?
D?
VE
RO
PP
_A
IA
UV
ST
, TABLE OF CONTENTS
Test Bank: Fundamentals of Chemical Engineering
Thermodynamics 1st Edition
Authors: Kevin Dahm, Donald Visco
ST
Ch 1: Introduction
UV
Ch 2: The Physical Properties of Pure Compounds
Ch 3: Material and Energy Balances
Ch 4: Entropy
IA
Ch 5: Thermodynamic Processes and Cycles
Ch 6: Thermodynamic Models of Real, Pure Compounds
_A
Ch 7: Equations of State (EOS)
Ch 8: Modeling Phase Equilibrium for Pure Components
Ch 9: An Introduction to Mixtures
PP
Ch 10: Vapor-Liquid Equilibrium
Ch 11: Theories and Models for Vapor-Liquid Equilibrium of Mixtures: Modified Raoult's Law
RO
Approaches
Ch 12: Theories and Models for Vapor-Liquid Equilibrium of Mixtures: Using Equations of State
Ch 13: Liquid-Liquid, Vapor-Liquid-Liquid, and Solid-Liquid Equilibrium
VE
Ch 14: Fundamentals of Chemical Reaction Equilibrium
Ch 15: Synthesis of Thermodynamic Principles
D?
?
, Dahm/Visco Fundamentals of Chemical Engineering Thermodynamics Chapter 1
REQUIRES ACCESS TO THE STEAM TABLES
1. 100 kg of water is contained in a piston-cylinder device. Initially, it is saturated liquid water
at P=10 bar. It is heated at constant pressure until it is superheated steam at P=10 bar and
T=250 °C.
ST
A) Determine the change in internal energy (U) of the water, in kJ.
B) Determine the amount of work (WEC) done on, or by, the water in this process.
UV
SOLUTION:
Specific internal energy and specific volume are both available in the steam tables.
IA
A)
������ − ����� = �(������� − ������)
_A
��
������ − ����� = (100 ��) (2710.4 − 761.4 ) = ���. ��� ��
��
PP
B)
������
��� = − ∫ ���
RO
�����
For constant pressure system:
��� = −�(������ − ����� ) = �(����� − ������)
VE
�
1 2
�3 10 �� 1�
5
�
��� = (10 ���)(100 ��) (0.001127 − 0.233 )( )( )( )
�� ��� 1 �� 1 ��
D
��� = −2.319 � 107 � = −��, ��� ��
Negative sign represents work done by water on the surroundings.
??
© 2015 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
, Dahm/Visco Fundamentals of Chemical Engineering Thermodynamics Chapter 1
2. A 50 kg object has kinetic energy of 100 kilojoules. What is its velocity in kilometers per
hour?
SOLUTION:
ST
1
�. �. = ��2
2
UV
1
100,000 � = (50 ��)�2
2
1 ���
1 �� 1
(100,000 �) ( )( �2 ) = (50 ��)�2
IA
1� 1� 2
�
� = ��. �
_A
�
PP
RO
VE
D ??
© 2015 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
D?
VE
RO
PP
_A
IA
UV
ST
, TABLE OF CONTENTS
Test Bank: Fundamentals of Chemical Engineering
Thermodynamics 1st Edition
Authors: Kevin Dahm, Donald Visco
ST
Ch 1: Introduction
UV
Ch 2: The Physical Properties of Pure Compounds
Ch 3: Material and Energy Balances
Ch 4: Entropy
IA
Ch 5: Thermodynamic Processes and Cycles
Ch 6: Thermodynamic Models of Real, Pure Compounds
_A
Ch 7: Equations of State (EOS)
Ch 8: Modeling Phase Equilibrium for Pure Components
Ch 9: An Introduction to Mixtures
PP
Ch 10: Vapor-Liquid Equilibrium
Ch 11: Theories and Models for Vapor-Liquid Equilibrium of Mixtures: Modified Raoult's Law
RO
Approaches
Ch 12: Theories and Models for Vapor-Liquid Equilibrium of Mixtures: Using Equations of State
Ch 13: Liquid-Liquid, Vapor-Liquid-Liquid, and Solid-Liquid Equilibrium
VE
Ch 14: Fundamentals of Chemical Reaction Equilibrium
Ch 15: Synthesis of Thermodynamic Principles
D?
?
, Dahm/Visco Fundamentals of Chemical Engineering Thermodynamics Chapter 1
REQUIRES ACCESS TO THE STEAM TABLES
1. 100 kg of water is contained in a piston-cylinder device. Initially, it is saturated liquid water
at P=10 bar. It is heated at constant pressure until it is superheated steam at P=10 bar and
T=250 °C.
ST
A) Determine the change in internal energy (U) of the water, in kJ.
B) Determine the amount of work (WEC) done on, or by, the water in this process.
UV
SOLUTION:
Specific internal energy and specific volume are both available in the steam tables.
IA
A)
������ − ����� = �(������� − ������)
_A
��
������ − ����� = (100 ��) (2710.4 − 761.4 ) = ���. ��� ��
��
PP
B)
������
��� = − ∫ ���
RO
�����
For constant pressure system:
��� = −�(������ − ����� ) = �(����� − ������)
VE
�
1 2
�3 10 �� 1�
5
�
��� = (10 ���)(100 ��) (0.001127 − 0.233 )( )( )( )
�� ��� 1 �� 1 ��
D
��� = −2.319 � 107 � = −��, ��� ��
Negative sign represents work done by water on the surroundings.
??
© 2015 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
, Dahm/Visco Fundamentals of Chemical Engineering Thermodynamics Chapter 1
2. A 50 kg object has kinetic energy of 100 kilojoules. What is its velocity in kilometers per
hour?
SOLUTION:
ST
1
�. �. = ��2
2
UV
1
100,000 � = (50 ��)�2
2
1 ���
1 �� 1
(100,000 �) ( )( �2 ) = (50 ��)�2
IA
1� 1� 2
�
� = ��. �
_A
�
PP
RO
VE
D ??
© 2015 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
