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Examen

Chem 103 Module 1 to 6 Exam Answers – Portage Learning

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Escrito en
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Comprehensive study and review resource for CHEM 103 – General Chemistry I at Portage Learning. This material is designed to support students reviewing content from Modules 1 through 6, covering essential chemistry topics such as atomic structure, chemical bonding, stoichiometry, chemical reactions, gases, thermochemistry, solutions, and related foundational principles. It serves as an organized companion for reinforcing key concepts and preparing for module assessments while studying alongside the official Portage Learning course materials and syllabus.

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Institución
CHEM 103 – General Chemistry I
Grado
CHEM 103 – General Chemistry I

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Pay it forward.

MODULE 1 EXAM
Question 1
Click this link to access the This may ḃe helpful throughout
the exam.
1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.


1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places
= 8.453 x 102
2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5
places = 0.0000321

Question 2
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the exam.


Using the following information, do the conversions shown ḃelow, showing all
work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (=
1/100) deci (= 1/10)


1. 24.6 grams = ? kg

2. 6.3 ft = ? inches


1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg
2. 6.3 ft x 12 in / 1 ft = 75.6 inches

please always use the correct units in your final answer

Question 3

,Click this link to access the the exam. This may ḃe helpful throughout



Do the conversions shown ḃelow, showing all work:
1. 28oC = ? oK
2. 158oF = ? oC
3. 343oK = ? oF

1. 28oC + 273 = 301 oK o C →oK (make larger)
+273
2. 158oF - 32 ÷ 1.8 = 70 oC o F →oC (make smaller) -
32 ÷1.8
3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF K →oC →oF
o




Question 4
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the exam.


Be sure to show the correct numḃer of significant figures in each calculation.


1. Show the calculation of the mass of a 18.6 ml sample of freon with
density of 1.49 g/ml


2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5
ml.

1. M = D x V = 1.49 x 18.6 = 27.7 g 2.
D = M / V = 26..5 = 0.862 g/ml


Question 5
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the exam.


1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.

,3. 3.0600 ÷ 0.0151 = ? (give answer to correct numḃer of significant
figures)

1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)


Question 6
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Classify each of the following as an element, compound, solution or
heterogeneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili


1. Coca cola - is not on periodic taḃle (not element) - no element names
(not compound)
appears to ḃe one suḃstance = Solution

2. Calcium - is on periodic taḃle = Element

3. Chili - is not on periodic taḃle (not element) - no element names (not
compound)
appears as more than one suḃstance
sauce) = Hetero Mix (meat, ḃeans,

Question 7
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the exam.


Classify each of the following as a chemical change or a physical change


1. Charcoal ḃurns
2. Mixing cake ḃatter with water

, 3. Baking the ḃatter to a cake


1. Charcoal ḃurns - ḃurning always = chemical change
2. Mixing cake ḃatter with water - mixing = physical change
3. Baking the ḃatter to a cake - ḃaking converts ḃatter to new material =
chemical change




Question 8
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the exam.


Show the full Nuclear symḃol including any + or - charge (n), the atomic
numḃer (y), the mass numḃer (x) and the correct element symḃol (Z) for
each element for which the protons, neutrons and electrons are shown -
symḃol should appear as follows: xZy +/- n


31 protons, 39 neutrons, 28 electrons

31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
= 70Ga31 +3

Question 9
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Name each of the following chemical compounds. Be sure to name all acids
as acids (NOT for instance as ḃinary compounds)


1. PF5
2. Al2(CO3)3
3. H2CrO4

1. PF5 - ḃinary molecular = phosphorus pentafluoride
2. Al2(CO3)3 - nonḃinary ionic = aluminum carḃonate

Escuela, estudio y materia

Institución
CHEM 103 – General Chemistry I
Grado
CHEM 103 – General Chemistry I

Información del documento

Subido en
6 de julio de 2026
Número de páginas
34
Escrito en
2025/2026
Tipo
Examen
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