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BIOD 171 MICROBIOLOGY MODULE 6 EXAM – PORTAGE LEARNING ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS WITH RATIONALES GRADED A+ LATEST

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BIOD 171 MICROBIOLOGY MODULE 6 EXAM PORTAGE LEARNING ACTUAL EXAM QUESTIONS AND CORRECT ANSWERS WITH RATIONALES GRADED A+ LATEST BIOD 171 Microbiology – Module 6 Comprehensive Exam (Portage Learning Style) This comprehensive Module 6 examination is designed to closely mirror the rigor, structure, and cognitive demands of the official Portage Learning BIOD 171 Microbiology assessment. The exam evaluates student mastery of microbial metabolism, enzymatic function, bioenergetics, and microbial growth dynamics. Questions across aerobic and anaerobic pathways, enzyme kinetics and inhibition, metabolic integration, environmental effects on microbial physiology, and bacterial growth phases. With clear rationales supporting the correct answers to reinforce learning and exam readiness.

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BIOD 171 MICROBIOLOGY MODULE 6 EXAM –
PORTAGE LEARNING ACTUAL EXAM QUESTIONS
AND CORRECT ANSWERS WITH RATIONALES
GRADED A+ LATEST

Question 1
Which characteristic best distinguishes an enzyme from a non-biological catalyst?
A. It increases reaction temperature
B. It is consumed during the reaction
C. It exhibits substrate specificity
D. It functions only at neutral pH
Correct Answer: C
Rationale: Enzymes are highly specific, binding only particular substrates due to
their unique active sites. They are not consumed and can function across various
pH ranges depending on the enzyme.


Question 2
A competitive inhibitor reduces enzyme activity by:
A. Binding to an allosteric site
B. Permanently altering enzyme structure
C. Competing with the substrate for the active site
D. Lowering the activation energy
Correct Answer: C
Rationale: Competitive inhibitors resemble the substrate and compete for binding
at the enzyme’s active site, reducing enzyme–substrate complex formation.

,Question 3
Which metabolic pathway generates the greatest amount of ATP per glucose
molecule under aerobic conditions?
A. Glycolysis
B. Pentose phosphate pathway
C. Krebs cycle
D. Electron transport chain
Correct Answer: D
Rationale: While glycolysis and the Krebs cycle produce some ATP directly, the
majority of ATP is generated through oxidative phosphorylation in the electron
transport chain.


Question 4
During glycolysis, glucose is converted into:
A. Acetyl-CoA
B. Two molecules of pyruvate
C. Carbon dioxide and water
D. Lactate
Correct Answer: B
Rationale: Glycolysis splits one glucose molecule into two pyruvate molecules,
producing ATP and NADH in the process.

,Question 5
Which molecule acts as the final electron acceptor in aerobic respiration?
A. Carbon dioxide
B. Oxygen
C. NAD⁺
D. Pyruvate
Correct Answer: B
Rationale: Oxygen serves as the terminal electron acceptor in the electron
transport chain, forming water.


Question 6
Fermentation primarily functions to:
A. Generate large amounts of ATP
B. Produce carbon dioxide
C. Regenerate NAD⁺
D. Oxidize glucose completely
Correct Answer: C
Rationale: Fermentation allows cells to regenerate NAD⁺ from NADH so
glycolysis can continue in the absence of oxygen.


Question 7
Which organism classification requires organic carbon and light energy?
A. Chemoautotroph
B. Photoautotroph
C. Photoheterotroph
D. Chemoheterotroph
Correct Answer: C
Rationale: Photoheterotrophs use light as an energy source but rely on organic
compounds for carbon.

, Question 8
Anabolism is best described as metabolism that:
A. Breaks down complex molecules
B. Releases energy
C. Builds complex molecules
D. Occurs only in mitochondria
Correct Answer: C
Rationale: Anabolic reactions synthesize complex molecules from simpler ones
and typically require energy input.


Question 9
Which factor would most likely denature a bacterial enzyme?
A. Slight substrate increase
B. Minor temperature change
C. Extreme pH shift
D. Increased enzyme concentration
Correct Answer: C
Rationale: Extreme pH alters protein structure, disrupting hydrogen bonds and
denaturing enzymes.


Question 10
The lag phase of bacterial growth is characterized by:
A. Rapid cell division
B. Declining cell numbers
C. Cellular adaptation and enzyme synthesis
D. Maximum metabolic activity
Correct Answer: C
Rationale: During lag phase, bacteria adjust to the environment and synthesize
enzymes necessary for growth.

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