AP Physics Final exam questions with
correct answers
Study |of |an |automobile |collision |requires |which |of |the |following |topics |in |physics? |- |CORRECT |
ANSWER✔✔-Newtonian |mechanics
Which |of |the |following |is |a |fundamental |unit |of |the |International |System |of |Units? |- |CORRECT |
ANSWER✔✔-Second
If |x |is |measured |in |meters, |v |and |vo |in |m/s |and |a |in |m/s2, |which |of |the |following |is |NOT |
dimensionally |consistent? |- |CORRECT |ANSWER✔✔-x |= |½ |at+vot
The |prefix |for |one |one-thousandth |(10-3) |is |- |CORRECT |ANSWER✔✔-milli
Express |.052 |g |in |engineering |notation. |- |CORRECT |ANSWER✔✔-52 |mg
A |man |goes |out |for |a |walk. |He |first |walks |120 |m |and |then |rests. |He |then |continues |on |his |
walk |for |another |64.8 |m. |What |is |the |total |length |of |his |walk? |- |CORRECT |ANSWER✔✔-185 |m
What |is |the |circumference |of |a |circle |with |a |7.38 |cm |radius? |(carefully |consider |the |number |of
|significant |figures) |- |CORRECT |ANSWER✔✔-46.4 |cm
Convert |0.092 |kg |to |standard |units |- |CORRECT |ANSWER✔✔-92 |g
Convert |211.3 |s |to |minutes. |- |CORRECT |ANSWER✔✔-3.522 |min
,Divide |46.73/11 |and |determine |the |answer |in |significant |figures. |- |CORRECT |ANSWER✔✔-
4.248
A |squirrel |dashes |across |a |240 |cm |wide |road |in |0.075 |minutes. |(You |must |always |show |work |
on |any |Free |Response |Question. |Most |points |are |awarded |for |showing |the |work |and |not |for |
the |actual |answer.)
A. |Convert |both |values |to |standard |units.
B. |Using |the |equation |speed=distance/time |calculate |the |speed |using |significant |figures.
C. |Convert |the |answer |to |Engineering |Notation. |- |CORRECT |ANSWER✔✔-A.
|240cm(1m/100cm)=2.4m |2 |Points
0.075min(60s/1min)=4.5s |2 |Points
B. |2.4/4.5=0.5333 |2 |Points
0.53 |m/s |2 |Points
C. |530 |x |10-3 |2 |Points
Given |two |vectors:
A=4i+ |2j
and
B=5i-3j
Find |the |magnitude |of:
A-B |- |CORRECT |ANSWER✔✔-5.1
Which |of |the |following |statements |about |vectors |is |NOT |true. |- |CORRECT |ANSWER✔✔-Vectors
|must |originate |at |the |point |0,0 |by |definition.
Which |of |the |following |are |NOT |vectors? |(Please |choose |all |that |are |correct) |- |CORRECT |
ANSWER✔✔-The |age |of |the |Earth
,A |persons |height
What |is |the |x |component |of |a |jet |flying |211 |m/s |at |215o? |- |CORRECT |ANSWER✔✔-Correct |
answer:
-172 |m/s
Ax=Acos()
Ax=211cos(215)=-172
if |you |got |41.7 |your |calculator |is |in |radians |and |must |be |switched |to |degrees
A |woman |runs |450 |m |at |30.o. |Assuming |the |angle |is |measured |from |normal |compass |points |
how |far |North |did |she |get? |- |CORRECT |ANSWER✔✔-390 |m
North |would |be |the |x |component |and |standard |angle |values |are |given |from |positive |x |or |East.
Ay=Asin()
Ay=450sin(30)=220
if |you |got |69 |then |your |calculator |is |in |radians |and |should |be |in |degrees
Three |sticks |of |length |6.0 |cm, |8.0 |cm |and |10.0 |cm |are |assembled |into |a |right |triangle. |What |is |
the |angle |of |the |where |the |6.0 |cm |stick |connects |to |the |10.0 |cm |stick? |- |CORRECT |
ANSWER✔✔-53º
T-6.0 |cm |becomes |the |adjacent |side |so
cosθ=(6/10)
, θ=cos-1(86/10)=53o
or |3-4-5 |triangle |so
Pythagorean |triple, |with |angles |of |53º |and |37º.
Which |equation |represents |the |angle |θ |in |the |drawing? |- |CORRECT |ANSWER✔✔-cos^-1(3/7)
-3 |is |adjacent, |7 |is |hypotenuse, |cos |θ |= |adjacent |over |hypotenuse.
θ |= |cos-1(3/7)=65o
Given |the |vector |relationship |A |+ |B |= |C. |If |the |magnitudes |of |the |vectors |are |related |by |A |+ |B |
> |C |which |of |the |following |statements |are |true? |(Choose |all |that |are |correct) |- |CORRECT |
ANSWER✔✔-The |vectors |A |and |B |could |NOT |be |pointing |in |the |same |direction
A |dog |walks |25.0 |m |West |and |then |7.50 |m |North. |What |is |the |magnitue |of |the |sum |of |these |
two |vectors? |- |CORRECT |ANSWER✔✔-26.1 |m
R=sqrt(Ax2+Ay2)
R=sqrt(252+7.52)=26.1 |m
A |dog |walks |25.0 |m |East |and |7.50 |m |South. |What |is |the |angle |of |the |sum |of |these |two |
vectors? |- |CORRECT |ANSWER✔✔--16.7o
()=tan-1(Ay/Ax)
()=tan-1(-7.5/25)=-16.7o
Find |the |resultant |vector |(magnitude |and |direction) |by |adding |the |following |set |of |vectors:
A |= |7.4m |due |South
correct answers
Study |of |an |automobile |collision |requires |which |of |the |following |topics |in |physics? |- |CORRECT |
ANSWER✔✔-Newtonian |mechanics
Which |of |the |following |is |a |fundamental |unit |of |the |International |System |of |Units? |- |CORRECT |
ANSWER✔✔-Second
If |x |is |measured |in |meters, |v |and |vo |in |m/s |and |a |in |m/s2, |which |of |the |following |is |NOT |
dimensionally |consistent? |- |CORRECT |ANSWER✔✔-x |= |½ |at+vot
The |prefix |for |one |one-thousandth |(10-3) |is |- |CORRECT |ANSWER✔✔-milli
Express |.052 |g |in |engineering |notation. |- |CORRECT |ANSWER✔✔-52 |mg
A |man |goes |out |for |a |walk. |He |first |walks |120 |m |and |then |rests. |He |then |continues |on |his |
walk |for |another |64.8 |m. |What |is |the |total |length |of |his |walk? |- |CORRECT |ANSWER✔✔-185 |m
What |is |the |circumference |of |a |circle |with |a |7.38 |cm |radius? |(carefully |consider |the |number |of
|significant |figures) |- |CORRECT |ANSWER✔✔-46.4 |cm
Convert |0.092 |kg |to |standard |units |- |CORRECT |ANSWER✔✔-92 |g
Convert |211.3 |s |to |minutes. |- |CORRECT |ANSWER✔✔-3.522 |min
,Divide |46.73/11 |and |determine |the |answer |in |significant |figures. |- |CORRECT |ANSWER✔✔-
4.248
A |squirrel |dashes |across |a |240 |cm |wide |road |in |0.075 |minutes. |(You |must |always |show |work |
on |any |Free |Response |Question. |Most |points |are |awarded |for |showing |the |work |and |not |for |
the |actual |answer.)
A. |Convert |both |values |to |standard |units.
B. |Using |the |equation |speed=distance/time |calculate |the |speed |using |significant |figures.
C. |Convert |the |answer |to |Engineering |Notation. |- |CORRECT |ANSWER✔✔-A.
|240cm(1m/100cm)=2.4m |2 |Points
0.075min(60s/1min)=4.5s |2 |Points
B. |2.4/4.5=0.5333 |2 |Points
0.53 |m/s |2 |Points
C. |530 |x |10-3 |2 |Points
Given |two |vectors:
A=4i+ |2j
and
B=5i-3j
Find |the |magnitude |of:
A-B |- |CORRECT |ANSWER✔✔-5.1
Which |of |the |following |statements |about |vectors |is |NOT |true. |- |CORRECT |ANSWER✔✔-Vectors
|must |originate |at |the |point |0,0 |by |definition.
Which |of |the |following |are |NOT |vectors? |(Please |choose |all |that |are |correct) |- |CORRECT |
ANSWER✔✔-The |age |of |the |Earth
,A |persons |height
What |is |the |x |component |of |a |jet |flying |211 |m/s |at |215o? |- |CORRECT |ANSWER✔✔-Correct |
answer:
-172 |m/s
Ax=Acos()
Ax=211cos(215)=-172
if |you |got |41.7 |your |calculator |is |in |radians |and |must |be |switched |to |degrees
A |woman |runs |450 |m |at |30.o. |Assuming |the |angle |is |measured |from |normal |compass |points |
how |far |North |did |she |get? |- |CORRECT |ANSWER✔✔-390 |m
North |would |be |the |x |component |and |standard |angle |values |are |given |from |positive |x |or |East.
Ay=Asin()
Ay=450sin(30)=220
if |you |got |69 |then |your |calculator |is |in |radians |and |should |be |in |degrees
Three |sticks |of |length |6.0 |cm, |8.0 |cm |and |10.0 |cm |are |assembled |into |a |right |triangle. |What |is |
the |angle |of |the |where |the |6.0 |cm |stick |connects |to |the |10.0 |cm |stick? |- |CORRECT |
ANSWER✔✔-53º
T-6.0 |cm |becomes |the |adjacent |side |so
cosθ=(6/10)
, θ=cos-1(86/10)=53o
or |3-4-5 |triangle |so
Pythagorean |triple, |with |angles |of |53º |and |37º.
Which |equation |represents |the |angle |θ |in |the |drawing? |- |CORRECT |ANSWER✔✔-cos^-1(3/7)
-3 |is |adjacent, |7 |is |hypotenuse, |cos |θ |= |adjacent |over |hypotenuse.
θ |= |cos-1(3/7)=65o
Given |the |vector |relationship |A |+ |B |= |C. |If |the |magnitudes |of |the |vectors |are |related |by |A |+ |B |
> |C |which |of |the |following |statements |are |true? |(Choose |all |that |are |correct) |- |CORRECT |
ANSWER✔✔-The |vectors |A |and |B |could |NOT |be |pointing |in |the |same |direction
A |dog |walks |25.0 |m |West |and |then |7.50 |m |North. |What |is |the |magnitue |of |the |sum |of |these |
two |vectors? |- |CORRECT |ANSWER✔✔-26.1 |m
R=sqrt(Ax2+Ay2)
R=sqrt(252+7.52)=26.1 |m
A |dog |walks |25.0 |m |East |and |7.50 |m |South. |What |is |the |angle |of |the |sum |of |these |two |
vectors? |- |CORRECT |ANSWER✔✔--16.7o
()=tan-1(Ay/Ax)
()=tan-1(-7.5/25)=-16.7o
Find |the |resultant |vector |(magnitude |and |direction) |by |adding |the |following |set |of |vectors:
A |= |7.4m |due |South
