MATH 1022 FINAL REVIEW QUESTIONS WITH
VERIFIED ACCURATE ANSWERS
area of a sector formula - Answers - A = 1/2r²θ with angle in RADIANS
arc length formula - Answers - s = rθ
special right triangles - Answers - SEE PICTURE
pythagorean identities - Answers - sin²θ + cos²θ = 1
tan²θ + 1 = sec²θ
1 + cot²θ = csc²θ
even-odd identities - Answers - sin(-x) = -sinx
cos(-x) = cosx
tan(-x) = -tanx
cofunction identities - Answers - sin (π/2 - θ) = cosθ
cos (π/2-θ) = sinθ
tan (π/2-θ) = cotθ
cot (π/2-θ) = tanθ
sec (π/2-θ) = cscθ
csc (π/2-θ) = secθ
missing coordinate on unit circle - Answers - x² + y² = 1
periodic property of sin and cosine - Answers - because the period of the sin/cos
function is 2pi, you can add 2pi to sin(-value) to make it positive
odd function - Answers - f(-x) = f(x), symmetric about the origin, sin, cos, sec
even function - Answers - f(-x) = -f(x), symmetric about the y-axis, tan, cot, csc
cosine function properties - Answers - zeros occur at (2n+1)/2 x π, relative maximum
occurs at 2πn = x
sine function properties - Answers - y intercept at 0, zeros are at x = nπ
graphing the sin and cosine function - Answers - y = A(Bsinx-C) + D and y = A(Bcosx-C)
+D
A = amplitude, make sure to multiply your range by the amplitude
B: used for finding the period, which is 2π/B, divide your period by 4 to get x values for
quarter points
C = phase shift, switch sign of phase shift +/-, phase shift is first quarter point
VERIFIED ACCURATE ANSWERS
area of a sector formula - Answers - A = 1/2r²θ with angle in RADIANS
arc length formula - Answers - s = rθ
special right triangles - Answers - SEE PICTURE
pythagorean identities - Answers - sin²θ + cos²θ = 1
tan²θ + 1 = sec²θ
1 + cot²θ = csc²θ
even-odd identities - Answers - sin(-x) = -sinx
cos(-x) = cosx
tan(-x) = -tanx
cofunction identities - Answers - sin (π/2 - θ) = cosθ
cos (π/2-θ) = sinθ
tan (π/2-θ) = cotθ
cot (π/2-θ) = tanθ
sec (π/2-θ) = cscθ
csc (π/2-θ) = secθ
missing coordinate on unit circle - Answers - x² + y² = 1
periodic property of sin and cosine - Answers - because the period of the sin/cos
function is 2pi, you can add 2pi to sin(-value) to make it positive
odd function - Answers - f(-x) = f(x), symmetric about the origin, sin, cos, sec
even function - Answers - f(-x) = -f(x), symmetric about the y-axis, tan, cot, csc
cosine function properties - Answers - zeros occur at (2n+1)/2 x π, relative maximum
occurs at 2πn = x
sine function properties - Answers - y intercept at 0, zeros are at x = nπ
graphing the sin and cosine function - Answers - y = A(Bsinx-C) + D and y = A(Bcosx-C)
+D
A = amplitude, make sure to multiply your range by the amplitude
B: used for finding the period, which is 2π/B, divide your period by 4 to get x values for
quarter points
C = phase shift, switch sign of phase shift +/-, phase shift is first quarter point
