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Examen

Pearson Edexcel International Advanced Level Physics UNIT 1 MAY 2025 QUESTION PAPER: Mechanics and Materials

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Publié le
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Écrit en
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Publié le
12 novembre 2025
Nombre de pages
32
Écrit en
2025/2026
Type
Examen
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Please check the examination details below before entering your candidate information
Candidate surname Other names


Centre Number Candidate Number




Pearson Edexcel International Advanced Level
Friday 9 May 2025
Morning (Time: 1 hour 30 minutes) Paper
reference WPH11/01
Physics
 


International Advanced Subsidiary/Advanced Level
UNIT 1: Mechanics and Materials

You must have: Total Marks
Scientific calculator, ruler



Instructions:
•• Use black ink or ball‑point pen.
If pencil is used for diagrams/sketches/graphs it must be dark (HB or B).
• Fill in the boxes at the top of this page with your name,
centre number and candidate number.
•• Answer all questions.
Answer the questions in the spaces provided
– there may be more space than you need.
• Show all your working out in calculations and include units where appropriate.
Information:
•• The total mark for this paper is 80.
The marks for each question are shown in brackets
– use this as a guide as to how much time to spend on each question.
• Into the question marked with an asterisk (*), marks will be awarded for your ability
structure your answer logically, showing how the points that you make are
related or follow on from each other where appropriate.
• The list of data, formulae and relationships is printed at the end of this booklet.
Advice:
•• Read each question carefully before you start to answer it.
Try to answer every question.
• Check your answers if you have time at the end. Turn over


P78753A
©2025 Pearson Education Ltd.
Y:1/1/1/
*P78753A0132*

, SECTION A
Answer ALL questions.




DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
For questions 1–10, in Section A, select one answer from A to D and put a cross in the box . If you
change your mind, put a line through the box and then mark your new answer with a cross .
1: A cube of volume V is placed in a liquid of density ρ. The cube displaces a weight W of
the liquid.
Which of the following gives the magnitude of the upthrust acting on the cube?

A V×W

B V

C V×ρ

D W
(Total for Question 1 = 1 mark)

2: A see‑saw is a uniform beam that balances on a support. The beam can rotate around the
top of the support.
Two children of equal weight sit on a see‑saw at equal distances from the support,
as shown.




support beam


Which row of the table describes the resultant force and resultant moment on the beam?

Resultant force Resultant moment
A zero zero
B zero anticlockwise
C downwards zero
D downwards anticlockwise

(Total for Question 2 = 1 mark)




2
*P78753A0232* 

, 3: The diagram shows a ball of mass m moving at speed v along a horizontal table.

v
DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA




The ball leaves the table. The time taken between the ball leaving the table and landing
on the floor is t.
A second ball of mass 2m moves at speed 2v along the table.
Which of the following gives the time taken between the second ball leaving the table
and landing on the floor?

A 2t
B t

t
C
2

t
D
4

(Total for Question 3 = 1 mark)

4: The forces acting on a person sitting on a chair are weight and normal contact force.
Which of the following gives a reason why these forces do not form a Newton’s third
law pair?

A The chair is stationary.

B The forces act in opposite directions.

C The forces act on the same object.

D The forces have the same magnitude.
(Total for Question 4 = 1 mark)




3
 *P78753A0332* Turn over

, 5: A wire is used to hang a picture from a hook on a wall.
The wire exerts forces T1 and T2 on the picture. The picture has weight W, as shown.




DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA DO NOT WRITE IN THIS AREA
wire hook


T1 T2
Not to scale



W



Which of the following describes the relationship between the forces when the picture is
hanging on the wall?

→ → →
A W = T1 + T2
→ → →
B W + T1 + T2 = 0
→ → →
C W = T1 – T2
→ → →
D W + T1 – T2 = 0
(Total for Question 5 = 1 mark)




4



*P78753A0432* 
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