,Chapter 1: Arithmetic Needed for Dosage
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MULTIPLE CHOICE oo
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to
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drink 15 oz. What portion of the water remained?
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a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A o o
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available
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quantity (25 oz): 10 oz remain. To determine the portion of the water that remains, create a
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fraction by dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided
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by 25 = 10/25. To reduce fractions, find the largest number that can be divided evenly into
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the numerator and the denominator
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(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms
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of 2/5.
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Format: Multiple oo
Choice Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Apply
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Difficulty: Moderate oo
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
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Integrated Process: Teaching/Learning
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Objective: 1, 2 oo oo
2. A patient/client was prescribed 240 W
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suSreMb.yWmSouth as a supplement but consumed
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only 100 mL. What portion of the Ensure remained?
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a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B o o
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total
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available quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that
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remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion).
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Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the largest number that can be
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divided evenly into the numerator and the denominator (20); 140 divided by 20 (140/20) = 7;
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240/20 = 12. The fraction 140/240 can be reduced to its lowest terms of 7/12.
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Format: Multiple oo
Choice Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Apply
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Difficulty: Moderate oo
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
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Integrated Process: Teaching/Learning
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Objective: 1, 2 oo oo
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, 3. A patient/client consumed
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broth. What is the total number of ounces consumed that should be documented for the
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patient/client?
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a. 3 3/4 oo
b. 4 5/12 oo
c. 4 2/3 oo
d. 4 4/9 oo
ANS: B o o
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
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multiplying the whole number by the denominator and then adding that total to the numerator. For
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the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
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= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different
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denominators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
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then multiply that result by the numerator of the fraction. The new fractions to be added are
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27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the
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numerators are added together and the fraction is reduced to the lowest terms.
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Format: Multiple oo
Choice Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Analyze
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Difficulty: Difficult oo
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
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Integrated Process: Communication and Documentation
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Objective: 1, 2
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4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
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the nurse document as
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WWW.TBSM.WS
consumed?
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a. 360
b. 420
c. 510
d. 600
ANS: B o o
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total
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number of milliliters consumed, multiply 180 7/3 (
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change it to an improper fraction by multiplying the whole number by the denominator and
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then adding that total to the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420
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mL (180 ÷ 3 = 60 × 7 = 420).
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Format: Multiple oo
Choice Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Analyze
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Difficulty: Difficult oo
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
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Integrated Process: Communication and Documentation
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Objective: 1, 2
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5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
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were gained since admission?
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a. 0.78
b. 0.88
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