MATH 225

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MATH  225 Midterm Exam 1 Complete with solutions.
  • MATH 225 Midterm Exam 1 Complete with solutions.

  • Exam (elaborations) • 6 pages • 2020
  • Solutions of First Midterm Exam 1.a) Show that the function y(x) = A Bex Ce2x satisfies the differential equation yJJJ − 3yJJ 2yJ = 0, where A, B, and C are arbitrary constants. Solution: y(x) = A Bex Ce2x, yJ(x) = Bex 2Ce2x, yJJ(x) = Bex 4Ce2x yJJJ(x) = Bex 8Ce2x Hence yJJJ − 3yJJ 2yJ = Bex 8Ce2x − 3(Bex 4Ce2x) 2(Bex 2Ce2x) = 0 1.b) Find the constants A, B, and C so that y(0) = 1, yJ(0) = −1, yJJ(0) = 0. Solution: y(0) = A B C = 1, yJ(0) = B 2C = −1, ...
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