CALIFORNIA MEDICAL LABORATORY TECHNICIAN (MLT)
LICENSING EXAMINATION AND CORRECT DETAILED
ANSWERS WITH RATIIONALES (100% VERIFIED
ANSWERS) ALREADY GRADED A+
Question 1
Which California regulation specifically defines the scope of practice for a licensed Medical
Laboratory Technician (MLT)?
A. CLIA ’88 Subpart M
B. California Business and Professions Code Section 1206.5
C. California Code of Regulations, Title 17, Section 1034
D. OSHA Bloodborne Pathogens Standard 29 CFR 1910.1030
Correct Answer: C
Rationale: In California, Title 17 of the California Code of Regulations, Section 1034, defines
personnel licensure categories including MLT scope of practice, supervision requirements, and
allowable testing. CLIA Subpart M addresses federal personnel requirements but not
California-specific licensure scope. The Business and Professions Code defines licensure
categories broadly, but the detailed scope is in Title 17. OSHA standards address safety, not
scope of practice.
Question 2
A complete blood count (CBC) on an EDTA-anticoagulated specimen shows a platelet count of
85 × 10³/µL. The peripheral smear reveals platelet clumps. What is the most appropriate
corrective action?
A. Report the count after warming the specimen to 37°C
B. Recollect the specimen in a sodium citrate tube and multiply the count by 1.1
C. Vortex the tube for 30 seconds and repeat the count
D. Perform a manual platelet estimate and report if no clumps are seen on the smear
Correct Answer: D
Rationale: Platelet clumps cause falsely low automated counts. The proper approach is to
perform a manual platelet estimate from a well-prepared smear to verify the count.
,Recollecting in citrate is an option for EDTA-induced pseudothrombocytopenia if clumps
persist, but the initial step is to check a smear for clumps and perform an estimate. Warming
or vortexing will not adequately break up antibody-mediated clumps and may damage cells.
Question 3
In spectrophotometry, Beer’s Law states that absorbance is directly proportional to:
A. The wavelength of light used
B. The log of transmittance
C. The concentration of the analyte and the path length
D. The square of the molar absorptivity
Correct Answer: C
Rationale: Beer’s Law is A = εbc, where A is absorbance, ε is molar absorptivity, b is path
length, and c is concentration. Absorbance is directly proportional to both concentration and
path length. Transmittance is inversely related, and the log of transmittance yields
absorbance, not the law’s statement of proportionality. Wavelength is selected based on the
analyte’s absorption maximum, not part of the proportionality.
Question 4
A peripheral blood smear shows macrocytic red cells, hypersegmented neutrophils, and oval
macrocytes. Which deficiency is most likely?
A. Iron deficiency
B. Folate or vitamin B12 deficiency
C. Glucose-6-phosphate dehydrogenase deficiency
D. Pyridoxine deficiency
Correct Answer: B
Rationale: The combination of macrocytic RBCs (oval macrocytes) and hypersegmented
neutrophils (more than 5 lobes) is classic for megaloblastic anemia due to folate or B12
deficiency, resulting from impaired DNA synthesis. Iron deficiency yields microcytic,
hypochromic cells. G6PD deficiency causes episodic hemolysis with bite cells. Pyridoxine
deficiency can cause microcytic anemia, but not oval macrocytes with hypersegmentation.
Question 5
Which Westgard rule is violated when one control result exceeds the mean by +3 standard
deviations while all other control results are within ±2s?
,A. 1₂s
B. 2₂s
C. 1₃s
D. R₄s
Correct Answer: C
Rationale: The 1₃s rule indicates a single control value exceeding the mean ±3 SD, signifying a
random error or beginning of a systematic error; it triggers rejection. The 1₂s is a warning rule.
The 2₂s rule requires two consecutive control values exceeding the same +2s or –2s limit. R₄s
applies when one control is +2s and another is –2s in the same run. Only 1₃s fits the
description.
Question 6
In blood bank, a group O, D-negative patient requires urgent transfusion and typed as O
negative. There is no time for a crossmatch. Which blood component is appropriate?
A. O positive packed red blood cells
B. O negative packed red blood cells, uncrossmatched
C. AB negative packed red blood cells
D. Group O whole blood
Correct Answer: B
Rationale: For an urgent need without crossmatch, O negative packed red cells are the
universal donor for red cells, avoiding Rh sensitization and ABO incompatibility. O positive
would cause anti-D formation in a D-negative patient. AB negative would be wasted and may
cause hemolysis if patient has anti-A or anti-B (though they are group O). Group O whole
blood is rarely used and would contain anti-A,B plasma, potentially causing minor hemolysis.
O neg packed cells are safest.
Question 7
Which anticoagulant is used for most routine coagulation tests because it preserves labile
clotting factors by binding calcium?
A. EDTA
B. Heparin
C. Sodium citrate (3.2%)
D. Potassium oxalate
Correct Answer: C
Rationale: Sodium citrate chelates calcium ions, reversibly preventing clotting. It is the
, anticoagulant of choice for PT, aPTT, and other coagulation tests because calcium can be
added back to initiate clotting. EDTA is too strong a chelator and irreversibly inhibits certain
factors, unsuitable for coagulation. Heparin inhibits thrombin and would interfere with tests.
Oxalate is rarely used and also less reversible.
Question 8
A chemistry analyzer’s glucose result is critically high at 550 mg/dL. The linearity limit of the
method is 500 mg/dL. What should the technologist do?
A. Report the result as >500 mg/dL
B. Dilute the specimen 1:2 with deionized water, reanalyze, and multiply by 2
C. Repeat the test using a different analyzer only
D. Release the result with a comment that it exceeds linearity
Correct Answer: B
Rationale: When a result exceeds the method’s linearity limit, the correct procedure is to
dilute the specimen with an appropriate diluent (often deionized water or saline for many
chemistry methods), reanalyze, then multiply by the dilution factor. Reporting >500 without a
quantitative value does not provide the physician a precise result if needed for management.
Repeating on another analyzer may have same linearity limit. A comment alone is insufficient.
Question 9
Which of the following is a commensal protozoan that may be found in stool but is
nonpathogenic and does not require treatment?
A. Giardia lamblia
B. Entamoeba histolytica
C. Entamoeba coli
D. Cryptosporidium parvum
Correct Answer: C
Rationale: Entamoeba coli is a nonpathogenic commensal found in the human intestine; its
presence in stool does not cause disease and needs no treatment. Giardia lamblia, Entamoeba
histolytica, and Cryptosporidium parvum are all pathogenic parasites that cause diarrhea and
gastrointestinal symptoms, requiring treatment.
Question 10
Under CLIA regulations, which of the following tests is classified as waived and can be
LICENSING EXAMINATION AND CORRECT DETAILED
ANSWERS WITH RATIIONALES (100% VERIFIED
ANSWERS) ALREADY GRADED A+
Question 1
Which California regulation specifically defines the scope of practice for a licensed Medical
Laboratory Technician (MLT)?
A. CLIA ’88 Subpart M
B. California Business and Professions Code Section 1206.5
C. California Code of Regulations, Title 17, Section 1034
D. OSHA Bloodborne Pathogens Standard 29 CFR 1910.1030
Correct Answer: C
Rationale: In California, Title 17 of the California Code of Regulations, Section 1034, defines
personnel licensure categories including MLT scope of practice, supervision requirements, and
allowable testing. CLIA Subpart M addresses federal personnel requirements but not
California-specific licensure scope. The Business and Professions Code defines licensure
categories broadly, but the detailed scope is in Title 17. OSHA standards address safety, not
scope of practice.
Question 2
A complete blood count (CBC) on an EDTA-anticoagulated specimen shows a platelet count of
85 × 10³/µL. The peripheral smear reveals platelet clumps. What is the most appropriate
corrective action?
A. Report the count after warming the specimen to 37°C
B. Recollect the specimen in a sodium citrate tube and multiply the count by 1.1
C. Vortex the tube for 30 seconds and repeat the count
D. Perform a manual platelet estimate and report if no clumps are seen on the smear
Correct Answer: D
Rationale: Platelet clumps cause falsely low automated counts. The proper approach is to
perform a manual platelet estimate from a well-prepared smear to verify the count.
,Recollecting in citrate is an option for EDTA-induced pseudothrombocytopenia if clumps
persist, but the initial step is to check a smear for clumps and perform an estimate. Warming
or vortexing will not adequately break up antibody-mediated clumps and may damage cells.
Question 3
In spectrophotometry, Beer’s Law states that absorbance is directly proportional to:
A. The wavelength of light used
B. The log of transmittance
C. The concentration of the analyte and the path length
D. The square of the molar absorptivity
Correct Answer: C
Rationale: Beer’s Law is A = εbc, where A is absorbance, ε is molar absorptivity, b is path
length, and c is concentration. Absorbance is directly proportional to both concentration and
path length. Transmittance is inversely related, and the log of transmittance yields
absorbance, not the law’s statement of proportionality. Wavelength is selected based on the
analyte’s absorption maximum, not part of the proportionality.
Question 4
A peripheral blood smear shows macrocytic red cells, hypersegmented neutrophils, and oval
macrocytes. Which deficiency is most likely?
A. Iron deficiency
B. Folate or vitamin B12 deficiency
C. Glucose-6-phosphate dehydrogenase deficiency
D. Pyridoxine deficiency
Correct Answer: B
Rationale: The combination of macrocytic RBCs (oval macrocytes) and hypersegmented
neutrophils (more than 5 lobes) is classic for megaloblastic anemia due to folate or B12
deficiency, resulting from impaired DNA synthesis. Iron deficiency yields microcytic,
hypochromic cells. G6PD deficiency causes episodic hemolysis with bite cells. Pyridoxine
deficiency can cause microcytic anemia, but not oval macrocytes with hypersegmentation.
Question 5
Which Westgard rule is violated when one control result exceeds the mean by +3 standard
deviations while all other control results are within ±2s?
,A. 1₂s
B. 2₂s
C. 1₃s
D. R₄s
Correct Answer: C
Rationale: The 1₃s rule indicates a single control value exceeding the mean ±3 SD, signifying a
random error or beginning of a systematic error; it triggers rejection. The 1₂s is a warning rule.
The 2₂s rule requires two consecutive control values exceeding the same +2s or –2s limit. R₄s
applies when one control is +2s and another is –2s in the same run. Only 1₃s fits the
description.
Question 6
In blood bank, a group O, D-negative patient requires urgent transfusion and typed as O
negative. There is no time for a crossmatch. Which blood component is appropriate?
A. O positive packed red blood cells
B. O negative packed red blood cells, uncrossmatched
C. AB negative packed red blood cells
D. Group O whole blood
Correct Answer: B
Rationale: For an urgent need without crossmatch, O negative packed red cells are the
universal donor for red cells, avoiding Rh sensitization and ABO incompatibility. O positive
would cause anti-D formation in a D-negative patient. AB negative would be wasted and may
cause hemolysis if patient has anti-A or anti-B (though they are group O). Group O whole
blood is rarely used and would contain anti-A,B plasma, potentially causing minor hemolysis.
O neg packed cells are safest.
Question 7
Which anticoagulant is used for most routine coagulation tests because it preserves labile
clotting factors by binding calcium?
A. EDTA
B. Heparin
C. Sodium citrate (3.2%)
D. Potassium oxalate
Correct Answer: C
Rationale: Sodium citrate chelates calcium ions, reversibly preventing clotting. It is the
, anticoagulant of choice for PT, aPTT, and other coagulation tests because calcium can be
added back to initiate clotting. EDTA is too strong a chelator and irreversibly inhibits certain
factors, unsuitable for coagulation. Heparin inhibits thrombin and would interfere with tests.
Oxalate is rarely used and also less reversible.
Question 8
A chemistry analyzer’s glucose result is critically high at 550 mg/dL. The linearity limit of the
method is 500 mg/dL. What should the technologist do?
A. Report the result as >500 mg/dL
B. Dilute the specimen 1:2 with deionized water, reanalyze, and multiply by 2
C. Repeat the test using a different analyzer only
D. Release the result with a comment that it exceeds linearity
Correct Answer: B
Rationale: When a result exceeds the method’s linearity limit, the correct procedure is to
dilute the specimen with an appropriate diluent (often deionized water or saline for many
chemistry methods), reanalyze, then multiply by the dilution factor. Reporting >500 without a
quantitative value does not provide the physician a precise result if needed for management.
Repeating on another analyzer may have same linearity limit. A comment alone is insufficient.
Question 9
Which of the following is a commensal protozoan that may be found in stool but is
nonpathogenic and does not require treatment?
A. Giardia lamblia
B. Entamoeba histolytica
C. Entamoeba coli
D. Cryptosporidium parvum
Correct Answer: C
Rationale: Entamoeba coli is a nonpathogenic commensal found in the human intestine; its
presence in stool does not cause disease and needs no treatment. Giardia lamblia, Entamoeba
histolytica, and Cryptosporidium parvum are all pathogenic parasites that cause diarrhea and
gastrointestinal symptoms, requiring treatment.
Question 10
Under CLIA regulations, which of the following tests is classified as waived and can be
