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Solution Manual For Introduction to Polymers Mechanics of Materials 3rd Edition by Robert J. Young Chapter 1-25

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Solution Manual For Introduction to Polymers Mechanics of Materials 3rd Edition by Robert J. Young Chapter 1-25

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Publié le
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Écrit en
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Solution Manual For
Introduction to Polymers Mechanics of Materials 3rd Edition by Robert J. Young
Chapter 1-25

are often a mix of theoretical knowledge and practical application. Depending on the subject area, these exams can vary significantly in format. Common types of business exams include:Multiple Choice Questions
(MCQs): These are frequently used to assess students’ understanding of business terminology, theories, and principles.Case Studies: A staple of business exams, case studies present students with real-world business
scenarios and ask them to apply their knowledge to solve complex problems. Case studies evaluate students' ability to think critically and make strategic decisions.Essay/Short Answer Questions: These types of
questions test the student’s ability to explain and analyze business concepts in a detailed and coherent manner.1.3. Skills Tested in Business ExamsCritical Thinking and Problem-Solving: Business exams often include
case studies that challenge students to apply theoretical knowledge to real-life situations. These tests assess decision-making skills, as well as the ability to evaluate various business alternatives.Quantitative Analysis:
For subjects like finance or economics, business exams often require students to perform calculations and interpret data. The ability to analyze financial statements, project revenues, and manage budgets is
essential.Communication




Part I
Problems
Concepts, Nomenclature
and
Synthesis of Polymers

, Chapter 1
Concepts and Nomenclature


1.1
Polystyrene has the repeat unit structure




Hence
M0 = (8 x 12 g mol-1) + (8 x 1 g mol-1) = 104 g mol-1
Neglecting contributions from end-groups (which is reasonable because M n is high), then xn
can be calculated using a rearranged form of Equation (1.1)
xn = M n / M0
89 440 g mol1
xn   860
1
104 g mol

Molar-mass dispersity ĐM is defined by ĐM = M w / M n and so if ĐM = 1.5, then
M = 1.5 x 89 440 g mol-1 = 134 160 g mol-1
are often a mix of theoretical knowledge and practical application. Depending on the subject area, these exams can vary significantly in format. Common types of business exams include:Multiple Choice Questions
(MCQs): These are frequently used to assess students’ understanding of business terminology, theories, and principles.Case Studies: A staple of business exams, case studies present students with real-world business
scenarios and ask them to apply their knowledge to solve complex problems. Case studies evaluate students' ability to think critically and make strategic decisions.Essay/Short Answer Questions: These types of
questions test the student’s abilitywto explain and analyze business concepts in a detailed and coherent manner.1.3. Skills Tested in Business ExamsCritical Thinking and Problem-Solving: Business exams often include
case studies that challenge students to apply theoretical knowledge to real-life situations. These tests assess decision-making skills, as well as the ability to evaluate various business alternatives.Quantitative Analysis:
For subjects like finance or economics, business exams often require students to perform calculations and interpret data. The ability to analyze financial statements, project revenues, and manage budgets is
essential.Communication

1.2
The mean repeat unit molar mass of the copolymer M cop
0 is given by Equation (1.2), which
requires knowledge of the mole fraction Xj and the molar mass M 0j of each type j of repeat
unit. Since there are only two types of repeat unit, it is necessary to calculate Xj for only one
of the two repeat units (because XE + XVAc = 1). The two repeat units are of structure:




and so
M 0E = (2 x 12 g mol-1) + (4 x 1 g mol-1) = 28 g mol-1

,M VAc = (4 x 12 g mol-1) + (6 x 1 g mol-1) + (2 x 16 g mol-1) = 86 g mol-1
0

, Thus
(100 12.9 g (100 g cop) g mol1
XE 
{(100 12.9 g (100 g cop)1) / 28 g mol1}{12.9 g (100 g cop) g mol1}
XE = 0.954
Hence
XVAc = 1 – 0.954 = 0.046
M 0cop can now be calculated from Equation (1.2)

M 0cop = (0.954 x 28 g mol-1) + (0.046 x 86 g mol-1)

M 0cop = 30.67 g mol-1
Finally, using a rearranged form of Equation (1.1)
39 870 g mol1
x cop  
n 1
1300
30.67 g mol
are often a mix of theoretical knowledge and practical application. Depending on the subject area, these exams can vary significantly in format. Common types of business exams include:Multiple Choice Questions
(MCQs): These are frequently used to assess students’ understanding of business terminology, theories, and principles.Case Studies: A staple of business exams, case studies present students with real-world business
scenarios and ask them to apply their knowledge to solve complex problems. Case studies evaluate students' ability to think critically and make strategic decisions.Essay/Short Answer Questions: These types of
questions test the student’s ability to explain and analyze business concepts in a detailed and coherent manner.1.3. Skills Tested in Business ExamsCritical Thinking and Problem-Solving: Business exams often include
case studies that challenge students to apply theoretical knowledge to real-life situations. These tests assess decision-making skills, as well as the ability to evaluate various business alternatives.Quantitative Analysis:
For subjects like finance or economics, business exams often require students to perform calculations and interpret data. The ability to analyze financial statements, project revenues, and manage budgets is
essential.Communication

1.3
(a) M n and M w can be calculated using, respectively, Equations (1.4) and (1.9) with
N1 = N2 = N3 = N:

( N  10 000 g mol1)  ( N  30 000 g mol1)  ( N  100 000 g mol1)
Mn 
NNN
M n = 46 667 g mol-1
{N  (10 000 g mol1)2}{N  (30 000 g mol1)2}{N  (100 000 g mol1)2}
Mw  ( N  10 000 g mol1)  ( N  30 000 g mol1)  ( N  100 000 g mol1)
M w = 78 571 g mol-1
M w / M n = 1.68
(b) M n and M w can be calculated using, respectively, Equations (1.7) and (1.8) with w1 =
w2 = w3 = 13 :

1
M 
n
( 000 g mol1)  ( 000 g mol1)  ( 000 g mol1)
3 3 3
M n = 20 930 g mol-1

M  ( 1  10 000 g mol1)  ( 1  30 000 g mol1)  ( 1  100 000 g mol1)
w 3 3 3
M w = 46 667 g mol-1
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