,
,Chapter 1: Arithmetic Needed for Dosage
ty ty ty ty ty
MULTIPLE CHOICE ty
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz.
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
What portion of the water remained?
ty ty ty ty ty
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A t y
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25 oz
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10 oz (r
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
emaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce fractions, fin
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
d the largest number that can be divided evenly into the numerator and the denominator
ty ty ty ty ty ty ty ty ty ty ty ty ty ty
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Apply ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integra
ty ty ty ty ty ty ty ty ty
ted Process: Teaching/Learning
ty ty
Objective: 1, 2 ty ty
2. A patient/client was prescribed 240 W
ty mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100
ty ty ty ty ty ty ty ty ty ty ty ty
mL. What portion of the Ensure remained?
ty ty ty ty ty ty
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B t y
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available quanti
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ty (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fraction by d
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by 240 = 7/12. To
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
reduce fractions, find the largest number that can be divided evenly into the numerator and the denomin
y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be reduced to its lowe
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
st terms of 7/12.
ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Apply ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integra
ty ty ty ty ty ty ty ty ty
ted Process: Teaching/Learning
ty ty
Objective: 1, 2 ty ty
1|Page
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, 3. A patient/client consumed
ty oz. of coffee, 2/3 oz. of ice cream, and ty t y t y ty ty ty ty ty ty ty ty t y
oz. of beef broth. What is the total number of ounces consumed that should be documented for the pati
t y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ent/client?
a. 3 3/4 ty
b. 4 5/12 ty
c. 4 2/3 ty
d. 4 4/9 ty
ANS: B t y
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by multipl
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ying the whole number by the denominator and then adding that total to the numerator. For the coffee, 4
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
2 = 8 + 1 = 9/4; for the beef broth, 2 1
y ty ty ty ty ty ty ty ty ty ty ty ty ty
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find the
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
least common denominator (LCD). For 2, 3, and 4, the LCD =
y ty ty ty ty ty ty ty ty ty ty ty
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then m
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ultiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee), 8/12
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
(ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added together
y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
and the fraction is reduced to the lowest terms.
ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Analyze ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
ty ty ty ty ty ty ty ty ty
grated Process: Communication and Documentation Objective: 1,
ty ty ty ty ty ty ty
2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
the nurse document as consumed?
ty ty ty ty
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B t y
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of millil
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
iters consumed, multiply 180 7/3 (
ty ty ty ty ty ty
). When a mixed number is present, change it to an improper fraction by multiplying the whole number b
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
y the denominator and then adding that total to
ty ty ty ty ty ty ty ty
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Analyze ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
ty ty ty ty ty ty ty ty ty
grated Process: Communication and Documentation Objective: 1,
ty ty ty ty ty ty ty
2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were g
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ained since admission? ty ty
a. 0.78
b. 0.88
2|Page
www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
ty ty ty ty ty
MULTIPLE CHOICE ty
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz.
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
What portion of the water remained?
ty ty ty ty ty
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A t y
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25 oz
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10 oz (r
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
emaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce fractions, fin
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
d the largest number that can be divided evenly into the numerator and the denominator
ty ty ty ty ty ty ty ty ty ty ty ty ty ty
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Apply ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integra
ty ty ty ty ty ty ty ty ty
ted Process: Teaching/Learning
ty ty
Objective: 1, 2 ty ty
2. A patient/client was prescribed 240 W
ty mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100
ty ty ty ty ty ty ty ty ty ty ty ty
mL. What portion of the Ensure remained?
ty ty ty ty ty ty
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B t y
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available quanti
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ty (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fraction by d
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by 240 = 7/12. To
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
reduce fractions, find the largest number that can be divided evenly into the numerator and the denomin
y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be reduced to its lowe
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
st terms of 7/12.
ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Apply ty ty
Difficulty: Moderate ty
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Integra
ty ty ty ty ty ty ty ty ty
ted Process: Teaching/Learning
ty ty
Objective: 1, 2 ty ty
1|Page
www.PlusBay.Plus
, 3. A patient/client consumed
ty oz. of coffee, 2/3 oz. of ice cream, and ty t y t y ty ty ty ty ty ty ty ty t y
oz. of beef broth. What is the total number of ounces consumed that should be documented for the pati
t y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ent/client?
a. 3 3/4 ty
b. 4 5/12 ty
c. 4 2/3 ty
d. 4 4/9 ty
ANS: B t y
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by multipl
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ying the whole number by the denominator and then adding that total to the numerator. For the coffee, 4
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
2 = 8 + 1 = 9/4; for the beef broth, 2 1
y ty ty ty ty ty ty ty ty ty ty ty ty ty
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find the
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
least common denominator (LCD). For 2, 3, and 4, the LCD =
y ty ty ty ty ty ty ty ty ty ty ty
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then m
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ultiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee), 8/12
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty t
(ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added together
y ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
and the fraction is reduced to the lowest terms.
ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Analyze ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
ty ty ty ty ty ty ty ty ty
grated Process: Communication and Documentation Objective: 1,
ty ty ty ty ty ty ty
2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
the nurse document as consumed?
ty ty ty ty
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B t y
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of millil
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
iters consumed, multiply 180 7/3 (
ty ty ty ty ty ty
). When a mixed number is present, change it to an improper fraction by multiplying the whole number b
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
y the denominator and then adding that total to
ty ty ty ty ty ty ty ty
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
Format: Multiple Choice Chapte ty ty ty
r: 1 ty
Client Needs: Physiological Integrity: Basic Care and Comfort Cog
ty ty ty ty ty ty ty ty
nitive Level: Analyze ty ty
Difficulty: Difficult ty
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions Inte
ty ty ty ty ty ty ty ty ty
grated Process: Communication and Documentation Objective: 1,
ty ty ty ty ty ty ty
2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were g
ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty ty
ained since admission? ty ty
a. 0.78
b. 0.88
2|Page
www.PlusBay.Plus
