ALEVELPAPERZ2025
Mark Scheme (Results)
Summer 2025
Pearson Edexcel GCE
In Mathematics (9MA0)
Paper 32 Mechanics
, ALEVELPAPERZ2025
Question Scheme Marks AOs
1(a) v = 15 + (2 × 4) M1 3.1b
= 23 ( m s −1 ) A1 1.1b
(2)
1(b) D − 400 = 800 × 2 M1 3.1b
(D =) 2000 A1 1.1b
(2)
(4 marks)
Notes:
1(a) M1 Use of v = u + at or any other complete method to form an equation in v only.
Condone sign errors.
1
e.g. May find s first: s= (15 × 4) + × 2 × 42 = 76 then
2
1
either: 76 = 4v − × 2 × 42
2
(15 + v)
or: = 76 ×4
2
or: v 2= 152 + 2 × 2 × 76
N.B. If they use v = u + at and have 15 = u + (2 × 4), M1A0
M0 if they clearly use an incorrect suvat formula or u = 0
A1 cao. Must be positive.
A0 if they get 23 but go on and do something with it. i.e. not ISW
N.B. 23 with no working can score both marks.
Use of F = ma to form an equation in D or a complete expression for D, with correct
M1
number of terms, condone sign errors and g in the ma term.
1(b)
A1 cao
N.B. 2000 with no working can score both marks.
Mark Scheme (Results)
Summer 2025
Pearson Edexcel GCE
In Mathematics (9MA0)
Paper 32 Mechanics
, ALEVELPAPERZ2025
Question Scheme Marks AOs
1(a) v = 15 + (2 × 4) M1 3.1b
= 23 ( m s −1 ) A1 1.1b
(2)
1(b) D − 400 = 800 × 2 M1 3.1b
(D =) 2000 A1 1.1b
(2)
(4 marks)
Notes:
1(a) M1 Use of v = u + at or any other complete method to form an equation in v only.
Condone sign errors.
1
e.g. May find s first: s= (15 × 4) + × 2 × 42 = 76 then
2
1
either: 76 = 4v − × 2 × 42
2
(15 + v)
or: = 76 ×4
2
or: v 2= 152 + 2 × 2 × 76
N.B. If they use v = u + at and have 15 = u + (2 × 4), M1A0
M0 if they clearly use an incorrect suvat formula or u = 0
A1 cao. Must be positive.
A0 if they get 23 but go on and do something with it. i.e. not ISW
N.B. 23 with no working can score both marks.
Use of F = ma to form an equation in D or a complete expression for D, with correct
M1
number of terms, condone sign errors and g in the ma term.
1(b)
A1 cao
N.B. 2000 with no working can score both marks.
