
C. 10−10 f s
D. 10−10 f s
E. 10−12
Ans: f B
3. The fSI fstandard fof flength fis fbased fon:
A. the fdistance ffrom fthe fnorth fpole fto fthe fequator falong fa fmeridian fpassing fthrough fParis
B. wavelength fof flight femitted fby fHg198
C. wavelength fof flight femitted fby fKr86
D. a fprecision fmeter fstick fin fParis
E. the fspeed fof flight
fAns: f E
4. In f1866, fthe fU. fS. fCongress fdefined fthe fU. fS. fyard fas fexactly f3600/3937 f international
f meter. fThis fwas fdone fprimarily fbecause:
A. length fcan fbe fmeasured fmore faccurately fin fmeters fthan fin fyards
B. the fmeter fis fmore fstable fthan fthe fyard
C. this fdefinition frelates fthe fcommon fU. fS. flength funits fto fa fmore fwidely fused fsystem
D. there fare fmore fwavelengths fin fa fyard fthan fin fa fmeter
E. the fmembers fof fthis fCongress fwere fexceptionally fintelligent
fAns: f C
5. Which fof fthe ffollowing fis fclosest fto fa fyard fin flength?
A. 0.01 fm
B. 0.1m f
C. 1 fm
D. 100 fm
E. 1000 fm
Ans: f C
Ans: f B
2 Chapter f1: MEASUREMENT
, 6. There fis fno fSI fbase funit ffor farea fbecause:
A. an farea fhas fno fthickness; fhence fno fphysical fstandard fcan fbe fbuilt
B. we flive fin fa fthree f(not fa ftwo) fdimensional fworld
C. it fis fimpossible fto fexpress fsquare ffeet fin fterms fof fmeters
D. area fcan fbe fexpressed fin fterms fof fsquare fmeters
E. area fis fnot fan fimportant fphysical fquantity
fAns: f D
7. The fSI fbase funit ffor fmass fis:
A. gram
B. pound
C. kilogram
D. ounce
E. kilopound
fAns: f C
8. A f gram f is:
A. 10−6 f kg
B. 10−3 f kg
C. 1 f kg
D. 103 f kg
E. 106 f kg
Ans: f B
9. Which fof fthe ffollowing fweighs fabout fa fpound?
A. 0.05 f kg
B. 0.5 fkg
C. 5 f kg
D. 50 fkg
E. 500 fkg
Ans: f D
10. (5.0 f × f 104) f × f (3.0 f × f 106) f = f
A. 1.5 f× f109
B. 1.5 f× f1010
C. 1.5 f× f1011
D. 1.5 f× f1012
E. 1.5 f× f1013
Ans: f C
11. (5.0 f × f 104) f × f (3.0 f × f 10−6) f = f
A. 1.5 f× f10−3
B. 1.5 f× f10−1
C. 1.5 f× f101
D. 1.5 f× f103
E. 1.5 f× f105
Chapter f1: MEASUREMENT 3
, 12. 5.0 f× f105 f + f3.0 f× f106 f =
A. 8.0 f× f105
B. 8.0 f× f106
C. 5.3 f× f105
D. 3.5 f× f105
E. 3.5 f× f106
Ans: f E
13. (7.0 f × f 106)/(2.0 f × f 10−6) f =f
A. 3.5 f× f10−12
B. 3.5 f× f10−6
C. 3.5
D. 3.5 f× f106
E. 3.5 f× f1012
Ans: f E
14. The fnumber fof fsignificant ffigures fin f0.00150 fis:
A. f f 2
B. f f 3
C. f f 4
D. f f 5
E. f f 6
Ans: f B
15. The fnumber fof fsignificant ffigures fin f15.0 fis:
A. f f 1
B. f f 2
C. f f 3
D. f f 4
E. f f 5
Ans: f C
16. 3.2 f × f 2.7 f =f
A. 9
B. 8
C. 8.6
D. 8.64
E. 8.640
Ans: f C
Ans: f B
2 Chapter f1: MEASUREMENT