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Examen

SAN3701 Project |Structural Analysis IV A| 2026

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This assignment has been carefully put together to give you more than just answers; it walks you through the reasoning behind each one, so you actually understand the material rather than just memorising it. Every solution has been verified for accuracy, with academic references that hold up to scrutiny. Whether you're working through it the night before a submission or using it to reinforce your understanding over time, it's built to be genuinely useful. The explanations are clear without being condescending, and the structure follows what examiners actually look for not just what sounds impressive. If you put in the effort to engage with it properly, distinction-level results are well within reach.

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UNIVERSITY OF SOUTH AFRICA
College of Science, Engineering and Technology


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SAN3701: Structural Analysis

Project Assignment — Semester 1, 2026

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SAN3701
Module Code:
Structural Analysis
Module Name:
Circular Reservoir Wall & Matrix Stiffness
Assignment Topic:
Method
Project 2026
Assignment Number:
2026
Due Date:
100
Total Marks:




Submitted in partial fulfilment of the requirements for SAN3701 — UNISA 2026

,UNISA | SAN3701 Structural Analysis: Project 2026



Question 1: Circular Reservoir Wall Analysis [50 Marks]

Circular reservoir walls are commonly idealised as vertical structural elements subjected to
hydrostatic pressure. Their behaviour is analysed using the theory of beams on elastic founda-
tions to determine shear forces, bending moments, and deflections along the wall height (Tim-
oshenko and Gere, 1972).


Question 1.1: Excel Program Development [20 Marks]


Develop a complete Excel spreadsheet program to analyse a circular reservoir
wall. The program must compute hydrostatic pressure distribution along the wall
height, as well as shear force and bending moment distributions. It should be a
general model adaptable to different input parameters and reservoir geometries.
All inputs, formulas, calculations, results, and graphs must be clearly presented
and organised within the spreadsheet.



Given Data


Table 1: Input Parameters
Parameter Value

Height of wall (H) 14 m
Wall thickness (t) 500 mm = 0.5 m
Reservoir diameter (D) 35 m
Poisson’s ratio (ν) 0
Base condition Hinged at base



Excel Spreadsheet Structure


The spreadsheet follows the structure illustrated in the format below, replicating the semi-
infinite beam analysis approach shown in the provided Excel output.

A1 1.1 EXCEL PROGRAM
INPUT SECTION — Damping Factor Calculations




Page 2 of 25

,UNISA | SAN3701 Structural Analysis: Project 2026




Parameter Value Unit

Load from the fluid (γw ) 9.81 kN/m3

Height of wall (H) 14 m

Tank diameter (D) 35 m

Thickness of wall (t) 0.5 m

Poisson’s ratio (ν) 0 —

Semi-infinite beam model

ANALYSIS FOR SEMI-INFINITE BEAM CASE

Step 1 — Calculation for µ
The characteristic length parameter µ for a cylindrical shell wall on an elastic founda-
tion is: r
4 3(1 − ν 2 )
µ=
R2 t2

With ν = 0, R = 17.5 m, t = 0.5 m:
s

r
3(1 − 0) 3
= 0.039157 = 0.44481 m−1
4 4 4
µ= =
(17.5)2 (0.5)2 76.5625


Symbol Value

µ= 0.44481422

µL = 6.22879909

Step 2 — Coefficient Equations from Shell Theory
From equation 5.3 SG, the deflection distribution is calculated from coefficients A1 and
A2 . These coefficients form part of equation 01 for the matrix formation.
Note: B1 = B2 = 0

Calculation for Coefficient Equation 01:
Coefficient Value Expression
Result

Coefficient A1 = 0
4EIµ4 v − q =
−137.2
Coefficient A2 = 1

From equation 5.4 SG, the slope distribution is calculated from coefficients A1 and A2 .
These coefficients form part of equation 02 for the matrix formation.



Page 3 of 25

,UNISA | SAN3701 Structural Analysis: Project 2026



Calculation for Coefficient Equation 02:
Coefficient Value Expression
Result

Coefficient A1 = 1
dq 1 dq
4EIµ3 dx − µ dx
=
22.027
Coefficient A2 = −1

Matrix Formation and Solution

        
−137.2 0 1 A −115.173
A1
 =   1 ⇒  = 
22.027 1 −1 A2 A2 −137.200




Hydrostatic Pressure Distribution Table


Hydrostatic pressure at any depth:


p(h) = γw h = 9.81h [kN/m2 ]



Table 2: Pressure, Shear Force and Bending Moment Distribution
Depth h (m) Pressure p (kN/m2 ) Shear V (kN/m) Moment M (kNm/m)
0

0.00 0.00 0.00 19.62
2

19.62 13.08 39.24 78.48
4

104.64 58.86 176.58 353.16
6 8

78.48 313.92 837.12 98.10
10

490.50 1635.00 117.72 706.32
12

2825.28 137.34 961.38 4486.44
14




Excel formulas used:



Page 4 of 25

, UNISA | SAN3701 Structural Analysis: Project 2026


• Pressure: =$B$6*A15
• Shear Force: =($B$6*A15ˆ2)/2
• Bending Moment: =($B$6*A15ˆ3)/6


Graphical Outputs — TikZ Representation


The three graphs below replicate the Excel chart outputs.

Graph 1: Hydrostatic Pressure Distribution
Hydrostatic Pressure p (kN/m2 )




140 p = γw h
120

100

80

60

40

20

0
0 2 4 6 8 10 12 14
Depth h (m)


Figure 1: Linear hydrostatic pressure distribution along wall height


Graph 2: Shear Force Distribution

1,000
γw h2
V = 2
Shear Force V (kN/m)




800


600


400


200


0
0 2 4 6 8 10 12 14
Depth h (m)


Figure 2: Parabolic shear force distribution along wall height




Page 5 of 25

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Subido en
17 de junio de 2026
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Escrito en
2025/2026
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