Mip1502 Assignment 4 due 16 Aug 2024

MIP1502

ASSIGNMENT 4

UNIQUE CODE:
397869

DUE DATE: 16 AUGUST 2024




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, QUESTION 1

2.1.
1.1.1. Complete the table below for tile numbers 5 and 6.

Tile no. (𝑛) 5 6 27
Tile length (𝑙) 7 8 29
Number of red squares 12 14 56
Number of black squares 37 50 785
Total number of squares 49 64 841



1.1.2. To determine the length of Tile number 7, we can use the established pattern
that the length of the of the tile increases by 1 unit for each subsequent tile
number.
Given that tile number 1 has length of 3. The formula to find the length of any
tile number 𝑛 can be expressed as 𝑙 = 3 + (𝑛 − 1). So, tile number 7 length will
be : = 3 + (7 − 1)
:=3+6=9
Another thought, the length of tile increases by 1 for each subsequent tile
number, so as tile number 1 has length and tile number 2 has a length of 4 =
(3+1). And tile number 3 has length of 5 = (4+1). Which means Tile number 7
has length of 9 = (8+1 = 9).
So, the length of tile number 7 is 9


1.1.3. Formulas
1.1.3.1. 𝑅 = 2𝑙 − 2
1.1.3.2. 𝐵 = 𝑙 2 − 2𝑙 + 2
1.1.4. Column 27

Tile no. (𝑛) 27

Tile length (𝑙) 29
Number of red squares 56

Number of black squares 785


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