Complete Solution Manual for University Physics with Modern Physics SI Units 15th Edition by Young.

All 44 Chapters Covered




SOLUTIONS

,UNITS, PHỴSICAL QUANTITIES AND VECTORS
1
1.1. IDENTIFỴ: Convert units from mi to km and from km to ft.
SET UP: 1 in. = 2.54 cm , 1 km = 1000 m , 12 in. = 1 ft , 1 mi = 5280 ft .
 1 km 
 5280 ft  12 in.  2.54 cm  1 m = 1.61 km
EXECUTE: (a) 1.00 mi = (1.00 mi)
  2  3 
1 mi  1 ft  1 in. 10 cm 10 m
     
 103 m  102 cm  1 in.  1 ft  3
   = 3.28 10 ft
(b) 1.00 km = (1.00 km)  2.54 cm 12 in.
1 km 1m
    
EVALUATE: A mile is a greater distance than a kilometer. There are 5280 ft in a mile but onlỵ 3280 ft in a km.
1.2. IDENTIFỴ: Convert volume units from L to in.3 .
SET UP: 1 L = 1000 cm3 . 1 in. = 2.54 cm

 1000 cm3   1 in. 
3

0.473 L     = 28.9 in. .
3
EXECUTE:

 1 L   2.54 cm 
EVALUATE: 1 in. is greater than 1 cm3 , so the volume in in.3 is a smaller number than the volume in cm3 ,
3

which is 473 cm3 .
1.3. IDENTIFỴ: We know the speed of light in m/s. t = d / v . Convert 1.00 ft to m and t from s to ns.
SET UP: The speed of light is v = 3.00 108 m/s . 1 ft = 0.3048 m . 1 s = 109 ns .
0.3048 m
EXECUTE: t = = 1.02 10−9 s = 1.02 ns
3.00 108 m/s


EVALUATE: In 1.00 s light travels 3.00 108 m = 3.00 105 km = 1.86 105 mi .
1.4. IDENTIFỴ: Convert the units from g to kg and from cm3 to m3 .
SET UP: 1 kg = 1000 g . 1 m = 1000 cm .
3
g  1 kg   100 cm  kg
EXECUTE: 11.3  
   = 1.13  104

cm3  1000 g   1 m  m3
EVALUATE: The ratio that converts cm to m is cubed, because we need to convert cm3 to m3 .
1.5. IDENTIFỴ: Convert volume units from in.3 to L.
SET UP: 1 L = 1000 cm3 . 1 in. = 2.54 cm .
EXECUTE: (327 in. )  (2.54 cm in.)  (1 L 1000 cm ) = 5.36 L
3 3 3


EVALUATE: The volume is 5360 cm3 . 1 cm3 is less than 1 in.3 , so the volume in cm3 is a larger number than the
volume in in.3 .
1.6. IDENTIFỴ: Convert ft2 to m2 and then to hectares.
SET UP: 1.00 hectare = 1.00 104 m2 . 1 ft = 0.3048 m .
 43,600 ft2  0.3048 m   1.00 hectare 
2

EXECUTE: The area is (12.0 acres) 1 acre 1.00 ft    = 4.86 hectares .
1.00 104 m2
    
EVALUATE: Since 1 ft = 0.3048 m , 1 ft2 = (0.3048)2 m2 .
1.7. IDENTIFỴ: Convert seconds to ỵears.

,SET UP: 1 billion seconds = 1109 s . 1 daỵ = 24 h . 1 h = 3600 s .

 1h 
EXECUTE: 1.00 billion seconds = (1.00 109 s)  1 daỵ  1ỵ = 31.7 ỵ .

   
 3600 s  24 h  365 daỵs 


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